What does a $4$-dimensional bell curve look like graphically?












4












$begingroup$


I have some $4$D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function. I am using MATLAB and a slider to emulate the fourth dimension. Does anyone know how a bell curve would look like in $4$D?



Thank you.










share|cite|improve this question











$endgroup$












  • $begingroup$
    The best you could do is try to animate surface plots and see the evolution.
    $endgroup$
    – Sean Roberson
    Aug 7 '17 at 17:38










  • $begingroup$
    @Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:59
















4












$begingroup$


I have some $4$D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function. I am using MATLAB and a slider to emulate the fourth dimension. Does anyone know how a bell curve would look like in $4$D?



Thank you.










share|cite|improve this question











$endgroup$












  • $begingroup$
    The best you could do is try to animate surface plots and see the evolution.
    $endgroup$
    – Sean Roberson
    Aug 7 '17 at 17:38










  • $begingroup$
    @Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:59














4












4








4


1



$begingroup$


I have some $4$D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function. I am using MATLAB and a slider to emulate the fourth dimension. Does anyone know how a bell curve would look like in $4$D?



Thank you.










share|cite|improve this question











$endgroup$




I have some $4$D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function. I am using MATLAB and a slider to emulate the fourth dimension. Does anyone know how a bell curve would look like in $4$D?



Thank you.







algebra-precalculus statistics descriptive-statistics






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 10 at 22:39







Irregardless

















asked Aug 7 '17 at 17:35









IrregardlessIrregardless

435417




435417












  • $begingroup$
    The best you could do is try to animate surface plots and see the evolution.
    $endgroup$
    – Sean Roberson
    Aug 7 '17 at 17:38










  • $begingroup$
    @Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:59


















  • $begingroup$
    The best you could do is try to animate surface plots and see the evolution.
    $endgroup$
    – Sean Roberson
    Aug 7 '17 at 17:38










  • $begingroup$
    @Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:26










  • $begingroup$
    @Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
    $endgroup$
    – iadvd
    Aug 8 '17 at 0:59
















$begingroup$
The best you could do is try to animate surface plots and see the evolution.
$endgroup$
– Sean Roberson
Aug 7 '17 at 17:38




$begingroup$
The best you could do is try to animate surface plots and see the evolution.
$endgroup$
– Sean Roberson
Aug 7 '17 at 17:38












$begingroup$
@Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
$endgroup$
– iadvd
Aug 8 '17 at 0:26




$begingroup$
@Irregardless do you have the points in a txt file or so? I would use a projection of the points in a 3D space. I have done similar things before, here you have an example. If you can add a link to the points I can try to visualize them with python (it will take me one day maybe) math.stackexchange.com/questions/2131551/…
$endgroup$
– iadvd
Aug 8 '17 at 0:26












$begingroup$
@Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
$endgroup$
– iadvd
Aug 8 '17 at 0:26




$begingroup$
@Irregardless or if you want to try yourself, in this other question I wrote the python template you can use to visualize the projection math.stackexchange.com/questions/2125036/…
$endgroup$
– iadvd
Aug 8 '17 at 0:26












$begingroup$
@Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
$endgroup$
– iadvd
Aug 8 '17 at 0:59




$begingroup$
@Irreglardless no hurries, I will try to find a moment also to do it. How can we do? do you have dropbox for instance? you can leave a link to a shared folder, so I can download it.
$endgroup$
– iadvd
Aug 8 '17 at 0:59










2 Answers
2






active

oldest

votes


















5












$begingroup$

Whereas the bivariate Normal yields elliptical contours (or a circle given zero correlation), the trivariate case yields the intuitive 3D equivalent, namely the surface of an ellipsoid (or that of a sphere given zero correlations).



So, at each point in time (reducing you to 3D), a contour plot of the pdf $f(x,y,z)$ = constant would look something like this:



enter image description here



where parameter $rho_{x,y}$ alters the 'orientation' of the ellipsoid in the $x$-$y$ plane etc






share|cite|improve this answer









$endgroup$





















    2












    $begingroup$

    This answer focuses on the first need of the OP:




    I have some $4$-D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function.




