What is the efficiency of the machine (probability theory)
Multi tool use
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A machine is made of 5 parts. Its efficiency deppends on the efficiency of each of the 5 parts. What is the efficiency of the machine, if the probabiliy that each of the parts is broken equals $P=10%$?
The machine is represented like this:
$$-T1-T2-T3-T4-T5-$$
probability probability-theory probability-distributions
asked Jan 22 at 9:01
zermelovaczermelovac
504212
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0
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A machine is made of 5 parts. Its efficiency deppends on the efficiency of each of the 5 parts. What is the efficiency of the machine, if the probabiliy that each of the parts is broken equals $P=10%$?
The machine is represented like this:
$$-T1-T2-T3-T4-T5-$$
probability probability-theory probability-distributions
asked Jan 22 at 9:01
zermelovaczermelovac
504212
$endgroup$
$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
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– Matti P.
Jan 22 at 9:36
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The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
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– cgiovanardi
Jan 22 at 13:41
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$begingroup$
A machine is made of 5 parts. Its efficiency deppends on the efficiency of each of the 5 parts. What is the efficiency of the machine, if the probabiliy that each of the parts is broken equals $P=10%$?
The machine is represented like this:
$$-T1-T2-T3-T4-T5-$$
probability probability-theory probability-distributions
asked Jan 22 at 9:01
zermelovaczermelovac
504212
$endgroup$
A machine is made of 5 parts. Its efficiency deppends on the efficiency of each of the 5 parts. What is the efficiency of the machine, if the probabiliy that each of the parts is broken equals $P=10%$?
The machine is represented like this:
$$-T1-T2-T3-T4-T5-$$
probability probability-theory probability-distributions
probability probability-theory probability-distributions
asked Jan 22 at 9:01
zermelovaczermelovac
504212
asked Jan 22 at 9:01
zermelovaczermelovac
504212
asked Jan 22 at 9:01
zermelovaczermelovac
504212
asked Jan 22 at 9:01
zermelovaczermelovac
504212
asked Jan 22 at 9:01
zermelovaczermelovac
504212
504212
$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
$endgroup$
– Matti P.
Jan 22 at 9:36
$begingroup$
The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
$endgroup$
– cgiovanardi
Jan 22 at 13:41
add a comment |
$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
$endgroup$
– Matti P.
Jan 22 at 9:36
$begingroup$
The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
$endgroup$
– cgiovanardi
Jan 22 at 13:41
$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
$endgroup$
– Matti P.
Jan 22 at 9:36
$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
$endgroup$
– Matti P.
Jan 22 at 9:36
$begingroup$
The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
$endgroup$
– cgiovanardi
Jan 22 at 13:41
$begingroup$
The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
$endgroup$
– cgiovanardi
Jan 22 at 13:41
add a comment |
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$begingroup$
How do we model the efficiency of the whole system? Is it completely down if at least one parts is broken? Or is it only 80 percent efficient if one is broken?
$endgroup$
– Matti P.
Jan 22 at 9:36
$begingroup$
The parts are connected in series, so the machine to run has to have all five parts in good conditions. P(broken part i)=1-P(not broken part i).
$endgroup$
– cgiovanardi
Jan 22 at 13:41