Probabilistic models problem
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Problem:
The probability of a player making a free throw is 0.6. Find the probability that the player makes the first at least 7 consecutive free throws.
The problem is that I have a dilemma: the requirement sounds for me that I need to use the formula from Poisson Model, but in that case, number of successes will be 8 (because "at least 7"), and I don't know how to find the number of trials, it will be also 8? Is it correct what I suppose?
probability probability-theory
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
$endgroup$
add a comment |
$begingroup$
Problem:
The probability of a player making a free throw is 0.6. Find the probability that the player makes the first at least 7 consecutive free throws.
The problem is that I have a dilemma: the requirement sounds for me that I need to use the formula from Poisson Model, but in that case, number of successes will be 8 (because "at least 7"), and I don't know how to find the number of trials, it will be also 8? Is it correct what I suppose?
probability probability-theory
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
$endgroup$
3
$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31
add a comment |
$begingroup$
Problem:
The probability of a player making a free throw is 0.6. Find the probability that the player makes the first at least 7 consecutive free throws.
The problem is that I have a dilemma: the requirement sounds for me that I need to use the formula from Poisson Model, but in that case, number of successes will be 8 (because "at least 7"), and I don't know how to find the number of trials, it will be also 8? Is it correct what I suppose?
probability probability-theory
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
$endgroup$
Problem:
The probability of a player making a free throw is 0.6. Find the probability that the player makes the first at least 7 consecutive free throws.
The problem is that I have a dilemma: the requirement sounds for me that I need to use the formula from Poisson Model, but in that case, number of successes will be 8 (because "at least 7"), and I don't know how to find the number of trials, it will be also 8? Is it correct what I suppose?
probability probability-theory
probability probability-theory
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
asked Jan 21 at 12:28
Haha ahahahHaha ahahah
233
233
3
$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31
add a comment |
3
$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31
3
3
$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31
$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
It's worth noting:
"at least $7$" means $geq 7$
"more than $7$" means $> 7$
In your problem, the probability that the player makes all $7$ consecutive free throws is simply $$0.6^7,=, 0.0279936$$
Whether or not they make any shots after the $7^text{th}$ is irrelevant.
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
$endgroup$
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It's worth noting:
"at least $7$" means $geq 7$
"more than $7$" means $> 7$
In your problem, the probability that the player makes all $7$ consecutive free throws is simply $$0.6^7,=, 0.0279936$$
Whether or not they make any shots after the $7^text{th}$ is irrelevant.
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
$endgroup$
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
add a comment |
$begingroup$
It's worth noting:
"at least $7$" means $geq 7$
"more than $7$" means $> 7$
In your problem, the probability that the player makes all $7$ consecutive free throws is simply $$0.6^7,=, 0.0279936$$
Whether or not they make any shots after the $7^text{th}$ is irrelevant.
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
$endgroup$
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
add a comment |
$begingroup$
It's worth noting:
"at least $7$" means $geq 7$
"more than $7$" means $> 7$
In your problem, the probability that the player makes all $7$ consecutive free throws is simply $$0.6^7,=, 0.0279936$$
Whether or not they make any shots after the $7^text{th}$ is irrelevant.
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
$endgroup$
It's worth noting:
"at least $7$" means $geq 7$
"more than $7$" means $> 7$
In your problem, the probability that the player makes all $7$ consecutive free throws is simply $$0.6^7,=, 0.0279936$$
Whether or not they make any shots after the $7^text{th}$ is irrelevant.
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
answered Jan 21 at 12:32
Zubin MukerjeeZubin Mukerjee
15.2k32658
15.2k32658
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
add a comment |
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
$begingroup$
That was my mistake :). Thanks a lot!
$endgroup$
– Haha ahahah
Jan 21 at 12:35
add a comment |
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$begingroup$
Why Poisson? the probability of making $n$ in a row is just $.6^n$
$endgroup$
– lulu
Jan 21 at 12:31