Can any one help me how toI find the average value of the function f(x)=1/x^3 , 1/3≤x≤1/2 [closed]
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Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.
calculus algebra-precalculus multivariable-calculus vector-analysis
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closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55
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Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.
calculus algebra-precalculus multivariable-calculus vector-analysis
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closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
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Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.
calculus algebra-precalculus multivariable-calculus vector-analysis
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Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.
calculus algebra-precalculus multivariable-calculus vector-analysis
calculus algebra-precalculus multivariable-calculus vector-analysis
edited Jan 12 at 9:26
Mauro ALLEGRANZA
65.2k448112
65.2k448112
asked Jan 11 at 21:14
Natasha KhouryNatasha Khoury
61
61
closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase
If this question can be reworded to fit the rules in the help center, please edit the question.
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2 Answers
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hint: Average value of a funtion $f$ on interval $[a,b]$ is given by
$$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$
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Hint
$$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
hint: Average value of a funtion $f$ on interval $[a,b]$ is given by
$$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$
$endgroup$
add a comment |
$begingroup$
hint: Average value of a funtion $f$ on interval $[a,b]$ is given by
$$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$
$endgroup$
add a comment |
$begingroup$
hint: Average value of a funtion $f$ on interval $[a,b]$ is given by
$$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$
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hint: Average value of a funtion $f$ on interval $[a,b]$ is given by
$$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$
answered Jan 11 at 21:19
kelalakakelalaka
3261212
3261212
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Hint
$$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$
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add a comment |
$begingroup$
Hint
$$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$
$endgroup$
add a comment |
$begingroup$
Hint
$$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$
$endgroup$
Hint
$$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$
answered Jan 12 at 9:29
Mostafa AyazMostafa Ayaz
15.3k3939
15.3k3939
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