Can any one help me how toI find the average value of the function f(x)=1/x^3 , 1/3≤x≤1/2 [closed]












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Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.










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closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55


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    Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.










    share|cite|improve this question











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    closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase

    If this question can be reworded to fit the rules in the help center, please edit the question.



















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      Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.










      share|cite|improve this question











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      Please help me how can I find the average value of the function $f(x)=1/x^3$, over the domain $1/3≤x≤1/2$.







      calculus algebra-precalculus multivariable-calculus vector-analysis






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      edited Jan 12 at 9:26









      Mauro ALLEGRANZA

      65.2k448112




      65.2k448112










      asked Jan 11 at 21:14









      Natasha KhouryNatasha Khoury

      61




      61




      closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase

      If this question can be reworded to fit the rules in the help center, please edit the question.







      closed as off-topic by zipirovich, Saad, RRL, Shailesh, rtybase Jan 12 at 10:55


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – zipirovich, Saad, RRL, Shailesh, rtybase

      If this question can be reworded to fit the rules in the help center, please edit the question.






















          2 Answers
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          $begingroup$

          hint: Average value of a funtion $f$ on interval $[a,b]$ is given by



          $$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$






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            0












            $begingroup$

            Hint



            $$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$






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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              1












              $begingroup$

              hint: Average value of a funtion $f$ on interval $[a,b]$ is given by



              $$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$






              share|cite|improve this answer









              $endgroup$


















                1












                $begingroup$

                hint: Average value of a funtion $f$ on interval $[a,b]$ is given by



                $$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$






                share|cite|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  hint: Average value of a funtion $f$ on interval $[a,b]$ is given by



                  $$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$






                  share|cite|improve this answer









                  $endgroup$



                  hint: Average value of a funtion $f$ on interval $[a,b]$ is given by



                  $$f_{avg} = frac{1}{b-a} int_a^b f(x)dx$$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 11 at 21:19









                  kelalakakelalaka

                  3261212




                  3261212























                      0












                      $begingroup$

                      Hint



                      $$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$






                      share|cite|improve this answer









                      $endgroup$


















                        0












                        $begingroup$

                        Hint



                        $$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$






                        share|cite|improve this answer









                        $endgroup$
















                          0












                          0








                          0





                          $begingroup$

                          Hint



                          $$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$






                          share|cite|improve this answer









                          $endgroup$



                          Hint



                          $$text{Average}={1over {1over 2}-{1over 3}}int_{{1over 3}}^{1over 2}{1over x^3}dx$$







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Jan 12 at 9:29









                          Mostafa AyazMostafa Ayaz

                          15.3k3939




                          15.3k3939















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