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Information for "Prerelease:EarthBound"

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Please consider supporting The Cutting Room Floor on Patreon. Thanks for all your support! Information for "Prerelease:EarthBound" Jump to: navigation, search .mw-hiddenCategoriesExplanation { display: none; } .mw-templatesUsedExplanation { display: none; } Basic information Display title Prerelease:EarthBound Default sort key EarthBound Page length (in bytes) 1,798 Page ID 73836 Page content language English (en) Page content model wikitext Indexing by robots Allowed Number of redirects to this page 1 Counted as a content page Yes Number of subpages of this page 4 (1 redirect; 3 non-redirects) Page protection Edit Allow all users Move Allow all users Edit history Page creator West (Talk | contribs) Date of page creation 10:21, 4 April 2014 Latest editor OKeijiDragon (Talk | contribs) Date of latest

If an operator $T$ satisfy a property, then $|Tx|=c|x|$

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3 1 $begingroup$ Let $(E,langlecdot;,;cdotrangle)$ be a complex Hilbert space and $mathcal{L}(E)$ be the algebra of all operators on $E$ . Assume that $Tin mathcal{L}(E)$ and satisfy the following property (P): $$langle x,yrangle=0Longrightarrow langle Tx,Tyrangle=0,$$ for all $x,yin E$ . I want to prove under the property $(P)$ that there exists $cgeq0$ such that $$|Tx|=c|x|,$$ for all $xin E$ . Note that, if there exist $x, yin Esetminus{0}$ such that $|Tx|=alpha|x|$ and $|Ty|=beta|y|$ for some $0leqalpha <beta$ , it can be seen that $langle x,yrangleneq0$ . functional-analysis operator-theory hilbert-spaces share | cite | improve this question