Can anyone explain the following slash notation?
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This notation can be seen made use of in equation 1.5 of https://arxiv.org/pdf/1311.5200.pdf
Roughly speaking, $$left. I = int f(z) prod_a frac{dz^a}{z-z_a} middle/ domega right.$$ where $$domega = frac{dz^1 dz^2 dz^3}{(z-z_1)(z-z_2)(z-z_3)} $$I do not understand what this slash notation means. Any examples will be greatly appreciated.
notation
asked Jan 19 at 18:52
user44690user44690
282
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add a comment |
$begingroup$
This notation can be seen made use of in equation 1.5 of https://arxiv.org/pdf/1311.5200.pdf
Roughly speaking, $$left. I = int f(z) prod_a frac{dz^a}{z-z_a} middle/ domega right.$$ where $$domega = frac{dz^1 dz^2 dz^3}{(z-z_1)(z-z_2)(z-z_3)} $$I do not understand what this slash notation means. Any examples will be greatly appreciated.
notation
asked Jan 19 at 18:52
user44690user44690
282
$endgroup$
$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
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– Rhys Hughes
Jan 19 at 19:12
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Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14
add a comment |
$begingroup$
This notation can be seen made use of in equation 1.5 of https://arxiv.org/pdf/1311.5200.pdf
Roughly speaking, $$left. I = int f(z) prod_a frac{dz^a}{z-z_a} middle/ domega right.$$ where $$domega = frac{dz^1 dz^2 dz^3}{(z-z_1)(z-z_2)(z-z_3)} $$I do not understand what this slash notation means. Any examples will be greatly appreciated.
notation
asked Jan 19 at 18:52
user44690user44690
282
$endgroup$
This notation can be seen made use of in equation 1.5 of https://arxiv.org/pdf/1311.5200.pdf
Roughly speaking, $$left. I = int f(z) prod_a frac{dz^a}{z-z_a} middle/ domega right.$$ where $$domega = frac{dz^1 dz^2 dz^3}{(z-z_1)(z-z_2)(z-z_3)} $$I do not understand what this slash notation means. Any examples will be greatly appreciated.
notation
notation
asked Jan 19 at 18:52
user44690user44690
282
asked Jan 19 at 18:52
user44690user44690
282
edited Jan 19 at 19:00
user44690
asked Jan 19 at 18:52
user44690user44690
282
asked Jan 19 at 18:52
user44690user44690
282
asked Jan 19 at 18:52
user44690user44690
282
282
$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
$endgroup$
– Rhys Hughes
Jan 19 at 19:12
$begingroup$
Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14
add a comment |
$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
$endgroup$
– Rhys Hughes
Jan 19 at 19:12
$begingroup$
Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14
$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
$endgroup$
– Rhys Hughes
Jan 19 at 19:12
$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
$endgroup$
– Rhys Hughes
Jan 19 at 19:12
$begingroup$
Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14
$begingroup$
Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14
add a comment |
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$begingroup$
I'd wager that the slash is used to indicate the end of the argument for the product, indicating that $domega$ is for the integral, not the product.
$endgroup$
– Rhys Hughes
Jan 19 at 19:12
$begingroup$
Isn't it just division? Possibly in the form of a quotient space? Apparently we can divide out 3 dimensions, which is what that division seems to do.
$endgroup$
– I like Serena
Jan 19 at 19:14