How to join many columns of data in array?












4












$begingroup$


I have large number of columns of data. How to put in single matrix?



For example, with test data of 1 x 3 matrixs



test[1] = {1, 1, 1}

test[2] = {2, 2, 2}

test[3] = {3, 3, 3}

test[4] = {4, 4, 4}


I use



Array[test, 4, 1, Join]


and get 1 x 12 matrix



{1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4}


I want to get 4 x 3 matrix



{{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





list-manipulation matrix array







share|improve this question









$endgroup$












  • $begingroup$
    Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
    $endgroup$
    – Hitesh Gaur
    Jan 23 at 19:11
















4












$begingroup$


I have large number of columns of data. How to put in single matrix?



For example, with test data of 1 x 3 matrixs



test[1] = {1, 1, 1}

test[2] = {2, 2, 2}

test[3] = {3, 3, 3}

test[4] = {4, 4, 4}


I use



Array[test, 4, 1, Join]


and get 1 x 12 matrix



{1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4}


I want to get 4 x 3 matrix



{{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





list-manipulation matrix array







share|improve this question









$endgroup$












  • $begingroup$
    Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
    $endgroup$
    – Hitesh Gaur
    Jan 23 at 19:11














4












4








4


1



$begingroup$


I have large number of columns of data. How to put in single matrix?



For example, with test data of 1 x 3 matrixs



test[1] = {1, 1, 1}

test[2] = {2, 2, 2}

test[3] = {3, 3, 3}

test[4] = {4, 4, 4}


I use



Array[test, 4, 1, Join]


and get 1 x 12 matrix



{1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4}


I want to get 4 x 3 matrix



{{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





list-manipulation matrix array







share|improve this question









$endgroup$




I have large number of columns of data. How to put in single matrix?



For example, with test data of 1 x 3 matrixs



test[1] = {1, 1, 1}

test[2] = {2, 2, 2}

test[3] = {3, 3, 3}

test[4] = {4, 4, 4}


I use



Array[test, 4, 1, Join]


and get 1 x 12 matrix



{1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4}


I want to get 4 x 3 matrix



{{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





list-manipulation matrix array




list-manipulation matrix array






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 23 at 11:11









Nigel1Nigel1

1976




1976












  • $begingroup$
    Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
    $endgroup$
    – Hitesh Gaur
    Jan 23 at 19:11


















  • $begingroup$
    Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
    $endgroup$
    – Hitesh Gaur
    Jan 23 at 19:11
















$begingroup$
Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
$endgroup$
– Hitesh Gaur
Jan 23 at 19:11




$begingroup$
Don't you already have a 4 x 3 matrix or let's say 2-dimensional array?
$endgroup$
– Hitesh Gaur
Jan 23 at 19:11










5 Answers
5






active

oldest

votes


















7












$begingroup$

You can try creating an Array and then Transposing:



In[14]:= Transpose @ Array[test, 4]



Out[14]= {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





share|improve this answer









$endgroup$





















    6












    $begingroup$

    num = 4;
    
test[#] & /@ Range[num] // Transpose



    {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}







    share|improve this answer









    $endgroup$









    • 4




      $begingroup$
      test /@ Range... will do too.
      $endgroup$
      – Kuba♦
      Jan 23 at 11:38



















    5












    $begingroup$

    Array[test, 4, 1, Transpose[{##}] &]



    {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}




    also



    Array[test, 4, 1, Flatten[{##}, {2}] &]
    
Array[test, 4, 1, Thread[{##}] &]





    share|improve this answer











    $endgroup$





















      3












      $begingroup$

      Another possibility:



      Array[List /@ test[#] &, 4, 1, Join[##, 2] &]





      share|improve this answer









      $endgroup$





















        -1












        $begingroup$

        I hope this helps in creating the array you're asking about.



        Var matrix = new int [4, 3];   
        
     //this creates an array (of arrays) with 4 rows, 3 columns in each row
        

        
IF THE VALUES ARE KNOWN (AS IN YOUR CASE) = 
        
Var matrix = new int [4, 3];
        
{
        
    {1, 1, 1}
        
    {2, 2, 2}
        
    {3, 3, 3}
        
    {4, 4, 4}
        
}





        share|improve this answer









        $endgroup$













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          5 Answers
          5






          active

          oldest

          votes








          5 Answers
          5






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          7












          $begingroup$

          You can try creating an Array and then Transposing:



          In[14]:= Transpose @ Array[test, 4]
          

          
Out[14]= {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





          share|improve this answer









          $endgroup$


















            7












            $begingroup$

            You can try creating an Array and then Transposing:



            In[14]:= Transpose @ Array[test, 4]
            

            
Out[14]= {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





            share|improve this answer









            $endgroup$
















              7












              7








              7





              $begingroup$

              You can try creating an Array and then Transposing:



              In[14]:= Transpose @ Array[test, 4]
              

              
Out[14]= {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}





              share|improve this answer









              $endgroup$



              You can try creating an Array and then Transposing:



              In[14]:= Transpose @ Array[test, 4]
              

              
Out[14]= {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Jan 23 at 11:17









              rafalcrafalc

              697212




              697212























                  6












                  $begingroup$

                  num = 4;
                  
test[#] & /@ Range[num] // Transpose



                  {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}







                  share|improve this answer









                  $endgroup$









                  • 4




                    $begingroup$
                    test /@ Range... will do too.
                    $endgroup$
                    – Kuba♦
                    Jan 23 at 11:38
















                  6












                  $begingroup$

                  num = 4;
                  
test[#] & /@ Range[num] // Transpose



                  {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}







                  share|improve this answer









                  $endgroup$









                  • 4




                    $begingroup$
                    test /@ Range... will do too.
                    $endgroup$
                    – Kuba♦
                    Jan 23 at 11:38














