Integral of a standard gaussian distribution
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Please see the image. I know that the integral of P(x) tends to 1. But the quadratic equation next to P(x) seems confusing.
probability-distributions normal-distribution
edited Jan 21 at 6:27
StubbornAtom
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
$endgroup$
add a comment |
$begingroup$
Please see the image. I know that the integral of P(x) tends to 1. But the quadratic equation next to P(x) seems confusing.
probability-distributions normal-distribution
edited Jan 21 at 6:27
StubbornAtom
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
$endgroup$
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What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
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I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15
add a comment |
$begingroup$
Please see the image. I know that the integral of P(x) tends to 1. But the quadratic equation next to P(x) seems confusing.
probability-distributions normal-distribution
edited Jan 21 at 6:27
StubbornAtom
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
$endgroup$
Please see the image. I know that the integral of P(x) tends to 1. But the quadratic equation next to P(x) seems confusing.
probability-distributions normal-distribution
probability-distributions normal-distribution
edited Jan 21 at 6:27
StubbornAtom
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
edited Jan 21 at 6:27
StubbornAtom
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
edited Jan 21 at 6:27
StubbornAtom
6,04811239
edited Jan 21 at 6:27
StubbornAtom
6,04811239
edited Jan 21 at 6:27
StubbornAtom
6,04811239
6,04811239
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
asked Jan 20 at 23:20
Hari Hara Kumar RajanalaHari Hara Kumar Rajanala
6
6
$begingroup$
What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
$begingroup$
I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15
add a comment |
$begingroup$
What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
$begingroup$
I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15
$begingroup$
What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
$begingroup$
What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
$begingroup$
I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Note: click on the 'edit' button on this answer to understand how to format your questions using Mathjax
You are trying to evaluate:
$$
int p(x) (ax^2 + bx+c)dx
$$
you can break this up into:
$$
a int p(x)x^2dx + bint p(x)xdx+ cint p(x)dx
$$
Then use the following facts:
$$
int p(x) x^2dx = mathbb{E}(x^2) = Var(x) + mathbb{E}(x)^2
$$
and
$$
int p(x) x dx= mathbb{E}(x)
$$
and finally:
$$
int p(x)dx = 1
$$
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
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add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Note: click on the 'edit' button on this answer to understand how to format your questions using Mathjax
You are trying to evaluate:
$$
int p(x) (ax^2 + bx+c)dx
$$
you can break this up into:
$$
a int p(x)x^2dx + bint p(x)xdx+ cint p(x)dx
$$
Then use the following facts:
$$
int p(x) x^2dx = mathbb{E}(x^2) = Var(x) + mathbb{E}(x)^2
$$
and
$$
int p(x) x dx= mathbb{E}(x)
$$
and finally:
$$
int p(x)dx = 1
$$
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
$endgroup$
add a comment |
$begingroup$
Note: click on the 'edit' button on this answer to understand how to format your questions using Mathjax
You are trying to evaluate:
$$
int p(x) (ax^2 + bx+c)dx
$$
you can break this up into:
$$
a int p(x)x^2dx + bint p(x)xdx+ cint p(x)dx
$$
Then use the following facts:
$$
int p(x) x^2dx = mathbb{E}(x^2) = Var(x) + mathbb{E}(x)^2
$$
and
$$
int p(x) x dx= mathbb{E}(x)
$$
and finally:
$$
int p(x)dx = 1
$$
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
$endgroup$
add a comment |
$begingroup$
Note: click on the 'edit' button on this answer to understand how to format your questions using Mathjax
You are trying to evaluate:
$$
int p(x) (ax^2 + bx+c)dx
$$
you can break this up into:
$$
a int p(x)x^2dx + bint p(x)xdx+ cint p(x)dx
$$
Then use the following facts:
$$
int p(x) x^2dx = mathbb{E}(x^2) = Var(x) + mathbb{E}(x)^2
$$
and
$$
int p(x) x dx= mathbb{E}(x)
$$
and finally:
$$
int p(x)dx = 1
$$
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
$endgroup$
Note: click on the 'edit' button on this answer to understand how to format your questions using Mathjax
You are trying to evaluate:
$$
int p(x) (ax^2 + bx+c)dx
$$
you can break this up into:
$$
a int p(x)x^2dx + bint p(x)xdx+ cint p(x)dx
$$
Then use the following facts:
$$
int p(x) x^2dx = mathbb{E}(x^2) = Var(x) + mathbb{E}(x)^2
$$
and
$$
int p(x) x dx= mathbb{E}(x)
$$
and finally:
$$
int p(x)dx = 1
$$
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
answered Jan 21 at 0:43
dimebuckerdimebucker
1,66511129
1,66511129
add a comment |
add a comment |
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$begingroup$
What have you tried? please use mathjax to typeset math.
$endgroup$
– Viktor Glombik
Jan 20 at 23:21
$begingroup$
I am new to this forum. So, please click on the link to view the image
$endgroup$
– Hari Hara Kumar Rajanala
Jan 20 at 23:21
$begingroup$
Edit your question for the image to appear in your post.
$endgroup$
– BlackMath
Jan 21 at 0:15