What are some applications of subdirect product?

Multi tool use
$begingroup$
I have studied direct products. I know a few applications of direct products, like group isomorphism, etc. What are some applications of sub-direct product of groups?
group-theory applications direct-product
$endgroup$
add a comment |
$begingroup$
I have studied direct products. I know a few applications of direct products, like group isomorphism, etc. What are some applications of sub-direct product of groups?
group-theory applications direct-product
$endgroup$
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46
add a comment |
$begingroup$
I have studied direct products. I know a few applications of direct products, like group isomorphism, etc. What are some applications of sub-direct product of groups?
group-theory applications direct-product
$endgroup$
I have studied direct products. I know a few applications of direct products, like group isomorphism, etc. What are some applications of sub-direct product of groups?
group-theory applications direct-product
group-theory applications direct-product
edited Jan 22 at 17:46
Shaun
9,300113684
9,300113684
asked Jan 22 at 8:49
I_wil_break_wallI_wil_break_wall
805
805
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46
add a comment |
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Subdirect products arise naturally as intransitive subgroups of $S_n$, where they are subdirect products of the induced actions of the group on its orbits. Similarly for completely reducible linear groups.
$endgroup$
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
add a comment |
$begingroup$
A powerful tool in group theory is something called the fibre product. This is a special type of subdirect product of the group with itself.
Associated to a short exact sequence $1rightarrow Nrightarrow Hrightarrow Qrightarrow 1$, where $pi(H)=Q$ is the natural map, is the fibre product $Psubset Htimes H$,
$$
P:={(h_1, h_2)mid pi(h_1)=pi(h_2)}.
$$
Clearly the diagonal component $Delta:={(h, h)mid hin H}$ is contained in $P$, so $P$ is a subdirect product.
The first application of fibre products which is know of is that there exist finitely generated subgroups of $F_2times F_2$ which have insoluble membership problem: Firstly, let $Q$ be finitely presented and have insoluble word problem, then $P$ has insoluble membership problem. To see that $P$ is finitely generated, since $Q$ is finitely presented we have that $N subset H$ is finitely generated as a normal subgroup, and then to obtain a finite generating set for $P$ one chooses a finite normal generating set for $Ntimes{1}$ and then appends a generating set for the diagonal $Deltacong H=F_2$.
A surprisingly powerful result, called the $1$-$2$-$3$ theorem, gives conditions on the fibre products to be finitely presentable, see: G. Baumslag, M.R. Bridson, C.F. Miller III, H. Short, Fibre products, non-positive curvature, and decision problems, Comm. Math. Helv. 75 (2000), 457–477.
A super-powerful application of fibre products is the following (the application is the main result of a paper in the Annals of Mathematics, one of the top journals - undisputed top 4 journal, disputed no. 1). If $Gamma$ is a group then $widehat{Gamma}$ denotes its profinite completion.
Question (Grothendieck, 1970). Let $Gamma_1$ and $Gamma_2$ be finitely presented, residually finite groups and let $u :Gamma_1rightarrow Gamma_2$ be a homomorphism such that $widehat{u} :widehat{Gamma}_1rightarrow widehat{Gamma}_2$ is an isomorphism of profinite groups. Does it follow that $u$ is an isomorphism from $Gamma_1$ onto $Gamma_2$?
Theorem (Bridson, Grunewald, 2004, Ann. Math., link). There exists a short exact sequence $1rightarrow NrightarrowGammarightarrow Qrightarrow 1$ where $Gamma$ has a whole host of nice properties, and where $P$ and $Gamma$ are a counter-example to Grothendieck's question: $P$ and $Gamma$ are finitely presentable, with $widehat{P}cong widehat{Gamma}$ but $Pnotcong Gamma$.
$endgroup$
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
add a comment |
$begingroup$
Typically, when you know that an object is a subdirect product of other objects, you know that it inherits all properties that are passed from products of those objects to their subsets. For example, a subdirect product of abelian groups must be abelian (and the same for any other group identity).
$endgroup$
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Subdirect products arise naturally as intransitive subgroups of $S_n$, where they are subdirect products of the induced actions of the group on its orbits. Similarly for completely reducible linear groups.
$endgroup$
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
add a comment |
$begingroup$
Subdirect products arise naturally as intransitive subgroups of $S_n$, where they are subdirect products of the induced actions of the group on its orbits. Similarly for completely reducible linear groups.
$endgroup$
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
add a comment |
$begingroup$
Subdirect products arise naturally as intransitive subgroups of $S_n$, where they are subdirect products of the induced actions of the group on its orbits. Similarly for completely reducible linear groups.
