Sum of the degrees of second neighbours of a vertex in a graph












1












$begingroup$


The question is: "Using only matrix formalism find the vector $pmb{v}$ whose element $i$ is the sum of the degrees of vertex's $i$ second neighbours".



My attempt:



Let $A$ be the adjacent matrix of the graph. The vector $pmb{k}$ whose elements are the degree of the vertices is $pmb{k}=Acdotpmb{1}$ where $pmb{1}$ is a column vector off all ones. Now, to find the sum of the degrees of the second neighbours I need a proper matrix to rearrange and sum the elements of the vector $pmb{k}$. For instance if I want instead the sum of the degrees of the first neighbours the proper matrix is the adjacent matrix. Indeed $Acdotpmb{k}$ is the vector whose element $i$ is the sum of the degrees of vertex $i$-th.



I tried to use a matrix similar to: $A^2-diag(pmb{k})$, but, of course, it will not work due to repetitions and loops.



Thanks










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  • $begingroup$
    Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
    $endgroup$
    – Mike
    Oct 4 '18 at 20:22


















1












$begingroup$


The question is: "Using only matrix formalism find the vector $pmb{v}$ whose element $i$ is the sum of the degrees of vertex's $i$ second neighbours".



My attempt:



Let $A$ be the adjacent matrix of the graph. The vector $pmb{k}$ whose elements are the degree of the vertices is $pmb{k}=Acdotpmb{1}$ where $pmb{1}$ is a column vector off all ones. Now, to find the sum of the degrees of the second neighbours I need a proper matrix to rearrange and sum the elements of the vector $pmb{k}$. For instance if I want instead the sum of the degrees of the first neighbours the proper matrix is the adjacent matrix. Indeed $Acdotpmb{k}$ is the vector whose element $i$ is the sum of the degrees of vertex $i$-th.



I tried to use a matrix similar to: $A^2-diag(pmb{k})$, but, of course, it will not work due to repetitions and loops.



Thanks










share|cite|improve this question











$endgroup$












  • $begingroup$
    Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
    $endgroup$
    – Mike
    Oct 4 '18 at 20:22
















1












1








1


1



$begingroup$


The question is: "Using only matrix formalism find the vector $pmb{v}$ whose element $i$ is the sum of the degrees of vertex's $i$ second neighbours".



My attempt:



Let $A$ be the adjacent matrix of the graph. The vector $pmb{k}$ whose elements are the degree of the vertices is $pmb{k}=Acdotpmb{1}$ where $pmb{1}$ is a column vector off all ones. Now, to find the sum of the degrees of the second neighbours I need a proper matrix to rearrange and sum the elements of the vector $pmb{k}$. For instance if I want instead the sum of the degrees of the first neighbours the proper matrix is the adjacent matrix. Indeed $Acdotpmb{k}$ is the vector whose element $i$ is the sum of the degrees of vertex $i$-th.



I tried to use a matrix similar to: $A^2-diag(pmb{k})$, but, of course, it will not work due to repetitions and loops.



Thanks










share|cite|improve this question











$endgroup$




The question is: "Using only matrix formalism find the vector $pmb{v}$ whose element $i$ is the sum of the degrees of vertex's $i$ second neighbours".



My attempt:



Let $A$ be the adjacent matrix of the graph. The vector $pmb{k}$ whose elements are the degree of the vertices is $pmb{k}=Acdotpmb{1}$ where $pmb{1}$ is a column vector off all ones. Now, to find the sum of the degrees of the second neighbours I need a proper matrix to rearrange and sum the elements of the vector $pmb{k}$. For instance if I want instead the sum of the degrees of the first neighbours the proper matrix is the adjacent matrix. Indeed $Acdotpmb{k}$ is the vector whose element $i$ is the sum of the degrees of vertex $i$-th.



I tried to use a matrix similar to: $A^2-diag(pmb{k})$, but, of course, it will not work due to repetitions and loops.



Thanks







graph-theory network adjacency-matrix






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share|cite|improve this question













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edited Jan 15 at 14:55









amWhy

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1










asked Oct 4 '18 at 11:06









AlexAlex

32319




32319












  • $begingroup$
    Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
    $endgroup$
    – Mike
    Oct 4 '18 at 20:22




















  • $begingroup$
    Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
    $endgroup$
    – Mike
    Oct 4 '18 at 20:22


















$begingroup$
Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
$endgroup$
– Mike
Oct 4 '18 at 20:22






$begingroup$
Well, $Apmb{k}$ counts the degree of each vertex, $A^2pmb{k}$ counts the sum of the degrees of the neighbours of each vertex, and something like $A^3pmb{k} - diag^2(A pmb{k})$ counts the sum of the degrees of the second neighbours of each vertex, the problem being caused by multiple counting due to cycles of length 3 or 4. What was the exact wording of the question?
$endgroup$
– Mike
Oct 4 '18 at 20:22












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