Identifying changes in new data using previously trained regression model












1












$begingroup$


I would like some ideas on the following problem. I have a data $x$:
$$x(y,z) = [x_1(y,z), x_2(y,z), x_3(y,z)]$$
such that they are function of $(y,z)$, but neither of $(y,z)$ is available. Therefore I set up a regression model, such that:
$$tilde{x}_1 = ax_2 + bx_3$$
$$tilde{x}_2 = ax_1 + bx_3 tag{1}$$
$$tilde{x}_3 = ax_1 + bx_2$$



Such model, let's simplify the notation to $tilde{x}_i = ABx_{notin{i}}$, can reflect when there is a change of $x$, other than due to $(y,z)$. This is because the relationship, other than relationship to $(y,z)$ is broken and the model will output $tilde{x}$, which is different from the given $x$.



Now, I also know, that $x_{new}$, that is the new incoming data, can differ from $x$, only in some particular way, lets say:



$$x = n^{(1)}x_{new} + n^{(2)} tag{2}$$



where $n^{(1)}$ and $n^{(2)}$ are vectors, the same dimension as $x$. This gives $2*dim(x)$ unknowns.





QUESTION:



Is it possible to recover the vectors $n^{(1)}$, $n^{(2)}$, given sufficient data $x_{new}$ ?



The whole problem again in simple words. The regression model is trained on $x_{train}$, such that $(1)$ is obtained. Then there is a change in the input $x$, such that $x_{new}$ in $(1)$ produces error. Can I find a function $(2)$, such that $x_{new}$ in $(2)$, will give $x$ using $(1)$ ?



Is there any material/technique that could help me to analyze this situation / solve the problem ?





P.S.



I have simply plugged $(2)$ into $(1)$, and using at least 2 $x_{new}$ to obtain $n^{(1)}$, $n^{(2)}$. Why 2 $x_{new}$ ? Because there are $2*dim(x)$ unknowns. This probably should work, but it is non-convex and relatively difficult to optimize.



P.S.2



I can use some stochastic search algorithm, but I would rather try some more mathematically reasoned techniques.










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    I would like some ideas on the following problem. I have a data $x$:
    $$x(y,z) = [x_1(y,z), x_2(y,z), x_3(y,z)]$$
    such that they are function of $(y,z)$, but neither of $(y,z)$ is available. Therefore I set up a regression model, such that:
    $$tilde{x}_1 = ax_2 + bx_3$$
    $$tilde{x}_2 = ax_1 + bx_3 tag{1}$$
    $$tilde{x}_3 = ax_1 + bx_2$$



    Such model, let's simplify the notation to $tilde{x}_i = ABx_{notin{i}}$, can reflect when there is a change of $x$, other than due to $(y,z)$. This is because the relationship, other than relationship to $(y,z)$ is broken and the model will output $tilde{x}$, which is different from the given $x$.



    Now, I also know, that $x_{new}$, that is the new incoming data, can differ from $x$, only in some particular way, lets say:



    $$x = n^{(1)}x_{new} + n^{(2)} tag{2}$$



    where $n^{(1)}$ and $n^{(2)}$ are vectors, the same dimension as $x$. This gives $2*dim(x)$ unknowns.





    QUESTION:



    Is it possible to recover the vectors $n^{(1)}$, $n^{(2)}$, given sufficient data $x_{new}$ ?



    The whole problem again in simple words. The regression model is trained on $x_{train}$, such that $(1)$ is obtained. Then there is a change in the input $x$, such that $x_{new}$ in $(1)$ produces error. Can I find a function $(2)$, such that $x_{new}$ in $(2)$, will give $x$ using $(1)$ ?



    Is there any material/technique that could help me to analyze this situation / solve the problem ?





    P.S.



    I have simply plugged $(2)$ into $(1)$, and using at least 2 $x_{new}$ to obtain $n^{(1)}$, $n^{(2)}$. Why 2 $x_{new}$ ? Because there are $2*dim(x)$ unknowns. This probably should work, but it is non-convex and relatively difficult to optimize.



    P.S.2



    I can use some stochastic search algorithm, but I would rather try some more mathematically reasoned techniques.