    I have used a cloud of more than $4cdot10^4$ $(w,x,y,z)$ points that the OP has sent me by email to make some $3$D projections. There are several options when projecting. In this case what you will see is a projection into a $3$D $(x1,x2,x3)$ cloud of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



    $x1=w$



    $x2=x$



    $x3=$projection of the data in plane $(y,z)$ of the points.



    The merging of $y$ and $z$ is due to a source of "$4$D light" that is located "behind" the $4$D cloud of points, specifically to create a shadow of the plane of $(y,z)$ of the cloud of points, being the shadow the projected points at $x3$.
    (A more concise explanation about the way of calculating the projection is in this other question).



    enter image description here



    Any $3$D projection is an "slice" of the $4$D object, just a cut of it. Thus, to see the "complete" $4$D object we need to rotate $360$° , with a camera around it in the $4$D space and see how evolves the projection. In $3$D we can only see one slice at a time, so a complete $360$° rotation around the $4$D object (in this case the "object" is a cloud of points) gives a final idea of how it looks in four dimensions. Here, the projection of the complete rotation around the $4$D cloud is shown (so basically we are seeing the "whole body" of the cloud if we consider it as a unique object):



    enter image description here



    Well in this case, more than $3$D is something like a "$2.5$D" (because we are visualizing a $3$D projection into this computer screen, so we are simulating three dimensions with two dimensions).



    I will add another different plane projection in some hours or maybe tomorrow (the Python program that creates the aforementioned slides takes some time to finish, and after that I use VirtualDub to create an animated gif).



    Update: 2017/08/10. As promised here is the $(x_1,x_2,x_3)$ projection of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



    $x_1=$projection of the data in plane $(w,x)$ of the points.



    $x_2=y$



    $x_3=z$



    A single slice:



    enter image description here



    And the complete object ($360$° view of the cloud). I do not know what the OP's points represent, but it looks quite cool:



    enter image description here






    share|cite|improve this answer











    $endgroup$













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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      5












      $begingroup$

      Whereas the bivariate Normal yields elliptical contours (or a circle given zero correlation), the trivariate case yields the intuitive 3D equivalent, namely the surface of an ellipsoid (or that of a sphere given zero correlations).



      So, at each point in time (reducing you to 3D), a contour plot of the pdf $f(x,y,z)$ = constant would look something like this:



      enter image description here



      where parameter $rho_{x,y}$ alters the 'orientation' of the ellipsoid in the $x$-$y$ plane etc






      share|cite|improve this answer









      $endgroup$


















        5












        $begingroup$

        Whereas the bivariate Normal yields elliptical contours (or a circle given zero correlation), the trivariate case yields the intuitive 3D equivalent, namely the surface of an ellipsoid (or that of a sphere given zero correlations).



        So, at each point in time (reducing you to 3D), a contour plot of the pdf $f(x,y,z)$ = constant would look something like this:



        enter image description here



        where parameter $rho_{x,y}$ alters the 'orientation' of the ellipsoid in the $x$-$y$ plane etc






        share|cite|improve this answer









        $endgroup$
















          5












          5








          5





          $begingroup$

          Whereas the bivariate Normal yields elliptical contours (or a circle given zero correlation), the trivariate case yields the intuitive 3D equivalent, namely the surface of an ellipsoid (or that of a sphere given zero correlations).



          So, at each point in time (reducing you to 3D), a contour plot of the pdf $f(x,y,z)$ = constant would look something like this:



          enter image description here



          where parameter $rho_{x,y}$ alters the 'orientation' of the ellipsoid in the $x$-$y$ plane etc






          share|cite|improve this answer









          $endgroup$



          Whereas the bivariate Normal yields elliptical contours (or a circle given zero correlation), the trivariate case yields the intuitive 3D equivalent, namely the surface of an ellipsoid (or that of a sphere given zero correlations).



          So, at each point in time (reducing you to 3D), a contour plot of the pdf $f(x,y,z)$ = constant would look something like this:



          enter image description here



          where parameter $rho_{x,y}$ alters the 'orientation' of the ellipsoid in the $x$-$y$ plane etc







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Aug 7 '17 at 17:48









          wolfieswolfies

          4,1662923




          4,1662923























              2












              $begingroup$

              This answer focuses on the first need of the OP:




              I have some $4$-D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function.




