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0 1 $begingroup$ Hi I am having problems to understand this: I have: $Omega = [0,1]$ , $Lambda =$ all subsets with defined length Let $A_{0}$ = {A $subset$ [0,1]: A is finite union of intervals} 1º: My doubt is that $A_{0}$ is a algebra but its not a sigma algebra. Why? Also, A = $(0,1/2) cup (1/2,3/4) cup (3/4,7/8) cup ... cup(1-1/2^{n},1-1/2^{n+1})...$ 2º: So the class of aleatory events would be bigger than $A_{0}$ . Why? How the set A is greater than $A_{0}$ ? measure-theory share | cite | improve this question asked Jan 8 at 19:17 Diogo Bastos Diogo Bastos 116 6 ...

0 $begingroup$ I was given this tricky problem in which I'm confuse on how to solve it and I would like some help: Let $v(x,y)$ be continuously differentiable function. Let the function $u(s,t)$ be given by $u(s,t) = sin(s)*v(s-2t,t^2)$ . Compute $du/ds$ and $du/dt$ in terms of $v$ and it's partial derivatives. My attempt (which is wrong): Using chain rule: $du/ds=(du/dx)(dx/ds) + (du/dy)(dy/ds)$ $du/dt=(du/dx)(dx/dt) + (du/dx)(dy/dt)$ So, $du/ds = sin(s)*v(x,y)*s + sin(s)*v(x,y)*0$ $du/dt = 2t*sin(s)*v(x,y) - 2*sin(s)*v(x,y)$ Thanks, calculus multivariable-calculus share | cite | improve this question edited Jan 19 at 19:38...

Please consider supporting The Cutting Room Floor on Patreon. Thanks for all your support! The Legend of Zelda: Spirit Tracks From The Cutting Room Floor Jump to: navigation, search The Legend of Zelda: Spirit Tracks Also known as : Zelda no Densetsu: Daichi no Kiteki (JP) Developer : Nintendo Publisher : Nintendo Platform : Nintendo DS Released in JP : December 23, 2009 Released in US : December 7, 2009 Released in EU : December 11, 2009 Released in AU : December 10, 2009 This game has unused areas. This game has unused graphics. This game has unused models. This game has unused music. This game has debugging material. This game has regional differences. This game has anti-piracy features. Spirit Tracks is the sequel to Phantom Hourglass and uses a modified version of its predecessor's engine. Yes, Zelda really is a spirit, and she's even...