Solving Normal Distribution Problem
$begingroup$
I'm trying to solve (i), I keep on finding that the answer to the question is 0.72. Nonetheless correct answer is shown to be 0.288.
My workings:
$$P(frac{-0.5}{1.4}<Z<frac{0.5}{1.4}) = P(-0.357<Z<0.357)$$
Based on the Standard Normal distribution table (Right tail only) we have: $$0.36 = 0.1406$$
I then proceed to get the area under both tails:
$$ 0.1406 * 2 = 0.28$$
and substract that value from 1
in order to get the area in the middle ( between 0 and 1 ):
$$ 1-0.28 = 0.72$$
Could someone possible tell me why we should substract the value from 1 at the end?
Thank you very much in advance
normal-distribution
asked Jan 23 at 11:04
FozoroFozoro
1265
$endgroup$
add a comment |
$begingroup$
I'm trying to solve (i), I keep on finding that the answer to the question is 0.72. Nonetheless correct answer is shown to be 0.288.
My workings:
$$P(frac{-0.5}{1.4}<Z<frac{0.5}{1.4}) = P(-0.357<Z<0.357)$$
Based on the Standard Normal distribution table (Right tail only) we have: $$0.36 = 0.1406$$
I then proceed to get the area under both tails:
$$ 0.1406 * 2 = 0.28$$
and substract that value from 1
in order to get the area in the middle ( between 0 and 1 ):
$$ 1-0.28 = 0.72$$
Could someone possible tell me why we should substract the value from 1 at the end?
Thank you very much in advance
normal-distribution
asked Jan 23 at 11:04
FozoroFozoro
1265
$endgroup$
add a comment |
$begingroup$
I'm trying to solve (i), I keep on finding that the answer to the question is 0.72. Nonetheless correct answer is shown to be 0.288.
My workings:
$$P(frac{-0.5}{1.4}<Z<frac{0.5}{1.4}) = P(-0.357<Z<0.357)$$
Based on the Standard Normal distribution table (Right tail only) we have: $$0.36 = 0.1406$$
I then proceed to get the area under both tails:
$$ 0.1406 * 2 = 0.28$$
and substract that value from 1
in order to get the area in the middle ( between 0 and 1 ):
$$ 1-0.28 = 0.72$$
Could someone possible tell me why we should substract the value from 1 at the end?
Thank you very much in advance
normal-distribution
asked Jan 23 at 11:04
FozoroFozoro
1265
$endgroup$
I'm trying to solve (i), I keep on finding that the answer to the question is 0.72. Nonetheless correct answer is shown to be 0.288.
My workings:
$$P(frac{-0.5}{1.4}<Z<frac{0.5}{1.4}) = P(-0.357<Z<0.357)$$
Based on the Standard Normal distribution table (Right tail only) we have: $$0.36 = 0.1406$$
I then proceed to get the area under both tails:
$$ 0.1406 * 2 = 0.28$$
and substract that value from 1
in order to get the area in the middle ( between 0 and 1 ):
$$ 1-0.28 = 0.72$$
Could someone possible tell me why we should substract the value from 1 at the end?
Thank you very much in advance
normal-distribution
normal-distribution
asked Jan 23 at 11:04
FozoroFozoro
1265
asked Jan 23 at 11:04
FozoroFozoro
1265
asked Jan 23 at 11:04
FozoroFozoro
1265
asked Jan 23 at 11:04
FozoroFozoro
1265
asked Jan 23 at 11:04
FozoroFozoro
1265
1265
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
I suspect that based on the table you find something like:$$P(Zgeq0.36)approx0.1406$$Taking that twice gives: $$P(Zleq-0.36text{ or }Zgeq0.36)=P(Zleq-0.36)+P(Zgeq0.36)=2P(Zgeq0.36)approx0.28$$Then:$$P(-0.36<Z<0.36)=1-P(Zleq-0.36text{ or }Zgeq0.36)approx0.72$$
answered Jan 23 at 11:15
drhabdrhab
102k545136
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3084330%2fsolving-normal-distribution-problem%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I suspect that based on the table you find something like:$$P(Zgeq0.36)approx0.1406$$Taking that twice gives: $$P(Zleq-0.36text{ or }Zgeq0.36)=P(Zleq-0.36)+P(Zgeq0.36)=2P(Zgeq0.36)approx0.28$$Then:$$P(-0.36<Z<0.36)=1-P(Zleq-0.36text{ or }Zgeq0.36)approx0.72$$
answered Jan 23 at 11:15
drhabdrhab
102k545136
$endgroup$
add a comment |
$begingroup$
I suspect that based on the table you find something like:$$P(Zgeq0.36)approx0.1406$$Taking that twice gives: $$P(Zleq-0.36text{ or }Zgeq0.36)=P(Zleq-0.36)+P(Zgeq0.36)=2P(Zgeq0.36)approx0.28$$Then:$$P(-0.36<Z<0.36)=1-P(Zleq-0.36text{ or }Zgeq0.36)approx0.72$$
answered Jan 23 at 11:15
drhabdrhab
102k545136
$endgroup$
add a comment |
$begingroup$
I suspect that based on the table you find something like:$$P(Zgeq0.36)approx0.1406$$Taking that twice gives: $$P(Zleq-0.36text{ or }Zgeq0.36)=P(Zleq-0.36)+P(Zgeq0.36)=2P(Zgeq0.36)approx0.28$$Then:$$P(-0.36<Z<0.36)=1-P(Zleq-0.36text{ or }Zgeq0.36)approx0.72$$
answered Jan 23 at 11:15
drhabdrhab
102k545136
$endgroup$
I suspect that based on the table you find something like:$$P(Zgeq0.36)approx0.1406$$Taking that twice gives: $$P(Zleq-0.36text{ or }Zgeq0.36)=P(Zleq-0.36)+P(Zgeq0.36)=2P(Zgeq0.36)approx0.28$$Then:$$P(-0.36<Z<0.36)=1-P(Zleq-0.36text{ or }Zgeq0.36)approx0.72$$
answered Jan 23 at 11:15
drhabdrhab
102k545136
answered Jan 23 at 11:15
drhabdrhab
102k545136
answered Jan 23 at 11:15
drhabdrhab
102k545136
answered Jan 23 at 11:15
drhabdrhab
102k545136
102k545136
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3084330%2fsolving-normal-distribution-problem%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