              I have used a cloud of more than $4cdot10^4$ $(w,x,y,z)$ points that the OP has sent me by email to make some $3$D projections. There are several options when projecting. In this case what you will see is a projection into a $3$D $(x1,x2,x3)$ cloud of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



              $x1=w$



              $x2=x$



              $x3=$projection of the data in plane $(y,z)$ of the points.



              The merging of $y$ and $z$ is due to a source of "$4$D light" that is located "behind" the $4$D cloud of points, specifically to create a shadow of the plane of $(y,z)$ of the cloud of points, being the shadow the projected points at $x3$.
              (A more concise explanation about the way of calculating the projection is in this other question).



              enter image description here



              Any $3$D projection is an "slice" of the $4$D object, just a cut of it. Thus, to see the "complete" $4$D object we need to rotate $360$° , with a camera around it in the $4$D space and see how evolves the projection. In $3$D we can only see one slice at a time, so a complete $360$° rotation around the $4$D object (in this case the "object" is a cloud of points) gives a final idea of how it looks in four dimensions. Here, the projection of the complete rotation around the $4$D cloud is shown (so basically we are seeing the "whole body" of the cloud if we consider it as a unique object):



              enter image description here



              Well in this case, more than $3$D is something like a "$2.5$D" (because we are visualizing a $3$D projection into this computer screen, so we are simulating three dimensions with two dimensions).



              I will add another different plane projection in some hours or maybe tomorrow (the Python program that creates the aforementioned slides takes some time to finish, and after that I use VirtualDub to create an animated gif).



              Update: 2017/08/10. As promised here is the $(x_1,x_2,x_3)$ projection of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



              $x_1=$projection of the data in plane $(w,x)$ of the points.



              $x_2=y$



              $x_3=z$



              A single slice:



              enter image description here



              And the complete object ($360$° view of the cloud). I do not know what the OP's points represent, but it looks quite cool:



              enter image description here






              share|cite|improve this answer











              $endgroup$


















                2












                $begingroup$

                This answer focuses on the first need of the OP:




                I have some $4$-D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function.




                I have used a cloud of more than $4cdot10^4$ $(w,x,y,z)$ points that the OP has sent me by email to make some $3$D projections. There are several options when projecting. In this case what you will see is a projection into a $3$D $(x1,x2,x3)$ cloud of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                $x1=w$



                $x2=x$



                $x3=$projection of the data in plane $(y,z)$ of the points.



                The merging of $y$ and $z$ is due to a source of "$4$D light" that is located "behind" the $4$D cloud of points, specifically to create a shadow of the plane of $(y,z)$ of the cloud of points, being the shadow the projected points at $x3$.
                (A more concise explanation about the way of calculating the projection is in this other question).



                enter image description here



                Any $3$D projection is an "slice" of the $4$D object, just a cut of it. Thus, to see the "complete" $4$D object we need to rotate $360$° , with a camera around it in the $4$D space and see how evolves the projection. In $3$D we can only see one slice at a time, so a complete $360$° rotation around the $4$D object (in this case the "object" is a cloud of points) gives a final idea of how it looks in four dimensions. Here, the projection of the complete rotation around the $4$D cloud is shown (so basically we are seeing the "whole body" of the cloud if we consider it as a unique object):



                enter image description here



                Well in this case, more than $3$D is something like a "$2.5$D" (because we are visualizing a $3$D projection into this computer screen, so we are simulating three dimensions with two dimensions).



                I will add another different plane projection in some hours or maybe tomorrow (the Python program that creates the aforementioned slides takes some time to finish, and after that I use VirtualDub to create an animated gif).



                Update: 2017/08/10. As promised here is the $(x_1,x_2,x_3)$ projection of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                $x_1=$projection of the data in plane $(w,x)$ of the points.



                $x_2=y$



                $x_3=z$



                A single slice:



                enter image description here



                And the complete object ($360$° view of the cloud). I do not know what the OP's points represent, but it looks quite cool:



                enter image description here






                share|cite|improve this answer











                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  This answer focuses on the first need of the OP:




                  I have some $4$-D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function.




                  I have used a cloud of more than $4cdot10^4$ $(w,x,y,z)$ points that the OP has sent me by email to make some $3$D projections. There are several options when projecting. In this case what you will see is a projection into a $3$D $(x1,x2,x3)$ cloud of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                  $x1=w$



                  $x2=x$



                  $x3=$projection of the data in plane $(y,z)$ of the points.



