Is this relation always an equivalence relation? [closed]
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Given a relation $R$, and a relation $S$ that is the inverse of $R,;$
is $S circ R$ always an equivalence relation?
relations equivalence-relations
edited Jan 17 at 13:14
jordan_glen
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
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closed as off-topic by José Carlos Santos, Alexander Gruber♦ Jan 17 at 23:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
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$begingroup$
Given a relation $R$, and a relation $S$ that is the inverse of $R,;$
is $S circ R$ always an equivalence relation?
relations equivalence-relations
edited Jan 17 at 13:14
jordan_glen
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
$endgroup$
closed as off-topic by José Carlos Santos, Alexander Gruber♦ Jan 17 at 23:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Given a relation $R$, and a relation $S$ that is the inverse of $R,;$
is $S circ R$ always an equivalence relation?
relations equivalence-relations
edited Jan 17 at 13:14
jordan_glen
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
$endgroup$
Given a relation $R$, and a relation $S$ that is the inverse of $R,;$
is $S circ R$ always an equivalence relation?
relations equivalence-relations
relations equivalence-relations
edited Jan 17 at 13:14
jordan_glen
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
edited Jan 17 at 13:14
jordan_glen
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
edited Jan 17 at 13:14
jordan_glen
1
edited Jan 17 at 13:14
jordan_glen
1
edited Jan 17 at 13:14
jordan_glen
1
1
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
asked Jan 17 at 11:49
Ayoub RossiAyoub Rossi
11610
11610
closed as off-topic by José Carlos Santos, Alexander Gruber♦ Jan 17 at 23:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by José Carlos Santos, Alexander Gruber♦ Jan 17 at 23:19
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
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1 Answer
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No. Let $X={a,b,c}$ and $R={(a,b)}$. Then $S={(b,a)}$, but $(c,c) notin S circ R.$
answered Jan 17 at 12:03
FredFred
46.1k1848
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
No. Let $X={a,b,c}$ and $R={(a,b)}$. Then $S={(b,a)}$, but $(c,c) notin S circ R.$
answered Jan 17 at 12:03
FredFred
46.1k1848
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add a comment |
$begingroup$
No. Let $X={a,b,c}$ and $R={(a,b)}$. Then $S={(b,a)}$, but $(c,c) notin S circ R.$
answered Jan 17 at 12:03
FredFred
46.1k1848
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add a comment |
$begingroup$
No. Let $X={a,b,c}$ and $R={(a,b)}$. Then $S={(b,a)}$, but $(c,c) notin S circ R.$
answered Jan 17 at 12:03
FredFred
46.1k1848
$endgroup$
No. Let $X={a,b,c}$ and $R={(a,b)}$. Then $S={(b,a)}$, but $(c,c) notin S circ R.$
answered Jan 17 at 12:03
FredFred
46.1k1848
answered Jan 17 at 12:03
FredFred
46.1k1848
answered Jan 17 at 12:03
FredFred
46.1k1848
answered Jan 17 at 12:03
FredFred
46.1k1848
46.1k1848
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