Get one of the solutions as Variable Value in Maxima












0












$begingroup$


I want to create random variables for a way more complex program to read.



Some example code is:



a:random(20);
b:random(100);
[c]:solve(a = 2 * x + b, [x]);
tex(a);
tex(b);
tex(c);


however, the last line prints x=5 instead of 5.



is it somehow possible to get the value of the solutin in maxima?










share|cite|improve this question









$endgroup$

















    0












    $begingroup$


    I want to create random variables for a way more complex program to read.



    Some example code is:



    a:random(20);
    b:random(100);
    [c]:solve(a = 2 * x + b, [x]);
    tex(a);
    tex(b);
    tex(c);


    however, the last line prints x=5 instead of 5.



    is it somehow possible to get the value of the solutin in maxima?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I want to create random variables for a way more complex program to read.



      Some example code is:



      a:random(20);
      b:random(100);
      [c]:solve(a = 2 * x + b, [x]);
      tex(a);
      tex(b);
      tex(c);


      however, the last line prints x=5 instead of 5.



      is it somehow possible to get the value of the solutin in maxima?










      share|cite|improve this question









      $endgroup$




      I want to create random variables for a way more complex program to read.



      Some example code is:



      a:random(20);
      b:random(100);
      [c]:solve(a = 2 * x + b, [x]);
      tex(a);
      tex(b);
      tex(c);


      however, the last line prints x=5 instead of 5.



      is it somehow possible to get the value of the solutin in maxima?







      computer-algebra-systems maxima-software






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 12 at 17:57









      TobiTobi

      1063




      1063






















          1 Answer
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          0












          $begingroup$

          The explanation is that solve returns a list of equations such as x = 5, not just values such as 5.



          Of course the values are the right-hand sides of the equations. So you can do e.g.:



          [c] : map(rhs,solve(a = 2 * x + b, [x]));





          share|cite|improve this answer









          $endgroup$













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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

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            active

            oldest

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            0












            $begingroup$

            The explanation is that solve returns a list of equations such as x = 5, not just values such as 5.



            Of course the values are the right-hand sides of the equations. So you can do e.g.:



            [c] : map(rhs,solve(a = 2 * x + b, [x]));





            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              The explanation is that solve returns a list of equations such as x = 5, not just values such as 5.



              Of course the values are the right-hand sides of the equations. So you can do e.g.:



              [c] : map(rhs,solve(a = 2 * x + b, [x]));





              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                The explanation is that solve returns a list of equations such as x = 5, not just values such as 5.



                Of course the values are the right-hand sides of the equations. So you can do e.g.:



                [c] : map(rhs,solve(a = 2 * x + b, [x]));





                share|cite|improve this answer









                $endgroup$



                The explanation is that solve returns a list of equations such as x = 5, not just values such as 5.



                Of course the values are the right-hand sides of the equations. So you can do e.g.:



                [c] : map(rhs,solve(a = 2 * x + b, [x]));






                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 24 at 20:43









                Ricardo BuringRicardo Buring

                1,3731234




                1,3731234






























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