legendre integration with derivative terms
$begingroup$
I want to prove that integration from -1 to 1 (1-x^2)p'n(x)p'n(x)dx = 2n(n+1)/(2n+1)
I substituted some recurrence relations but got stuck at evaluating the integral of x^2p'p .. how can i deal with the derivative in this case?
legendre-polynomials
asked Jan 19 at 19:32
user635977user635977
63
$endgroup$
add a comment |
$begingroup$
I want to prove that integration from -1 to 1 (1-x^2)p'n(x)p'n(x)dx = 2n(n+1)/(2n+1)
I substituted some recurrence relations but got stuck at evaluating the integral of x^2p'p .. how can i deal with the derivative in this case?
legendre-polynomials
asked Jan 19 at 19:32
user635977user635977
63
$endgroup$
add a comment |
$begingroup$
I want to prove that integration from -1 to 1 (1-x^2)p'n(x)p'n(x)dx = 2n(n+1)/(2n+1)
I substituted some recurrence relations but got stuck at evaluating the integral of x^2p'p .. how can i deal with the derivative in this case?
legendre-polynomials
asked Jan 19 at 19:32
user635977user635977
63
$endgroup$
I want to prove that integration from -1 to 1 (1-x^2)p'n(x)p'n(x)dx = 2n(n+1)/(2n+1)
I substituted some recurrence relations but got stuck at evaluating the integral of x^2p'p .. how can i deal with the derivative in this case?
legendre-polynomials
legendre-polynomials
asked Jan 19 at 19:32
user635977user635977
63
asked Jan 19 at 19:32
user635977user635977
63
asked Jan 19 at 19:32
user635977user635977
63
asked Jan 19 at 19:32
user635977user635977
63
asked Jan 19 at 19:32
user635977user635977
63
63
add a comment |
add a comment |
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