How do I show this equality using Plancherel's theorem in this paper?












0












$begingroup$


I refer to the paper written by T. Ozawa, K. M. Rogers, https://link.springer.com/article/10.1007/s11854-013-0031-0



I have 2 questions



In the proof of lemma 2.1,
first,



enter image description here



I really don't know how Plancherel's theorem is worked.



And second,



enter image description here



Why are blue line necessary?



I have spent lots of days.



The most plausible idea(only my opinion) is, the $D^{-s}e^{-itD^a}f(x)$ is the Fourier transform of $int_{mathbb{S}^{d-1}} r^{frac{d-a-s}{a} hat{f}(r^{1/a}omega})e^{ir^{1/a}omegacdot x}domega$ with respect to $t$ because of $e^{-itr}$.



But I think that is not true since $t$ and $r$ are defined $mathbb{R}$ and $mathbb{R}^+$, respectively.



Please, I am begging you. And I apologize about my poor English skill.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just write to the authors. They may remember what they wrote.
    $endgroup$
    – ablmf
    Jan 12 at 19:08
















0












$begingroup$


I refer to the paper written by T. Ozawa, K. M. Rogers, https://link.springer.com/article/10.1007/s11854-013-0031-0



I have 2 questions



In the proof of lemma 2.1,
first,



enter image description here



I really don't know how Plancherel's theorem is worked.



And second,



enter image description here



Why are blue line necessary?



I have spent lots of days.



The most plausible idea(only my opinion) is, the $D^{-s}e^{-itD^a}f(x)$ is the Fourier transform of $int_{mathbb{S}^{d-1}} r^{frac{d-a-s}{a} hat{f}(r^{1/a}omega})e^{ir^{1/a}omegacdot x}domega$ with respect to $t$ because of $e^{-itr}$.



But I think that is not true since $t$ and $r$ are defined $mathbb{R}$ and $mathbb{R}^+$, respectively.



Please, I am begging you. And I apologize about my poor English skill.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just write to the authors. They may remember what they wrote.
    $endgroup$
    – ablmf
    Jan 12 at 19:08














0












0








0





$begingroup$


I refer to the paper written by T. Ozawa, K. M. Rogers, https://link.springer.com/article/10.1007/s11854-013-0031-0



I have 2 questions



In the proof of lemma 2.1,
first,



enter image description here



I really don't know how Plancherel's theorem is worked.



And second,



enter image description here



Why are blue line necessary?



I have spent lots of days.



The most plausible idea(only my opinion) is, the $D^{-s}e^{-itD^a}f(x)$ is the Fourier transform of $int_{mathbb{S}^{d-1}} r^{frac{d-a-s}{a} hat{f}(r^{1/a}omega})e^{ir^{1/a}omegacdot x}domega$ with respect to $t$ because of $e^{-itr}$.



But I think that is not true since $t$ and $r$ are defined $mathbb{R}$ and $mathbb{R}^+$, respectively.



Please, I am begging you. And I apologize about my poor English skill.










share|cite|improve this question











$endgroup$




I refer to the paper written by T. Ozawa, K. M. Rogers, https://link.springer.com/article/10.1007/s11854-013-0031-0



I have 2 questions



In the proof of lemma 2.1,
first,



enter image description here



I really don't know how Plancherel's theorem is worked.



And second,



enter image description here



Why are blue line necessary?



I have spent lots of days.



The most plausible idea(only my opinion) is, the $D^{-s}e^{-itD^a}f(x)$ is the Fourier transform of $int_{mathbb{S}^{d-1}} r^{frac{d-a-s}{a} hat{f}(r^{1/a}omega})e^{ir^{1/a}omegacdot x}domega$ with respect to $t$ because of $e^{-itr}$.



But I think that is not true since $t$ and $r$ are defined $mathbb{R}$ and $mathbb{R}^+$, respectively.



Please, I am begging you. And I apologize about my poor English skill.







fourier-transform harmonic-analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 12 at 19:18







Idkwhat

















asked Jan 12 at 19:00









IdkwhatIdkwhat

236




236












  • $begingroup$
    Just write to the authors. They may remember what they wrote.
    $endgroup$
    – ablmf
    Jan 12 at 19:08


















  • $begingroup$
    Just write to the authors. They may remember what they wrote.
    $endgroup$
    – ablmf
    Jan 12 at 19:08
















$begingroup$
Just write to the authors. They may remember what they wrote.
$endgroup$
– ablmf
Jan 12 at 19:08




$begingroup$
Just write to the authors. They may remember what they wrote.
$endgroup$
– ablmf
Jan 12 at 19:08










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