Complex version of the Fermat last problem












8












$begingroup$


A complex integer is a complex number $x=m+ni$ where $m,nin mathbb{Z}$.




Are there complex integers $x,y,z$ with $x^3+y^3=z^3$?











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$endgroup$








  • 2




    $begingroup$
    Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
    $endgroup$
    – postmortes
    Jan 15 at 7:46






  • 3




    $begingroup$
    These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
    $endgroup$
    – A. Pongrácz
    Jan 15 at 7:50






  • 1




    $begingroup$
    See also mathoverflow.net/questions/90972/…
    $endgroup$
    – Watson
    Jan 15 at 8:18






  • 1




    $begingroup$
    See also this MSE-question.
    $endgroup$
    – Dietrich Burde
    Jan 15 at 9:43
















8












$begingroup$


A complex integer is a complex number $x=m+ni$ where $m,nin mathbb{Z}$.




Are there complex integers $x,y,z$ with $x^3+y^3=z^3$?











share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
    $endgroup$
    – postmortes
    Jan 15 at 7:46






  • 3




    $begingroup$
    These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
    $endgroup$
    – A. Pongrácz
    Jan 15 at 7:50






  • 1




    $begingroup$
    See also mathoverflow.net/questions/90972/…
    $endgroup$
    – Watson
    Jan 15 at 8:18






  • 1




    $begingroup$
    See also this MSE-question.
    $endgroup$
    – Dietrich Burde
    Jan 15 at 9:43














8












8








8


4



$begingroup$


A complex integer is a complex number $x=m+ni$ where $m,nin mathbb{Z}$.




Are there complex integers $x,y,z$ with $x^3+y^3=z^3$?











share|cite|improve this question











$endgroup$




A complex integer is a complex number $x=m+ni$ where $m,nin mathbb{Z}$.




Are there complex integers $x,y,z$ with $x^3+y^3=z^3$?








number-theory complex-numbers






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 15 at 7:51







Ali Taghavi

















asked Jan 15 at 7:34









Ali TaghaviAli Taghavi

235329




235329








  • 2




    $begingroup$
    Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
    $endgroup$
    – postmortes
    Jan 15 at 7:46






  • 3




    $begingroup$
    These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
    $endgroup$
    – A. Pongrácz
    Jan 15 at 7:50






  • 1




    $begingroup$
    See also mathoverflow.net/questions/90972/…
    $endgroup$
    – Watson
    Jan 15 at 8:18






  • 1




    $begingroup$
    See also this MSE-question.
    $endgroup$
    – Dietrich Burde
    Jan 15 at 9:43














  • 2




    $begingroup$
    Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
    $endgroup$
    – postmortes
    Jan 15 at 7:46






  • 3




    $begingroup$
    These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
    $endgroup$
    – A. Pongrácz
    Jan 15 at 7:50






  • 1




    $begingroup$
    See also mathoverflow.net/questions/90972/…
    $endgroup$
    – Watson
    Jan 15 at 8:18






  • 1




    $begingroup$
    See also this MSE-question.
    $endgroup$
    – Dietrich Burde
    Jan 15 at 9:43








2




2




$begingroup$
Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
$endgroup$
– postmortes
Jan 15 at 7:46




$begingroup$
Can you provide some context? What have you tried (expanding the equation out with complex numbers and seeing what the real and complex parts must satisfy, for example), and what sparked this interest? Questions with context and background tend to attract better answers.
$endgroup$
– postmortes
Jan 15 at 7:46




3




3




$begingroup$
These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
$endgroup$
– A. Pongrácz
Jan 15 at 7:50




$begingroup$
These are called Gaussian integers, they form a unique factorization domain. It could be helpful.
$endgroup$
– A. Pongrácz
Jan 15 at 7:50




1




1




$begingroup$
See also mathoverflow.net/questions/90972/…
$endgroup$
– Watson
Jan 15 at 8:18




$begingroup$
See also mathoverflow.net/questions/90972/…
$endgroup$
– Watson
Jan 15 at 8:18




1




1




$begingroup$
See also this MSE-question.
$endgroup$
– Dietrich Burde
Jan 15 at 9:43




$begingroup$
See also this MSE-question.
$endgroup$
– Dietrich Burde
Jan 15 at 9:43










1 Answer
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$begingroup$

Lampakis 2007 provided a new proof there are no $xyzne 0$ solutions. It runs to several pages. Lampakis notes Feuter 1913 provided the original proof, but I couldn't find an online link to his reference, R. Feuter, Sitzungsber. Akad. Wiss. Heidelberg (Math.), 4, A, 1913 No. 25.






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  • $begingroup$
    Thank you very much for your answer.
    $endgroup$
    – Ali Taghavi
    Jan 16 at 20:58











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1 Answer
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1 Answer
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active

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active

oldest

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active

oldest

votes









6












$begingroup$

Lampakis 2007 provided a new proof there are no $xyzne 0$ solutions. It runs to several pages. Lampakis notes Feuter 1913 provided the original proof, but I couldn't find an online link to his reference, R. Feuter, Sitzungsber. Akad. Wiss. Heidelberg (Math.), 4, A, 1913 No. 25.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you very much for your answer.
    $endgroup$
    – Ali Taghavi
    Jan 16 at 20:58
















6












$begingroup$

Lampakis 2007 provided a new proof there are no $xyzne 0$ solutions. It runs to several pages. Lampakis notes Feuter 1913 provided the original proof, but I couldn't find an online link to his reference, R. Feuter, Sitzungsber. Akad. Wiss. Heidelberg (Math.), 4, A, 1913 No. 25.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thank you very much for your answer.
    $endgroup$
    – Ali Taghavi
    Jan 16 at 20:58














6












6








6





$begingroup$

Lampakis 2007 provided a new proof there are no $xyzne 0$ solutions. It runs to several pages. Lampakis notes Feuter 1913 provided the original proof, but I couldn't find an online link to his reference, R. Feuter, Sitzungsber. Akad. Wiss. Heidelberg (Math.), 4, A, 1913 No. 25.






share|cite|improve this answer











$endgroup$



Lampakis 2007 provided a new proof there are no $xyzne 0$ solutions. It runs to several pages. Lampakis notes Feuter 1913 provided the original proof, but I couldn't find an online link to his reference, R. Feuter, Sitzungsber. Akad. Wiss. Heidelberg (Math.), 4, A, 1913 No. 25.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Jan 15 at 12:08

























answered Jan 15 at 7:53









J.G.J.G.

25.6k22539




25.6k22539












  • $begingroup$
    Thank you very much for your answer.
    $endgroup$
    – Ali Taghavi
    Jan 16 at 20:58


















  • $begingroup$
    Thank you very much for your answer.
    $endgroup$
    – Ali Taghavi
    Jan 16 at 20:58
















$begingroup$
Thank you very much for your answer.
$endgroup$
– Ali Taghavi
Jan 16 at 20:58




$begingroup$
Thank you very much for your answer.
$endgroup$
– Ali Taghavi
Jan 16 at 20:58


















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