Probability of obtaining at most one negative value in $5$ trials
In an experiment, positive and negative values are equally likely to occur. What is the probability of obtaining at most one negative value in five trials?
$$P(text{obtaining at most one negative value in $5$ trials}) = ^5C_1 cdot left(frac{1}{2}right) cdot left(frac{1}{2}right)^4 = frac{5}{32}$$
But ans is $frac 6{32}$.
probability
edited yesterday
amWhy
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
add a comment |
In an experiment, positive and negative values are equally likely to occur. What is the probability of obtaining at most one negative value in five trials?
$$P(text{obtaining at most one negative value in $5$ trials}) = ^5C_1 cdot left(frac{1}{2}right) cdot left(frac{1}{2}right)^4 = frac{5}{32}$$
But ans is $frac 6{32}$.
probability
edited yesterday
amWhy
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
add a comment |
In an experiment, positive and negative values are equally likely to occur. What is the probability of obtaining at most one negative value in five trials?
$$P(text{obtaining at most one negative value in $5$ trials}) = ^5C_1 cdot left(frac{1}{2}right) cdot left(frac{1}{2}right)^4 = frac{5}{32}$$
But ans is $frac 6{32}$.
probability
edited yesterday
amWhy
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
In an experiment, positive and negative values are equally likely to occur. What is the probability of obtaining at most one negative value in five trials?
$$P(text{obtaining at most one negative value in $5$ trials}) = ^5C_1 cdot left(frac{1}{2}right) cdot left(frac{1}{2}right)^4 = frac{5}{32}$$
But ans is $frac 6{32}$.
probability
probability
edited yesterday
amWhy
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
edited yesterday
amWhy
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
edited yesterday
amWhy
192k28224439
edited yesterday
amWhy
192k28224439
edited yesterday
amWhy
192k28224439
192k28224439
asked Jul 6 '16 at 10:02
akash
7217
asked Jul 6 '16 at 10:02
akash
7217
asked Jul 6 '16 at 10:02
akash
7217
7217
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You calculated the probability of getting exactly one negative. It says "at most one", so you have to add in the probability of getting zero negatives, which is $1/32$.
(also, your $36$s should be $32$s)
answered Jul 6 '16 at 10:04
florence
11.5k12045
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1850759%2fprobability-of-obtaining-at-most-one-negative-value-in-5-trials%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You calculated the probability of getting exactly one negative. It says "at most one", so you have to add in the probability of getting zero negatives, which is $1/32$.
(also, your $36$s should be $32$s)
answered Jul 6 '16 at 10:04
florence
11.5k12045
add a comment |
You calculated the probability of getting exactly one negative. It says "at most one", so you have to add in the probability of getting zero negatives, which is $1/32$.
(also, your $36$s should be $32$s)
answered Jul 6 '16 at 10:04
florence
11.5k12045
add a comment |
You calculated the probability of getting exactly one negative. It says "at most one", so you have to add in the probability of getting zero negatives, which is $1/32$.
(also, your $36$s should be $32$s)
answered Jul 6 '16 at 10:04
florence
11.5k12045
You calculated the probability of getting exactly one negative. It says "at most one", so you have to add in the probability of getting zero negatives, which is $1/32$.
(also, your $36$s should be $32$s)
answered Jul 6 '16 at 10:04
florence
11.5k12045
answered Jul 6 '16 at 10:04
florence
11.5k12045
answered Jul 6 '16 at 10:04
florence
11.5k12045
answered Jul 6 '16 at 10:04
florence
11.5k12045
11.5k12045
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1850759%2fprobability-of-obtaining-at-most-one-negative-value-in-5-trials%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