$endgroup$
Subdirect products arise naturally as intransitive subgroups of $S_n$, where they are subdirect products of the induced actions of the group on its orbits. Similarly for completely reducible linear groups.
answered Jan 22 at 10:04
Derek HoltDerek Holt
53.8k53571
53.8k53571
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
add a comment |
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
I was interested in the application in computer science.
$endgroup$
– I_wil_break_wall
Jan 23 at 5:41
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
$begingroup$
Also, centralizers in the alternating group (e.g., of a 3-cycle) are usually naturally subdirect (fibre) products.
$endgroup$
– YCor
Jan 24 at 3:47
add a comment |
$begingroup$
A powerful tool in group theory is something called the fibre product. This is a special type of subdirect product of the group with itself.
Associated to a short exact sequence $1rightarrow Nrightarrow Hrightarrow Qrightarrow 1$, where $pi(H)=Q$ is the natural map, is the fibre product $Psubset Htimes H$,
$$
P:={(h_1, h_2)mid pi(h_1)=pi(h_2)}.
$$
Clearly the diagonal component $Delta:={(h, h)mid hin H}$ is contained in $P$, so $P$ is a subdirect product.
The first application of fibre products which is know of is that there exist finitely generated subgroups of $F_2times F_2$ which have insoluble membership problem: Firstly, let $Q$ be finitely presented and have insoluble word problem, then $P$ has insoluble membership problem. To see that $P$ is finitely generated, since $Q$ is finitely presented we have that $N subset H$ is finitely generated as a normal subgroup, and then to obtain a finite generating set for $P$ one chooses a finite normal generating set for $Ntimes{1}$ and then appends a generating set for the diagonal $Deltacong H=F_2$.
A surprisingly powerful result, called the $1$-$2$-$3$ theorem, gives conditions on the fibre products to be finitely presentable, see: G. Baumslag, M.R. Bridson, C.F. Miller III, H. Short, Fibre products, non-positive curvature, and decision problems, Comm. Math. Helv. 75 (2000), 457–477.
A super-powerful application of fibre products is the following (the application is the main result of a paper in the Annals of Mathematics, one of the top journals - undisputed top 4 journal, disputed no. 1). If $Gamma$ is a group then $widehat{Gamma}$ denotes its profinite completion.
Question (Grothendieck, 1970). Let $Gamma_1$ and $Gamma_2$ be finitely presented, residually finite groups and let $u :Gamma_1rightarrow Gamma_2$ be a homomorphism such that $widehat{u} :widehat{Gamma}_1rightarrow widehat{Gamma}_2$ is an isomorphism of profinite groups. Does it follow that $u$ is an isomorphism from $Gamma_1$ onto $Gamma_2$?
Theorem (Bridson, Grunewald, 2004, Ann. Math., link). There exists a short exact sequence $1rightarrow NrightarrowGammarightarrow Qrightarrow 1$ where $Gamma$ has a whole host of nice properties, and where $P$ and $Gamma$ are a counter-example to Grothendieck's question: $P$ and $Gamma$ are finitely presentable, with $widehat{P}cong widehat{Gamma}$ but $Pnotcong Gamma$.
$endgroup$
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
add a comment |
$begingroup$
A powerful tool in group theory is something called the fibre product. This is a special type of subdirect product of the group with itself.
Associated to a short exact sequence $1rightarrow Nrightarrow Hrightarrow Qrightarrow 1$, where $pi(H)=Q$ is the natural map, is the fibre product $Psubset Htimes H$,
$$
P:={(h_1, h_2)mid pi(h_1)=pi(h_2)}.
$$
Clearly the diagonal component $Delta:={(h, h)mid hin H}$ is contained in $P$, so $P$ is a subdirect product.
The first application of fibre products which is know of is that there exist finitely generated subgroups of $F_2times F_2$ which have insoluble membership problem: Firstly, let $Q$ be finitely presented and have insoluble word problem, then $P$ has insoluble membership problem. To see that $P$ is finitely generated, since $Q$ is finitely presented we have that $N subset H$ is finitely generated as a normal subgroup, and then to obtain a finite generating set for $P$ one chooses a finite normal generating set for $Ntimes{1}$ and then appends a generating set for the diagonal $Deltacong H=F_2$.
A surprisingly powerful result, called the $1$-$2$-$3$ theorem, gives conditions on the fibre products to be finitely presentable, see: G. Baumslag, M.R. Bridson, C.F. Miller III, H. Short, Fibre products, non-positive curvature, and decision problems, Comm. Math. Helv. 75 (2000), 457–477.
