Probability of seeing a heterozygote using Hardy-Weinberg
Multi tool use
$begingroup$
This question is an extension of this question.
The hardy-weinberg equation is defined as, given two alleles, $A$ and $a$, and $frequency(A) = p$ and $frequency(a) = q$. Now, we have $p+q = 1 = p^2 + 2pq + q^2$.
Now, based on the linked question, I know what the probability of a heterozygote is for when there are only two alleles. But that answer uses a guess and check approach. How do I generalize this for $n$ alleles situation using an equation?
For current intuition is the following, if there are $n$ alleles, then I would use the multi-normial theorem to expand the allele probabilities then use that information to figure out the maximum possible probability. But now sure how to proceed.
probability
asked Jan 22 at 8:22
JonathanJonathan
388317
$endgroup$
add a comment |
$begingroup$
This question is an extension of this question.
The hardy-weinberg equation is defined as, given two alleles, $A$ and $a$, and $frequency(A) = p$ and $frequency(a) = q$. Now, we have $p+q = 1 = p^2 + 2pq + q^2$.
Now, based on the linked question, I know what the probability of a heterozygote is for when there are only two alleles. But that answer uses a guess and check approach. How do I generalize this for $n$ alleles situation using an equation?
For current intuition is the following, if there are $n$ alleles, then I would use the multi-normial theorem to expand the allele probabilities then use that information to figure out the maximum possible probability. But now sure how to proceed.
probability
asked Jan 22 at 8:22
JonathanJonathan
388317
$endgroup$
add a comment |
$begingroup$
This question is an extension of this question.
The hardy-weinberg equation is defined as, given two alleles, $A$ and $a$, and $frequency(A) = p$ and $frequency(a) = q$. Now, we have $p+q = 1 = p^2 + 2pq + q^2$.
Now, based on the linked question, I know what the probability of a heterozygote is for when there are only two alleles. But that answer uses a guess and check approach. How do I generalize this for $n$ alleles situation using an equation?
For current intuition is the following, if there are $n$ alleles, then I would use the multi-normial theorem to expand the allele probabilities then use that information to figure out the maximum possible probability. But now sure how to proceed.
probability
asked Jan 22 at 8:22
JonathanJonathan
388317
$endgroup$
This question is an extension of this question.
The hardy-weinberg equation is defined as, given two alleles, $A$ and $a$, and $frequency(A) = p$ and $frequency(a) = q$. Now, we have $p+q = 1 = p^2 + 2pq + q^2$.
Now, based on the linked question, I know what the probability of a heterozygote is for when there are only two alleles. But that answer uses a guess and check approach. How do I generalize this for $n$ alleles situation using an equation?
For current intuition is the following, if there are $n$ alleles, then I would use the multi-normial theorem to expand the allele probabilities then use that information to figure out the maximum possible probability. But now sure how to proceed.
probability
probability
asked Jan 22 at 8:22
JonathanJonathan
388317
asked Jan 22 at 8:22
JonathanJonathan
388317
asked Jan 22 at 8:22
JonathanJonathan
388317
asked Jan 22 at 8:22
JonathanJonathan
388317
asked Jan 22 at 8:22
JonathanJonathan
388317
388317
add a comment |
add a comment |
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