Calculus problem engineering
$begingroup$
You are working as a Junior Engineer for a small motor racing team. You have been given a proposed mathematical model to calculate the velocity (when t=0) of a car accelerating from rest in a straight line. The equation is:
$$v(t)=Aleft(1- e^frac{-5t}{tmax} right)$$
v(t) is the instantaneous velocity of the car (m/s)
t is the time in seconds
tmax is the time to reach the maximum speed in seconds
A is a constant.
t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)
- Identify the
● units of the coefficient A
● physical meaning of A
● velocity of the car at t = 0
● asymptote of this function as t → ∞?
calculus
$endgroup$
add a comment |
$begingroup$
You are working as a Junior Engineer for a small motor racing team. You have been given a proposed mathematical model to calculate the velocity (when t=0) of a car accelerating from rest in a straight line. The equation is:
$$v(t)=Aleft(1- e^frac{-5t}{tmax} right)$$
v(t) is the instantaneous velocity of the car (m/s)
t is the time in seconds
tmax is the time to reach the maximum speed in seconds
A is a constant.
t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)
- Identify the
● units of the coefficient A
● physical meaning of A
● velocity of the car at t = 0
● asymptote of this function as t → ∞?
calculus
$endgroup$
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
1
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14
add a comment |
$begingroup$
You are working as a Junior Engineer for a small motor racing team. You have been given a proposed mathematical model to calculate the velocity (when t=0) of a car accelerating from rest in a straight line. The equation is:
$$v(t)=Aleft(1- e^frac{-5t}{tmax} right)$$
v(t) is the instantaneous velocity of the car (m/s)
t is the time in seconds
tmax is the time to reach the maximum speed in seconds
A is a constant.
t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)
- Identify the
● units of the coefficient A
● physical meaning of A
● velocity of the car at t = 0
● asymptote of this function as t → ∞?
calculus
$endgroup$
You are working as a Junior Engineer for a small motor racing team. You have been given a proposed mathematical model to calculate the velocity (when t=0) of a car accelerating from rest in a straight line. The equation is:
$$v(t)=Aleft(1- e^frac{-5t}{tmax} right)$$
v(t) is the instantaneous velocity of the car (m/s)
t is the time in seconds
tmax is the time to reach the maximum speed in seconds
A is a constant.
t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)
- Identify the
● units of the coefficient A
● physical meaning of A
● velocity of the car at t = 0
● asymptote of this function as t → ∞?
calculus
calculus
edited Jan 15 at 16:55
Ernest Kucyłyma
asked Jan 15 at 16:43
Ernest KucyłymaErnest Kucyłyma
11
11
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
1
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14
add a comment |
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
1
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
1
1
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
A miles per hour is the upper limit of the velocity of the car.
How could you not know what v(0) is?
Notice v levels off at y = A.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3074629%2fcalculus-problem-engineering%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A miles per hour is the upper limit of the velocity of the car.
How could you not know what v(0) is?
Notice v levels off at y = A.
$endgroup$
add a comment |
$begingroup$
A miles per hour is the upper limit of the velocity of the car.
How could you not know what v(0) is?
Notice v levels off at y = A.
$endgroup$
add a comment |
$begingroup$
A miles per hour is the upper limit of the velocity of the car.
How could you not know what v(0) is?
Notice v levels off at y = A.
$endgroup$
A miles per hour is the upper limit of the velocity of the car.
How could you not know what v(0) is?
Notice v levels off at y = A.
answered Jan 16 at 2:31
William ElliotWilliam Elliot
8,0602720
8,0602720
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3074629%2fcalculus-problem-engineering%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Set aside that the maximum velocity is never actually reached, what is the question here?
$endgroup$
– maxmilgram
Jan 15 at 16:53
$begingroup$
what is the physical meaning of A
$endgroup$
– Ernest Kucyłyma
Jan 15 at 16:56
$begingroup$
Please update the original question. Also, what is the last line supposed to tell us?
$endgroup$
– maxmilgram
Jan 15 at 17:01
1
$begingroup$
What have you done so far? Please show more effort. Also this line "t(0-28 m/s) 1.9 (s) t(400m) 10.50 (s) tmax 7.1 (s)" is completely unclear. Furthermore as I said before the max velocity can not be reached. Please include all of these points in the original question.
$endgroup$
– maxmilgram
Jan 15 at 17:14