A super-powerful application of fibre products is the following (the application is the main result of a paper in the Annals of Mathematics, one of the top journals - undisputed top 4 journal, disputed no. 1). If $Gamma$ is a group then $widehat{Gamma}$ denotes its profinite completion.
Question (Grothendieck, 1970). Let $Gamma_1$ and $Gamma_2$ be finitely presented, residually finite groups and let $u :Gamma_1rightarrow Gamma_2$ be a homomorphism such that $widehat{u} :widehat{Gamma}_1rightarrow widehat{Gamma}_2$ is an isomorphism of profinite groups. Does it follow that $u$ is an isomorphism from $Gamma_1$ onto $Gamma_2$?
Theorem (Bridson, Grunewald, 2004, Ann. Math., link). There exists a short exact sequence $1rightarrow NrightarrowGammarightarrow Qrightarrow 1$ where $Gamma$ has a whole host of nice properties, and where $P$ and $Gamma$ are a counter-example to Grothendieck's question: $P$ and $Gamma$ are finitely presentable, with $widehat{P}cong widehat{Gamma}$ but $Pnotcong Gamma$.
$endgroup$
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
add a comment |
$begingroup$
A powerful tool in group theory is something called the fibre product. This is a special type of subdirect product of the group with itself.
Associated to a short exact sequence $1rightarrow Nrightarrow Hrightarrow Qrightarrow 1$, where $pi(H)=Q$ is the natural map, is the fibre product $Psubset Htimes H$,
$$
P:={(h_1, h_2)mid pi(h_1)=pi(h_2)}.
$$
Clearly the diagonal component $Delta:={(h, h)mid hin H}$ is contained in $P$, so $P$ is a subdirect product.
The first application of fibre products which is know of is that there exist finitely generated subgroups of $F_2times F_2$ which have insoluble membership problem: Firstly, let $Q$ be finitely presented and have insoluble word problem, then $P$ has insoluble membership problem. To see that $P$ is finitely generated, since $Q$ is finitely presented we have that $N subset H$ is finitely generated as a normal subgroup, and then to obtain a finite generating set for $P$ one chooses a finite normal generating set for $Ntimes{1}$ and then appends a generating set for the diagonal $Deltacong H=F_2$.
A surprisingly powerful result, called the $1$-$2$-$3$ theorem, gives conditions on the fibre products to be finitely presentable, see: G. Baumslag, M.R. Bridson, C.F. Miller III, H. Short, Fibre products, non-positive curvature, and decision problems, Comm. Math. Helv. 75 (2000), 457–477.
A super-powerful application of fibre products is the following (the application is the main result of a paper in the Annals of Mathematics, one of the top journals - undisputed top 4 journal, disputed no. 1). If $Gamma$ is a group then $widehat{Gamma}$ denotes its profinite completion.
Question (Grothendieck, 1970). Let $Gamma_1$ and $Gamma_2$ be finitely presented, residually finite groups and let $u :Gamma_1rightarrow Gamma_2$ be a homomorphism such that $widehat{u} :widehat{Gamma}_1rightarrow widehat{Gamma}_2$ is an isomorphism of profinite groups. Does it follow that $u$ is an isomorphism from $Gamma_1$ onto $Gamma_2$?
Theorem (Bridson, Grunewald, 2004, Ann. Math., link). There exists a short exact sequence $1rightarrow NrightarrowGammarightarrow Qrightarrow 1$ where $Gamma$ has a whole host of nice properties, and where $P$ and $Gamma$ are a counter-example to Grothendieck's question: $P$ and $Gamma$ are finitely presentable, with $widehat{P}cong widehat{Gamma}$ but $Pnotcong Gamma$.
$endgroup$
A powerful tool in group theory is something called the fibre product. This is a special type of subdirect product of the group with itself.
Associated to a short exact sequence $1rightarrow Nrightarrow Hrightarrow Qrightarrow 1$, where $pi(H)=Q$ is the natural map, is the fibre product $Psubset Htimes H$,
$$
P:={(h_1, h_2)mid pi(h_1)=pi(h_2)}.
$$
Clearly the diagonal component $Delta:={(h, h)mid hin H}$ is contained in $P$, so $P$ is a subdirect product.
