Transformation of a scalar function
Multi tool use
$begingroup$
Given a scalar function, we consider the following transformation:
$$delta f(x) = f'(x') - f(x) $$
But since $f(x)$ is a scalar isn't it true that $ f'(x') = f(x) $
Then the variation is always zero? What am I missing?
transformation
asked Jan 17 at 17:58
HiggsinoHiggsino
595
$endgroup$
add a comment |
$begingroup$
Given a scalar function, we consider the following transformation:
$$delta f(x) = f'(x') - f(x) $$
But since $f(x)$ is a scalar isn't it true that $ f'(x') = f(x) $
Then the variation is always zero? What am I missing?
transformation
asked Jan 17 at 17:58
HiggsinoHiggsino
595
$endgroup$
add a comment |
$begingroup$
Given a scalar function, we consider the following transformation:
$$delta f(x) = f'(x') - f(x) $$
But since $f(x)$ is a scalar isn't it true that $ f'(x') = f(x) $
Then the variation is always zero? What am I missing?
transformation
asked Jan 17 at 17:58
HiggsinoHiggsino
595
$endgroup$
Given a scalar function, we consider the following transformation:
$$delta f(x) = f'(x') - f(x) $$
But since $f(x)$ is a scalar isn't it true that $ f'(x') = f(x) $
Then the variation is always zero? What am I missing?
transformation
transformation
asked Jan 17 at 17:58
HiggsinoHiggsino
595
asked Jan 17 at 17:58
HiggsinoHiggsino
595
asked Jan 17 at 17:58
HiggsinoHiggsino
595
asked Jan 17 at 17:58
HiggsinoHiggsino
595
asked Jan 17 at 17:58
HiggsinoHiggsino
595
595
add a comment |
add a comment |
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