Guaranteeing isoperimetry constraint for non-extremal functional in PDE.












0












$begingroup$


First of all, hello and thank you for your time.





Context



I am making a program that solves the differential equation for the time evolution of a system from the equations: $$F[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}f(mathbf{x},mathbf{y}, mathbf{nabla y})dmathbf{x}$$
$$frac{partial y_i}{partial t}=kDeltafrac{delta F}{delta y_i}$$
Where $Delta$ is the Laplacian and $$frac{delta F}{delta y_i}=sumlimits_kfrac{partial}{partial x_k}frac{partial f}{partial (partial_ky_i)}-frac{partial f}{partial y_i}$$ is the variational derivative ($partial _k$ is the partial derivative with respect to $x_k$). Also: $mathbf{x}inmathbb{R}^n, mathbf{y}inmathbb{R}^m$



The system should satisfy the global conservation constraints:
$$J_i[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}y_idmathbf{x}=k_i$$
Where the $k_i$ are constants.



I ran the program (without adding the Lagrange multipliers to the integral). And noticed that the $J_i$ increased with time, which was obviously not intended.





Question



I want to add the constraints to the solution. At first I naïvely thought that I could just modify the functional by adding lagrange mutipliers: $$K[mathbf{y}]=F[mathbf{y}]-sumlimits_ilambda_i J_i[mathbf{y}]$$



But when checking my reference book I noticed the Theorem said (I modified and omitted parts to take what's most relevant to the current question):




Suppose that $F$ has an extremum at $yin C^2[x_0, x_1]$ subject to the boundary conditions [...]. Then there exist two numbers $lambda_0, lambda_1$ not both zero such that $$frac{delta K}{delta y}=0$$
Where $K=lambda_0 F-lambda_1 J$




As the theorem says, this works when one wishes to find the extremum so my naïve assumption is probably wrong since the system I described only reaches the extremum of the functional when $mathbf{y}$ gets to the steady state (i.e. it approaches it asymptotically).



Is there a way to satisfy the constraint continuously throughout the time evolution of the system despite $F$ not being stationary?



I understand this may be more involved than what an answer in the site may allow so if you know of any good textbook where I could find it I would also be very grateful.










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    First of all, hello and thank you for your time.





    Context



    I am making a program that solves the differential equation for the time evolution of a system from the equations: $$F[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}f(mathbf{x},mathbf{y}, mathbf{nabla y})dmathbf{x}$$
    $$frac{partial y_i}{partial t}=kDeltafrac{delta F}{delta y_i}$$
    Where $Delta$ is the Laplacian and $$frac{delta F}{delta y_i}=sumlimits_kfrac{partial}{partial x_k}frac{partial f}{partial (partial_ky_i)}-frac{partial f}{partial y_i}$$ is the variational derivative ($partial _k$ is the partial derivative with respect to $x_k$). Also: $mathbf{x}inmathbb{R}^n, mathbf{y}inmathbb{R}^m$



    The system should satisfy the global conservation constraints:
    $$J_i[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}y_idmathbf{x}=k_i$$
    Where the $k_i$ are constants.



    I ran the program (without adding the Lagrange multipliers to the integral). And noticed that the $J_i$ increased with time, which was obviously not intended.





    Question



    I want to add the constraints to the solution. At first I naïvely thought that I could just modify the functional by adding lagrange mutipliers: $$K[mathbf{y}]=F[mathbf{y}]-sumlimits_ilambda_i J_i[mathbf{y}]$$



    But when checking my reference book I noticed the Theorem said (I modified and omitted parts to take what's most relevant to the current question):




    Suppose that $F$ has an extremum at $yin C^2[x_0, x_1]$ subject to the boundary conditions [...]. Then there exist two numbers $lambda_0, lambda_1$ not both zero such that $$frac{delta K}{delta y}=0$$
    Where $K=lambda_0 F-lambda_1 J$




    As the theorem says, this works when one wishes to find the extremum so my naïve assumption is probably wrong since the system I described only reaches the extremum of the functional when $mathbf{y}$ gets to the steady state (i.e. it approaches it asymptotically).



    Is there a way to satisfy the constraint continuously throughout the time evolution of the system despite $F$ not being stationary?



    I understand this may be more involved than what an answer in the site may allow so if you know of any good textbook where I could find it I would also be very grateful.










    share|cite|improve this question











    $endgroup$















      0












      0








      0


      1



      $begingroup$


      First of all, hello and thank you for your time.