The first application of fibre products which is know of is that there exist finitely generated subgroups of $F_2times F_2$ which have insoluble membership problem: Firstly, let $Q$ be finitely presented and have insoluble word problem, then $P$ has insoluble membership problem. To see that $P$ is finitely generated, since $Q$ is finitely presented we have that $N subset H$ is finitely generated as a normal subgroup, and then to obtain a finite generating set for $P$ one chooses a finite normal generating set for $Ntimes{1}$ and then appends a generating set for the diagonal $Deltacong H=F_2$.
A surprisingly powerful result, called the $1$-$2$-$3$ theorem, gives conditions on the fibre products to be finitely presentable, see: G. Baumslag, M.R. Bridson, C.F. Miller III, H. Short, Fibre products, non-positive curvature, and decision problems, Comm. Math. Helv. 75 (2000), 457–477.
A super-powerful application of fibre products is the following (the application is the main result of a paper in the Annals of Mathematics, one of the top journals - undisputed top 4 journal, disputed no. 1). If $Gamma$ is a group then $widehat{Gamma}$ denotes its profinite completion.
Question (Grothendieck, 1970). Let $Gamma_1$ and $Gamma_2$ be finitely presented, residually finite groups and let $u :Gamma_1rightarrow Gamma_2$ be a homomorphism such that $widehat{u} :widehat{Gamma}_1rightarrow widehat{Gamma}_2$ is an isomorphism of profinite groups. Does it follow that $u$ is an isomorphism from $Gamma_1$ onto $Gamma_2$?
Theorem (Bridson, Grunewald, 2004, Ann. Math., link). There exists a short exact sequence $1rightarrow NrightarrowGammarightarrow Qrightarrow 1$ where $Gamma$ has a whole host of nice properties, and where $P$ and $Gamma$ are a counter-example to Grothendieck's question: $P$ and $Gamma$ are finitely presentable, with $widehat{P}cong widehat{Gamma}$ but $Pnotcong Gamma$.
edited Jan 24 at 9:41
answered Jan 22 at 16:30


user1729user1729
17.2k64193
17.2k64193
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
add a comment |
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
@Shaun regarding your numerals edit, you might be interested in this tex.SE question.
$endgroup$
– user1729
Jan 22 at 19:10
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
Thank you, @user1729; that'll save me some time in future! It's nice to know a useful convention :)
$endgroup$
– Shaun
Jan 22 at 19:45
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
"A powerful tool in group theory, developed over the last 20 or so years but has a longer history". This sounds weird. I'd certainly not say that the tool of fibre products was developed in this period. Also if I prove a result about direct products I'm not developing the tool of direct product.
$endgroup$
– YCor
Jan 24 at 3:43
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
$begingroup$
@YCor I'll remove the statement with the dates. However, I can only think of three results pre-Baumslag, Bridson, Miller, Short which use fibre products (but I think they invented the name?). So do you think it would be correct to say that they "came to the fore" in the past 20 years?
$endgroup$
– user1729
Jan 24 at 9:41
add a comment |
$begingroup$
Typically, when you know that an object is a subdirect product of other objects, you know that it inherits all properties that are passed from products of those objects to their subsets. For example, a subdirect product of abelian groups must be abelian (and the same for any other group identity).
$endgroup$
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
add a comment |
$begingroup$
Typically, when you know that an object is a subdirect product of other objects, you know that it inherits all properties that are passed from products of those objects to their subsets. For example, a subdirect product of abelian groups must be abelian (and the same for any other group identity).
$endgroup$
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
add a comment |
$begingroup$
Typically, when you know that an object is a subdirect product of other objects, you know that it inherits all properties that are passed from products of those objects to their subsets. For example, a subdirect product of abelian groups must be abelian (and the same for any other group identity).
$endgroup$
Typically, when you know that an object is a subdirect product of other objects, you know that it inherits all properties that are passed from products of those objects to their subsets. For example, a subdirect product of abelian groups must be abelian (and the same for any other group identity).
edited Jan 22 at 16:38


user1729
17.2k64193
17.2k64193
answered Jan 22 at 9:26


Jose BroxJose Brox
3,15711128
3,15711128
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
add a comment |
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
1
1
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
$begingroup$
This seems to just be a property of a "subgroup of the direct product", which is a weaker property than being a subdirect product.
$endgroup$
– Ted
Jan 22 at 17:07
add a comment |
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5ufT,3d6w5X2X5mj
$begingroup$
Exercise: a group is isomorphic to a (nontrivial) subdirect product of two groups iff it has two nontrivial normal subgroups with trivial intersection. (By nontrivial subdirect, I mean none of the two projections is injective on the subgroup.)
$endgroup$
– YCor
Jan 24 at 3:46