Speed of Propogation in PDE?












0












$begingroup$


Let $u(x,t)$ be a solution to some PDE, then how do we calculate the speed of propagation (I am not even sure what does that term mean). I have some intuitive idea for example if $u(x,t) = f(x-ct)$, then the graph of $u(x,t)$ is same as graph of $u(x-ct,0)$ and hence we have a vague notion of graph moving at a speed of $c$ in a particular direction. But for more complicated cases where the graph not only travels but also changes is shapes (sorry I couldn't think of an example), how does one go about calculating the speed of propagation.










share|cite|improve this question









$endgroup$












  • $begingroup$
    What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
    $endgroup$
    – Tyler Kharazi
    Jan 9 at 21:56










  • $begingroup$
    @TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
    $endgroup$
    – henceproved
    Jan 9 at 22:03










  • $begingroup$
    Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
    $endgroup$
    – Tyler Kharazi
    Jan 10 at 21:37


















0












$begingroup$


Let $u(x,t)$ be a solution to some PDE, then how do we calculate the speed of propagation (I am not even sure what does that term mean). I have some intuitive idea for example if $u(x,t) = f(x-ct)$, then the graph of $u(x,t)$ is same as graph of $u(x-ct,0)$ and hence we have a vague notion of graph moving at a speed of $c$ in a particular direction. But for more complicated cases where the graph not only travels but also changes is shapes (sorry I couldn't think of an example), how does one go about calculating the speed of propagation.










share|cite|improve this question









$endgroup$












  • $begingroup$
    What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
    $endgroup$
    – Tyler Kharazi
    Jan 9 at 21:56










  • $begingroup$
    @TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
    $endgroup$
    – henceproved
    Jan 9 at 22:03










  • $begingroup$
    Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
    $endgroup$
    – Tyler Kharazi
    Jan 10 at 21:37
















0












0








0





$begingroup$


Let $u(x,t)$ be a solution to some PDE, then how do we calculate the speed of propagation (I am not even sure what does that term mean). I have some intuitive idea for example if $u(x,t) = f(x-ct)$, then the graph of $u(x,t)$ is same as graph of $u(x-ct,0)$ and hence we have a vague notion of graph moving at a speed of $c$ in a particular direction. But for more complicated cases where the graph not only travels but also changes is shapes (sorry I couldn't think of an example), how does one go about calculating the speed of propagation.










share|cite|improve this question









$endgroup$




Let $u(x,t)$ be a solution to some PDE, then how do we calculate the speed of propagation (I am not even sure what does that term mean). I have some intuitive idea for example if $u(x,t) = f(x-ct)$, then the graph of $u(x,t)$ is same as graph of $u(x-ct,0)$ and hence we have a vague notion of graph moving at a speed of $c$ in a particular direction. But for more complicated cases where the graph not only travels but also changes is shapes (sorry I couldn't think of an example), how does one go about calculating the speed of propagation.







pde






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 9 at 21:26









henceprovedhenceproved

1358




1358












  • $begingroup$
    What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
    $endgroup$
    – Tyler Kharazi
    Jan 9 at 21:56










  • $begingroup$
    @TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
    $endgroup$
    – henceproved
    Jan 9 at 22:03










  • $begingroup$
    Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
    $endgroup$
    – Tyler Kharazi
    Jan 10 at 21:37




















  • $begingroup$
    What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
    $endgroup$
    – Tyler Kharazi
    Jan 9 at 21:56










  • $begingroup$
    @TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
    $endgroup$
    – henceproved
    Jan 9 at 22:03










  • $begingroup$
    Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
    $endgroup$
    – Tyler Kharazi
    Jan 10 at 21:37


















$begingroup$
What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
$endgroup$
– Tyler Kharazi
Jan 9 at 21:56




$begingroup$
What sort of PDE are you interested in, wave equation, heat equation? Any initial conditions? Might help to know.
$endgroup$
– Tyler Kharazi
Jan 9 at 21:56












$begingroup$
@TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
$endgroup$
– henceproved
Jan 9 at 22:03




$begingroup$
@TylerKharazi I would like to find the speed of the wave equation on an infinite line, where $u(x,0)= 0$ and $u'(x,0) = 1$ on $|x| < a$ and 0 otherwise.
$endgroup$
– henceproved
Jan 9 at 22:03












$begingroup$
Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
$endgroup$
– Tyler Kharazi
Jan 10 at 21:37






$begingroup$
Sorry it took me so long to respond, I forgot to finish answering last night. Hmm, I think that within the PDE, the speed of propagation should be the inverse of the constant term multiplying the time derivative term (or the constant on the spatial derivative term). Have a look at page 16 and 17 of this: web.math.ucsb.edu/~grigoryan/124A.pdf. The speed of propagation is kinda what is sounds like. Its the speed at which the solution moves through space. Even if the waveform changes shape, we can still calculate how quickly the shape is moving through space.
$endgroup$
– Tyler Kharazi
Jan 10 at 21:37












0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3067966%2fspeed-of-propogation-in-pde%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3067966%2fspeed-of-propogation-in-pde%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Mario Kart Wii

What does “Dominus providebit” mean?

Antonio Litta Visconti Arese