      Context



      I am making a program that solves the differential equation for the time evolution of a system from the equations: $$F[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}f(mathbf{x},mathbf{y}, mathbf{nabla y})dmathbf{x}$$
      $$frac{partial y_i}{partial t}=kDeltafrac{delta F}{delta y_i}$$
      Where $Delta$ is the Laplacian and $$frac{delta F}{delta y_i}=sumlimits_kfrac{partial}{partial x_k}frac{partial f}{partial (partial_ky_i)}-frac{partial f}{partial y_i}$$ is the variational derivative ($partial _k$ is the partial derivative with respect to $x_k$). Also: $mathbf{x}inmathbb{R}^n, mathbf{y}inmathbb{R}^m$



      The system should satisfy the global conservation constraints:
      $$J_i[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}y_idmathbf{x}=k_i$$
      Where the $k_i$ are constants.



      I ran the program (without adding the Lagrange multipliers to the integral). And noticed that the $J_i$ increased with time, which was obviously not intended.





      Question



      I want to add the constraints to the solution. At first I naïvely thought that I could just modify the functional by adding lagrange mutipliers: $$K[mathbf{y}]=F[mathbf{y}]-sumlimits_ilambda_i J_i[mathbf{y}]$$



      But when checking my reference book I noticed the Theorem said (I modified and omitted parts to take what's most relevant to the current question):




      Suppose that $F$ has an extremum at $yin C^2[x_0, x_1]$ subject to the boundary conditions [...]. Then there exist two numbers $lambda_0, lambda_1$ not both zero such that $$frac{delta K}{delta y}=0$$
      Where $K=lambda_0 F-lambda_1 J$




      As the theorem says, this works when one wishes to find the extremum so my naïve assumption is probably wrong since the system I described only reaches the extremum of the functional when $mathbf{y}$ gets to the steady state (i.e. it approaches it asymptotically).



      Is there a way to satisfy the constraint continuously throughout the time evolution of the system despite $F$ not being stationary?



      I understand this may be more involved than what an answer in the site may allow so if you know of any good textbook where I could find it I would also be very grateful.










      share|cite|improve this question











      $endgroup$




      First of all, hello and thank you for your time.





      Context



      I am making a program that solves the differential equation for the time evolution of a system from the equations: $$F[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}f(mathbf{x},mathbf{y}, mathbf{nabla y})dmathbf{x}$$
      $$frac{partial y_i}{partial t}=kDeltafrac{delta F}{delta y_i}$$
      Where $Delta$ is the Laplacian and $$frac{delta F}{delta y_i}=sumlimits_kfrac{partial}{partial x_k}frac{partial f}{partial (partial_ky_i)}-frac{partial f}{partial y_i}$$ is the variational derivative ($partial _k$ is the partial derivative with respect to $x_k$). Also: $mathbf{x}inmathbb{R}^n, mathbf{y}inmathbb{R}^m$



      The system should satisfy the global conservation constraints:
      $$J_i[mathbf{y}]=intlimits_{Omegasubsetmathbb{R}^n}y_idmathbf{x}=k_i$$
      Where the $k_i$ are constants.



      I ran the program (without adding the Lagrange multipliers to the integral). And noticed that the $J_i$ increased with time, which was obviously not intended.





      Question



      I want to add the constraints to the solution. At first I naïvely thought that I could just modify the functional by adding lagrange mutipliers: $$K[mathbf{y}]=F[mathbf{y}]-sumlimits_ilambda_i J_i[mathbf{y}]$$



      But when checking my reference book I noticed the Theorem said (I modified and omitted parts to take what's most relevant to the current question):




      Suppose that $F$ has an extremum at $yin C^2[x_0, x_1]$ subject to the boundary conditions [...]. Then there exist two numbers $lambda_0, lambda_1$ not both zero such that $$frac{delta K}{delta y}=0$$
      Where $K=lambda_0 F-lambda_1 J$




      As the theorem says, this works when one wishes to find the extremum so my naïve assumption is probably wrong since the system I described only reaches the extremum of the functional when $mathbf{y}$ gets to the steady state (i.e. it approaches it asymptotically).



      Is there a way to satisfy the constraint continuously throughout the time evolution of the system despite $F$ not being stationary?



      I understand this may be more involved than what an answer in the site may allow so if you know of any good textbook where I could find it I would also be very grateful.







      pde calculus-of-variations lagrange-multiplier euler-lagrange-equation variational-analysis






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 21 at 16:53







      Salvador Villarreal

















      asked Jan 18 at 18:26









      Salvador VillarrealSalvador Villarreal

      1107




      1107






















          0






          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3078598%2fguaranteeing-isoperimetry-constraint-for-non-extremal-functional-in-pde%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          0






          active

          oldest

          votes








          0






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3078598%2fguaranteeing-isoperimetry-constraint-for-non-extremal-functional-in-pde%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Mario Kart Wii

          What does “Dominus providebit” mean?

          Antonio Litta Visconti Arese