How do you find the factor of a polynomial with the remainders of polynomials that are being divided?












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I don't understand how to do this problem. I need to determine constants a and b based of the remainders of two polynomials divided by f(x)




When a polynomial expression $f(x)$ is divided by $x^2-4$ the remainder is $ax+b$. Determine the constants $a$ and $b$, given that $x-2$ is a factor of $f(x)$ and also that when $f(x)$ is divided by $x+2$, the remainder is $8$.











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    I don't understand how to do this problem. I need to determine constants a and b based of the remainders of two polynomials divided by f(x)




    When a polynomial expression $f(x)$ is divided by $x^2-4$ the remainder is $ax+b$. Determine the constants $a$ and $b$, given that $x-2$ is a factor of $f(x)$ and also that when $f(x)$ is divided by $x+2$, the remainder is $8$.











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    New contributor




    CosmoCrash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      0












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      0







      I don't understand how to do this problem. I need to determine constants a and b based of the remainders of two polynomials divided by f(x)




      When a polynomial expression $f(x)$ is divided by $x^2-4$ the remainder is $ax+b$. Determine the constants $a$ and $b$, given that $x-2$ is a factor of $f(x)$ and also that when $f(x)$ is divided by $x+2$, the remainder is $8$.











      share|cite|improve this question









      New contributor




      CosmoCrash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I don't understand how to do this problem. I need to determine constants a and b based of the remainders of two polynomials divided by f(x)




      When a polynomial expression $f(x)$ is divided by $x^2-4$ the remainder is $ax+b$. Determine the constants $a$ and $b$, given that $x-2$ is a factor of $f(x)$ and also that when $f(x)$ is divided by $x+2$, the remainder is $8$.








      polynomials






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      edited 2 hours ago









      jmerry

      1,961210




      1,961210






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      asked 2 hours ago









      CosmoCrash

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          The key to this problem is that $x-2$ and $x-4$ are the factors of $x^2-4$.



          Suppose we split $f$ into two parts through that division: $f(x) = (x^2-4)g(x) + ax+b$. What does it look like if we divide that by $x-2$? By $x+2$?






          share|cite|improve this answer





















          • I solved the problem and got a = 0 , b = 2 but it says that's wrong
            – CosmoCrash
            1 hour ago










          • Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
            – jmerry
            1 hour ago











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          0














          The key to this problem is that $x-2$ and $x-4$ are the factors of $x^2-4$.



          Suppose we split $f$ into two parts through that division: $f(x) = (x^2-4)g(x) + ax+b$. What does it look like if we divide that by $x-2$? By $x+2$?






          share|cite|improve this answer





















          • I solved the problem and got a = 0 , b = 2 but it says that's wrong
            – CosmoCrash
            1 hour ago










          • Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
            – jmerry
            1 hour ago
















          0














          The key to this problem is that $x-2$ and $x-4$ are the factors of $x^2-4$.



          Suppose we split $f$ into two parts through that division: $f(x) = (x^2-4)g(x) + ax+b$. What does it look like if we divide that by $x-2$? By $x+2$?






          share|cite|improve this answer





















          • I solved the problem and got a = 0 , b = 2 but it says that's wrong
            – CosmoCrash
            1 hour ago










          • Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
            – jmerry
            1 hour ago














          0












          0








          0






          The key to this problem is that $x-2$ and $x-4$ are the factors of $x^2-4$.



          Suppose we split $f$ into two parts through that division: $f(x) = (x^2-4)g(x) + ax+b$. What does it look like if we divide that by $x-2$? By $x+2$?






          share|cite|improve this answer












          The key to this problem is that $x-2$ and $x-4$ are the factors of $x^2-4$.



          Suppose we split $f$ into two parts through that division: $f(x) = (x^2-4)g(x) + ax+b$. What does it look like if we divide that by $x-2$? By $x+2$?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 2 hours ago









          jmerry

          1,961210




          1,961210












          • I solved the problem and got a = 0 , b = 2 but it says that's wrong
            – CosmoCrash
            1 hour ago










          • Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
            – jmerry
            1 hour ago


















          • I solved the problem and got a = 0 , b = 2 but it says that's wrong
            – CosmoCrash
            1 hour ago










          • Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
            – jmerry
            1 hour ago
















          I solved the problem and got a = 0 , b = 2 but it says that's wrong
          – CosmoCrash
          1 hour ago




          I solved the problem and got a = 0 , b = 2 but it says that's wrong
          – CosmoCrash
          1 hour ago












          Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
          – jmerry
          1 hour ago




          Indeed. That would be a remainder of $2$ when divided by $x-2$ and a remainder of $2$ when divided by $x+2$. We can't say more unless you say more about what you've tried to do.
          – jmerry
          1 hour ago










          CosmoCrash is a new contributor. Be nice, and check out our Code of Conduct.










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