how to generate b-spline matlab code?
i was tryied to write b-spline matalab code.
function [B1] = bpsl2(a,b,n,x,l,h,x0,B,B1)
a=-5;b=5;
n=10;
x=-5:0.5:5;
l=1;
x0=a;
h=(b-a)/n;
t=1./h;
g=length(x);
B1=zeros(n+1,g);
for i=1:g
B=zeros(1,n+1);
for j=1:n+1
if x(i)>=x0 && x(i)<(x0+h)
B(j)=t*(x(i)-x0);
elseif x(i)>=(x0+h)&& x(i)<=(x0+2*h)
B(j)=t*((x0+2*h)-x(i));
else B(j)=0;
end
if j==1;
x0=x0;
else
x0=x0+h;
end
end
B1(:,i)=B';
end
it work for one x but when i want to use a vector of x gives me a matrix with zero value. any body can help e to solve this problem?
numerical-methods
New contributor
add a comment |
i was tryied to write b-spline matalab code.
function [B1] = bpsl2(a,b,n,x,l,h,x0,B,B1)
a=-5;b=5;
n=10;
x=-5:0.5:5;
l=1;
x0=a;
h=(b-a)/n;
t=1./h;
g=length(x);
B1=zeros(n+1,g);
for i=1:g
B=zeros(1,n+1);
for j=1:n+1
if x(i)>=x0 && x(i)<(x0+h)
B(j)=t*(x(i)-x0);
elseif x(i)>=(x0+h)&& x(i)<=(x0+2*h)
B(j)=t*((x0+2*h)-x(i));
else B(j)=0;
end
if j==1;
x0=x0;
else
x0=x0+h;
end
end
B1(:,i)=B';
end
it work for one x but when i want to use a vector of x gives me a matrix with zero value. any body can help e to solve this problem?
numerical-methods
New contributor
add a comment |
i was tryied to write b-spline matalab code.
function [B1] = bpsl2(a,b,n,x,l,h,x0,B,B1)
a=-5;b=5;
n=10;
x=-5:0.5:5;
l=1;
x0=a;
h=(b-a)/n;
t=1./h;
g=length(x);
B1=zeros(n+1,g);
for i=1:g
B=zeros(1,n+1);
for j=1:n+1
if x(i)>=x0 && x(i)<(x0+h)
B(j)=t*(x(i)-x0);
elseif x(i)>=(x0+h)&& x(i)<=(x0+2*h)
B(j)=t*((x0+2*h)-x(i));
else B(j)=0;
end
if j==1;
x0=x0;
else
x0=x0+h;
end
end
B1(:,i)=B';
end
it work for one x but when i want to use a vector of x gives me a matrix with zero value. any body can help e to solve this problem?
numerical-methods
New contributor
i was tryied to write b-spline matalab code.
function [B1] = bpsl2(a,b,n,x,l,h,x0,B,B1)
a=-5;b=5;
n=10;
x=-5:0.5:5;
l=1;
x0=a;
h=(b-a)/n;
t=1./h;
g=length(x);
B1=zeros(n+1,g);
for i=1:g
B=zeros(1,n+1);
for j=1:n+1
if x(i)>=x0 && x(i)<(x0+h)
B(j)=t*(x(i)-x0);
elseif x(i)>=(x0+h)&& x(i)<=(x0+2*h)
B(j)=t*((x0+2*h)-x(i));
else B(j)=0;
end
if j==1;
x0=x0;
else
x0=x0+h;
end
end
B1(:,i)=B';
end
it work for one x but when i want to use a vector of x gives me a matrix with zero value. any body can help e to solve this problem?
numerical-methods
numerical-methods
New contributor
New contributor
edited 18 hours ago
Bernard
118k639112
118k639112
New contributor
asked 19 hours ago
Nafis Ne1910
1
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