Probability under Uncertainity












0












$begingroup$


Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00


















0












$begingroup$


Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00
















0












0








0





$begingroup$


Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










share|cite|improve this question









$endgroup$




Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?







probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 12 at 17:28









HarshilHarshil

1034




1034












  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00




















  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00


















$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42




$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42












$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50




$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50












$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53




$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53












$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00






$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00












0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071148%2fprobability-under-uncertainity%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071148%2fprobability-under-uncertainity%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Mario Kart Wii

What does “Dominus providebit” mean?

The Binding of Isaac: Rebirth/Afterbirth