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      I would like some ideas on the following problem. I have a data $x$:
      $$x(y,z) = [x_1(y,z), x_2(y,z), x_3(y,z)]$$
      such that they are function of $(y,z)$, but neither of $(y,z)$ is available. Therefore I set up a regression model, such that:
      $$tilde{x}_1 = ax_2 + bx_3$$
      $$tilde{x}_2 = ax_1 + bx_3 tag{1}$$
      $$tilde{x}_3 = ax_1 + bx_2$$



      Such model, let's simplify the notation to $tilde{x}_i = ABx_{notin{i}}$, can reflect when there is a change of $x$, other than due to $(y,z)$. This is because the relationship, other than relationship to $(y,z)$ is broken and the model will output $tilde{x}$, which is different from the given $x$.



      Now, I also know, that $x_{new}$, that is the new incoming data, can differ from $x$, only in some particular way, lets say:



      $$x = n^{(1)}x_{new} + n^{(2)} tag{2}$$



      where $n^{(1)}$ and $n^{(2)}$ are vectors, the same dimension as $x$. This gives $2*dim(x)$ unknowns.





      QUESTION:



      Is it possible to recover the vectors $n^{(1)}$, $n^{(2)}$, given sufficient data $x_{new}$ ?



      The whole problem again in simple words. The regression model is trained on $x_{train}$, such that $(1)$ is obtained. Then there is a change in the input $x$, such that $x_{new}$ in $(1)$ produces error. Can I find a function $(2)$, such that $x_{new}$ in $(2)$, will give $x$ using $(1)$ ?



      Is there any material/technique that could help me to analyze this situation / solve the problem ?





      P.S.



      I have simply plugged $(2)$ into $(1)$, and using at least 2 $x_{new}$ to obtain $n^{(1)}$, $n^{(2)}$. Why 2 $x_{new}$ ? Because there are $2*dim(x)$ unknowns. This probably should work, but it is non-convex and relatively difficult to optimize.



      P.S.2



      I can use some stochastic search algorithm, but I would rather try some more mathematically reasoned techniques.










      share|cite|improve this question









      $endgroup$




      I would like some ideas on the following problem. I have a data $x$:
      $$x(y,z) = [x_1(y,z), x_2(y,z), x_3(y,z)]$$
      such that they are function of $(y,z)$, but neither of $(y,z)$ is available. Therefore I set up a regression model, such that:
      $$tilde{x}_1 = ax_2 + bx_3$$
      $$tilde{x}_2 = ax_1 + bx_3 tag{1}$$
      $$tilde{x}_3 = ax_1 + bx_2$$



      Such model, let's simplify the notation to $tilde{x}_i = ABx_{notin{i}}$, can reflect when there is a change of $x$, other than due to $(y,z)$. This is because the relationship, other than relationship to $(y,z)$ is broken and the model will output $tilde{x}$, which is different from the given $x$.



      Now, I also know, that $x_{new}$, that is the new incoming data, can differ from $x$, only in some particular way, lets say:



      $$x = n^{(1)}x_{new} + n^{(2)} tag{2}$$



      where $n^{(1)}$ and $n^{(2)}$ are vectors, the same dimension as $x$. This gives $2*dim(x)$ unknowns.





      QUESTION:



      Is it possible to recover the vectors $n^{(1)}$, $n^{(2)}$, given sufficient data $x_{new}$ ?



      The whole problem again in simple words. The regression model is trained on $x_{train}$, such that $(1)$ is obtained. Then there is a change in the input $x$, such that $x_{new}$ in $(1)$ produces error. Can I find a function $(2)$, such that $x_{new}$ in $(2)$, will give $x$ using $(1)$ ?



      Is there any material/technique that could help me to analyze this situation / solve the problem ?





      P.S.



      I have simply plugged $(2)$ into $(1)$, and using at least 2 $x_{new}$ to obtain $n^{(1)}$, $n^{(2)}$. Why 2 $x_{new}$ ? Because there are $2*dim(x)$ unknowns. This probably should work, but it is non-convex and relatively difficult to optimize.



      P.S.2



      I can use some stochastic search algorithm, but I would rather try some more mathematically reasoned techniques.







      optimization regression machine-learning






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 21 at 13:14









      Martin GMartin G

      548




      548






















          0






          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081867%2fidentifying-changes-in-new-data-using-previously-trained-regression-model%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          0






          active

          oldest

          votes








          0






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3081867%2fidentifying-changes-in-new-data-using-previously-trained-regression-model%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Mario Kart Wii

          The Binding of Isaac: Rebirth/Afterbirth

          What does “Dominus providebit” mean?