Need help to approach a question of Mensuration [closed]












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Answered: In a cylinderical vessel of diameter 24 cm filled
up with sufficient quantity of water, a solid
spherical ball, of radius 6 cm is completely immersed. Then the increases in height of water.










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closed as off-topic by fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin Jan 25 at 23:19


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$begingroup$


Answered: In a cylinderical vessel of diameter 24 cm filled
up with sufficient quantity of water, a solid
spherical ball, of radius 6 cm is completely immersed. Then the increases in height of water.










share|cite|improve this question











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closed as off-topic by fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin Jan 25 at 23:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin

If this question can be reworded to fit the rules in the help center, please edit the question.
















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    Comments are not for extended discussion; this conversation has been moved to chat.
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    – Aloizio Macedo
    Jan 26 at 15:53














-1












-1








-1





$begingroup$


Answered: In a cylinderical vessel of diameter 24 cm filled
up with sufficient quantity of water, a solid
spherical ball, of radius 6 cm is completely immersed. Then the increases in height of water.










share|cite|improve this question











$endgroup$




Answered: In a cylinderical vessel of diameter 24 cm filled
up with sufficient quantity of water, a solid
spherical ball, of radius 6 cm is completely immersed. Then the increases in height of water.







geometry euclidean-geometry






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edited Jan 27 at 5:35







Sagar Gupta

















asked Jan 25 at 11:08









Sagar GuptaSagar Gupta

16




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closed as off-topic by fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin Jan 25 at 23:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin Jan 25 at 23:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – fermesomme, Namaste, Eric Wofsey, Robert Z, Lee David Chung Lin

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Comments are not for extended discussion; this conversation has been moved to chat.
    $endgroup$
    – Aloizio Macedo
    Jan 26 at 15:53


















  • $begingroup$
    Comments are not for extended discussion; this conversation has been moved to chat.
    $endgroup$
    – Aloizio Macedo
    Jan 26 at 15:53
















$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– Aloizio Macedo
Jan 26 at 15:53




$begingroup$
Comments are not for extended discussion; this conversation has been moved to chat.
$endgroup$
– Aloizio Macedo
Jan 26 at 15:53










1 Answer
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First, you need to find the volume of the sphere, which is equivalent to the volume of water displaced:
$$ frac{4pi r^3}{3} = frac{4pi 6^3}{3} = 288pi $$
Since the vessel is cylindrical, we can find the increase in height, $h$, using the following formula for the volume of a cylinder:
$$ pi r^2h = V = 288pi $$






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    First, you need to find the volume of the sphere, which is equivalent to the volume of water displaced:
    $$ frac{4pi r^3}{3} = frac{4pi 6^3}{3} = 288pi $$
    Since the vessel is cylindrical, we can find the increase in height, $h$, using the following formula for the volume of a cylinder:
    $$ pi r^2h = V = 288pi $$






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      First, you need to find the volume of the sphere, which is equivalent to the volume of water displaced:
      $$ frac{4pi r^3}{3} = frac{4pi 6^3}{3} = 288pi $$
      Since the vessel is cylindrical, we can find the increase in height, $h$, using the following formula for the volume of a cylinder:
      $$ pi r^2h = V = 288pi $$






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        First, you need to find the volume of the sphere, which is equivalent to the volume of water displaced:
        $$ frac{4pi r^3}{3} = frac{4pi 6^3}{3} = 288pi $$
        Since the vessel is cylindrical, we can find the increase in height, $h$, using the following formula for the volume of a cylinder:
        $$ pi r^2h = V = 288pi $$






        share|cite|improve this answer









        $endgroup$



        First, you need to find the volume of the sphere, which is equivalent to the volume of water displaced:
        $$ frac{4pi r^3}{3} = frac{4pi 6^3}{3} = 288pi $$
        Since the vessel is cylindrical, we can find the increase in height, $h$, using the following formula for the volume of a cylinder:
        $$ pi r^2h = V = 288pi $$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 25 at 11:35









        Geneten48Geneten48

        1549




        1549















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