                  The merging of $y$ and $z$ is due to a source of "$4$D light" that is located "behind" the $4$D cloud of points, specifically to create a shadow of the plane of $(y,z)$ of the cloud of points, being the shadow the projected points at $x3$.
                  (A more concise explanation about the way of calculating the projection is in this other question).



                  enter image description here



                  Any $3$D projection is an "slice" of the $4$D object, just a cut of it. Thus, to see the "complete" $4$D object we need to rotate $360$° , with a camera around it in the $4$D space and see how evolves the projection. In $3$D we can only see one slice at a time, so a complete $360$° rotation around the $4$D object (in this case the "object" is a cloud of points) gives a final idea of how it looks in four dimensions. Here, the projection of the complete rotation around the $4$D cloud is shown (so basically we are seeing the "whole body" of the cloud if we consider it as a unique object):



                  enter image description here



                  Well in this case, more than $3$D is something like a "$2.5$D" (because we are visualizing a $3$D projection into this computer screen, so we are simulating three dimensions with two dimensions).



                  I will add another different plane projection in some hours or maybe tomorrow (the Python program that creates the aforementioned slides takes some time to finish, and after that I use VirtualDub to create an animated gif).



                  Update: 2017/08/10. As promised here is the $(x_1,x_2,x_3)$ projection of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                  $x_1=$projection of the data in plane $(w,x)$ of the points.



                  $x_2=y$



                  $x_3=z$



                  A single slice:



                  enter image description here



                  And the complete object ($360$° view of the cloud). I do not know what the OP's points represent, but it looks quite cool:



                  enter image description here






                  share|cite|improve this answer











                  $endgroup$



                  This answer focuses on the first need of the OP:




                  I have some $4$-D data in $(w,x,y,z)$ quaternion format that I'd like to graph to discern whether or not it follows a Gaussian function.




                  I have used a cloud of more than $4cdot10^4$ $(w,x,y,z)$ points that the OP has sent me by email to make some $3$D projections. There are several options when projecting. In this case what you will see is a projection into a $3$D $(x1,x2,x3)$ cloud of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                  $x1=w$



                  $x2=x$



                  $x3=$projection of the data in plane $(y,z)$ of the points.



                  The merging of $y$ and $z$ is due to a source of "$4$D light" that is located "behind" the $4$D cloud of points, specifically to create a shadow of the plane of $(y,z)$ of the cloud of points, being the shadow the projected points at $x3$.
                  (A more concise explanation about the way of calculating the projection is in this other question).



                  enter image description here



                  Any $3$D projection is an "slice" of the $4$D object, just a cut of it. Thus, to see the "complete" $4$D object we need to rotate $360$° , with a camera around it in the $4$D space and see how evolves the projection. In $3$D we can only see one slice at a time, so a complete $360$° rotation around the $4$D object (in this case the "object" is a cloud of points) gives a final idea of how it looks in four dimensions. Here, the projection of the complete rotation around the $4$D cloud is shown (so basically we are seeing the "whole body" of the cloud if we consider it as a unique object):



                  enter image description here



                  Well in this case, more than $3$D is something like a "$2.5$D" (because we are visualizing a $3$D projection into this computer screen, so we are simulating three dimensions with two dimensions).



                  I will add another different plane projection in some hours or maybe tomorrow (the Python program that creates the aforementioned slides takes some time to finish, and after that I use VirtualDub to create an animated gif).



                  Update: 2017/08/10. As promised here is the $(x_1,x_2,x_3)$ projection of the original cloud $(w,x,y,z)$ of $4$D points with the following settings:



                  $x_1=$projection of the data in plane $(w,x)$ of the points.



                  $x_2=y$



                  $x_3=z$



                  A single slice:



                  enter image description here



                  And the complete object ($360$° view of the cloud). I do not know what the OP's points represent, but it looks quite cool:



                  enter image description here







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Aug 10 '17 at 16:21









                  Irregardless

                  435417




                  435417










                  answered Aug 9 '17 at 8:35









                  iadvdiadvd

                  5,435102655




                  5,435102655






























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