                  6












                  6








                  6





                  $begingroup$

                  num = 4;
                  
test[#] & /@ Range[num] // Transpose



                  {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}







                  share|improve this answer









                  $endgroup$



                  num = 4;
                  
test[#] & /@ Range[num] // Transpose



                  {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 23 at 11:22









                  JerryJerry

                  1,440212




                  1,440212








                  • 4




                    $begingroup$
                    test /@ Range... will do too.
                    $endgroup$
                    – Kuba♦
                    Jan 23 at 11:38














                  • 4




                    $begingroup$
                    test /@ Range... will do too.
                    $endgroup$
                    – Kuba♦
                    Jan 23 at 11:38








                  4




                  4




                  $begingroup$
                  test /@ Range... will do too.
                  $endgroup$
                  – Kuba♦
                  Jan 23 at 11:38




                  $begingroup$
                  test /@ Range... will do too.
                  $endgroup$
                  – Kuba♦
                  Jan 23 at 11:38











                  5












                  $begingroup$

                  Array[test, 4, 1, Transpose[{##}] &]



                  {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}




                  also



                  Array[test, 4, 1, Flatten[{##}, {2}] &]
                  
Array[test, 4, 1, Thread[{##}] &]





                  share|improve this answer











                  $endgroup$


















                    5












                    $begingroup$

                    Array[test, 4, 1, Transpose[{##}] &]



                    {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}




                    also



                    Array[test, 4, 1, Flatten[{##}, {2}] &]
                    
Array[test, 4, 1, Thread[{##}] &]





                    share|improve this answer











                    $endgroup$
















                      5












                      5








                      5





                      $begingroup$

                      Array[test, 4, 1, Transpose[{##}] &]



                      {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}




                      also



                      Array[test, 4, 1, Flatten[{##}, {2}] &]
                      
Array[test, 4, 1, Thread[{##}] &]





                      share|improve this answer











                      $endgroup$



                      Array[test, 4, 1, Transpose[{##}] &]



                      {{1, 2, 3, 4}, {1, 2, 3, 4}, {1, 2, 3, 4}}




                      also



                      Array[test, 4, 1, Flatten[{##}, {2}] &]
                      
Array[test, 4, 1, Thread[{##}] &]






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited Jan 23 at 11:34

























                      answered Jan 23 at 11:28









                      kglrkglr

                      186k10203422




                      186k10203422























                          3












                          $begingroup$

                          Another possibility:



                          Array[List /@ test[#] &, 4, 1, Join[##, 2] &]





                          share|improve this answer









                          $endgroup$


















                            3












                            $begingroup$

                            Another possibility:



                            Array[List /@ test[#] &, 4, 1, Join[##, 2] &]





                            share|improve this answer









                            $endgroup$
















                              3












                              3








                              3





                              $begingroup$

                              Another possibility:



                              Array[List /@ test[#] &, 4, 1, Join[##, 2] &]





                              share|improve this answer









                              $endgroup$



                              Another possibility:



                              Array[List /@ test[#] &, 4, 1, Join[##, 2] &]






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Jan 23 at 11:24









                              Henrik SchumacherHenrik Schumacher

                              55.3k576154




                              55.3k576154























                                  -1












                                  $begingroup$

                                  I hope this helps in creating the array you're asking about.



                                  Var matrix = new int [4, 3];   
                                  
     //this creates an array (of arrays) with 4 rows, 3 columns in each row
                                  

                                  
IF THE VALUES ARE KNOWN (AS IN YOUR CASE) = 
                                  
Var matrix = new int [4, 3];
                                  
{
                                  
    {1, 1, 1}
                                  
    {2, 2, 2}
                                  
    {3, 3, 3}
                                  
    {4, 4, 4}
                                  
}





                                  share|improve this answer









                                  $endgroup$


















                                    -1












                                    $begingroup$

                                    I hope this helps in creating the array you're asking about.



                                    Var matrix = new int [4, 3];   
                                    
     //this creates an array (of arrays) with 4 rows, 3 columns in each row
                                    

                                    
IF THE VALUES ARE KNOWN (AS IN YOUR CASE) = 
                                    
Var matrix = new int [4, 3];
                                    
{
                                    
    {1, 1, 1}
                                    
    {2, 2, 2}
                                    
    {3, 3, 3}
                                    
    {4, 4, 4}
                                    
}





                                    share|improve this answer









                                    $endgroup$
















                                      -1












                                      -1








                                      -1





                                      $begingroup$

                                      I hope this helps in creating the array you're asking about.



                                      Var matrix = new int [4, 3];   
                                      
     //this creates an array (of arrays) with 4 rows, 3 columns in each row
                                      

                                      
IF THE VALUES ARE KNOWN (AS IN YOUR CASE) = 
                                      
Var matrix = new int [4, 3];
                                      
{
                                      
    {1, 1, 1}
                                      
    {2, 2, 2}
                                      
    {3, 3, 3}
                                      
    {4, 4, 4}
                                      
}





                                      share|improve this answer









                                      $endgroup$



                                      I hope this helps in creating the array you're asking about.



                                      Var matrix = new int [4, 3];   
                                      
     //this creates an array (of arrays) with 4 rows, 3 columns in each row
                                      

                                      
IF THE VALUES ARE KNOWN (AS IN YOUR CASE) = 
                                      
Var matrix = new int [4, 3];
                                      
{
                                      
    {1, 1, 1}
                                      
    {2, 2, 2}
                                      
    {3, 3, 3}
                                      
    {4, 4, 4}
                                      
}






                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered Jan 23 at 17:22









                                      LocoEse74LocoEse74

                                      1




                                      1






























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