How exactly does character inflation work?












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$begingroup$


Let $A_4$ be the alternating group and let $V = {{(1), (12)(34), (13)(24), (14)(23)}}$ be a normal subgroup of $A_4$. Then $A_4/V simeq C_3$, so $A_4$ has $3$ one dimensional representations, which apparently, we can inflate/lift from the character table for $C_3$.



I don't really understand how this works? How do I relate the character values of $C_3$ to $A_4$? Do I need to define a homomorphism from $A_4$ to $C_3$?










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$endgroup$












  • $begingroup$
    Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
    $endgroup$
    – anomaly
    Jan 21 at 22:00
















0












$begingroup$


Let $A_4$ be the alternating group and let $V = {{(1), (12)(34), (13)(24), (14)(23)}}$ be a normal subgroup of $A_4$. Then $A_4/V simeq C_3$, so $A_4$ has $3$ one dimensional representations, which apparently, we can inflate/lift from the character table for $C_3$.



I don't really understand how this works? How do I relate the character values of $C_3$ to $A_4$? Do I need to define a homomorphism from $A_4$ to $C_3$?










share|cite|improve this question









$endgroup$












  • $begingroup$
    Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
    $endgroup$
    – anomaly
    Jan 21 at 22:00














0












0








0





$begingroup$


Let $A_4$ be the alternating group and let $V = {{(1), (12)(34), (13)(24), (14)(23)}}$ be a normal subgroup of $A_4$. Then $A_4/V simeq C_3$, so $A_4$ has $3$ one dimensional representations, which apparently, we can inflate/lift from the character table for $C_3$.



I don't really understand how this works? How do I relate the character values of $C_3$ to $A_4$? Do I need to define a homomorphism from $A_4$ to $C_3$?










share|cite|improve this question









$endgroup$




Let $A_4$ be the alternating group and let $V = {{(1), (12)(34), (13)(24), (14)(23)}}$ be a normal subgroup of $A_4$. Then $A_4/V simeq C_3$, so $A_4$ has $3$ one dimensional representations, which apparently, we can inflate/lift from the character table for $C_3$.



I don't really understand how this works? How do I relate the character values of $C_3$ to $A_4$? Do I need to define a homomorphism from $A_4$ to $C_3$?







abstract-algebra representation-theory characters






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asked Jan 21 at 21:37









the manthe man

772715




772715












  • $begingroup$
    Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
    $endgroup$
    – anomaly
    Jan 21 at 22:00


















  • $begingroup$
    Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
    $endgroup$
    – anomaly
    Jan 21 at 22:00
















$begingroup$
Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
$endgroup$
– anomaly
Jan 21 at 22:00




$begingroup$
Just look at the representation $A_4 to A_4 /V to GL(X)$ induced from a representation $A_4/V to GL(X)$.
$endgroup$
– anomaly
Jan 21 at 22:00










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