Solution for first order ODE with discontinuous right hand side












1












$begingroup$


I'm now approaching for the first time to first order differential equations with discontinuous right hand side.



Let $Asubset mathbb{R}timesmathbb{R}^n$ and $f=f(t, x):Ato mathbb{R}^n$. Fix $(t_0,x_0)in A$ and consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(t_0)=x_0end{cases}.qquad[A]$$ It is well known that if $f$ is continuous then Peano's Theorem guarantee the existence of a local classical solution to $[A]$, which is also a $C^1$ function.



The notion of Carathéodory solution for an initial problem like $[A]$ arises when $f$ is a general function, not necessarily continuous.



Def. An absolutely continuous function $y:[t_0,t_0+a]to mathbb{R}^n$ ($a in mathbb{R},a>0$), such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is said to be a Carathedory solution for $[A]$ if $$y(t)=x_0+int_{t_0}^{t}f(s,y(s)dsqquad t in [t_0,t_0+a].$$ By equivalent definitions of absolute continuity for functions on closed and bounded intervals it follow immediately that if $y:[t_0,t_0+a]to mathbb{R}^n$, such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is an absolutely continuous function, then $$text{y is a Carathédory solution of}, [A] iff ,text y(t_0)=x_0,text{and}, y'(t)=f(t,y(t)), text {for a.e.}, t in [t_0,t_0+a].$$



By Carathédory existence theorem we know that, under suitable conditions on $f$, there is at least a solution of $[A]$, in the weak sense as above.



Now let's suppose we are given a function $f:[0,+infty)times mathbb{R}^nto mathbb{R}^n$ and a point $x_0 in mathbb{R}^n$. Consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(0)=x_0end{cases}.qquad[B]$$ In many books I read that under the hypothesis:



(i)$f$ is bounded



(ii) the map $tto f(x, t)$ is measurable for each $x$



(iii) Exists $L>0$ such that $$|f(t,x_1)-f(t,x_2)|leq L|x_1-x_2| qquad forall (t,x_1)(t,x_2) in [0,+infty)times mathbb{R}^n $$
then there exist a unique global solution $y_{x_0}:[0,+infty)to mathbb{R}^n$ to $[B]$.



The problem is that I'm missing what "solution" in this case means (the interval of definition of $y_{x_0}$ is not closed and it is also unbounded). I think that it could be understood like a function $y:[0,+infty)to mathbb{R}^n$ such that $y$ is absolutely continuous on every compact subinterval $[a,b]subset [0,+infty)$ and $$y(t)=x_0+int_{t_0}^{t}f(s,y(s))ds qquad t>0,$$ but I'm not sure about it. For instance, this problem arises in studying optimal control theory.



Can anyone give me some help or some good references?



Thanks a lot.










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    I'm now approaching for the first time to first order differential equations with discontinuous right hand side.



    Let $Asubset mathbb{R}timesmathbb{R}^n$ and $f=f(t, x):Ato mathbb{R}^n$. Fix $(t_0,x_0)in A$ and consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(t_0)=x_0end{cases}.qquad[A]$$ It is well known that if $f$ is continuous then Peano's Theorem guarantee the existence of a local classical solution to $[A]$, which is also a $C^1$ function.



    The notion of Carathéodory solution for an initial problem like $[A]$ arises when $f$ is a general function, not necessarily continuous.



    Def. An absolutely continuous function $y:[t_0,t_0+a]to mathbb{R}^n$ ($a in mathbb{R},a>0$), such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is said to be a Carathedory solution for $[A]$ if $$y(t)=x_0+int_{t_0}^{t}f(s,y(s)dsqquad t in [t_0,t_0+a].$$ By equivalent definitions of absolute continuity for functions on closed and bounded intervals it follow immediately that if $y:[t_0,t_0+a]to mathbb{R}^n$, such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is an absolutely continuous function, then $$text{y is a Carathédory solution of}, [A] iff ,text y(t_0)=x_0,text{and}, y'(t)=f(t,y(t)), text {for a.e.}, t in [t_0,t_0+a].$$



    By Carathédory existence theorem we know that, under suitable conditions on $f$, there is at least a solution of $[A]$, in the weak sense as above.



    Now let's suppose we are given a function $f:[0,+infty)times mathbb{R}^nto mathbb{R}^n$ and a point $x_0 in mathbb{R}^n$. Consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(0)=x_0end{cases}.qquad[B]$$ In many books I read that under the hypothesis:



    (i)$f$ is bounded



    (ii) the map $tto f(x, t)$ is measurable for each $x$



    (iii) Exists $L>0$ such that $$|f(t,x_1)-f(t,x_2)|leq L|x_1-x_2| qquad forall (t,x_1)(t,x_2) in [0,+infty)times mathbb{R}^n $$
    then there exist a unique global solution $y_{x_0}:[0,+infty)to mathbb{R}^n$ to $[B]$.



    The problem is that I'm missing what "solution" in this case means (the interval of definition of $y_{x_0}$ is not closed and it is also unbounded). I think that it could be understood like a function $y:[0,+infty)to mathbb{R}^n$ such that $y$ is absolutely continuous on every compact subinterval $[a,b]subset [0,+infty)$ and $$y(t)=x_0+int_{t_0}^{t}f(s,y(s))ds qquad t>0,$$ but I'm not sure about it. For instance, this problem arises in studying optimal control theory.



    Can anyone give me some help or some good references?



    Thanks a lot.










    share|cite|improve this question









    $endgroup$















      1












      1








      1


      2



      $begingroup$


      I'm now approaching for the first time to first order differential equations with discontinuous right hand side.



      Let $Asubset mathbb{R}timesmathbb{R}^n$ and $f=f(t, x):Ato mathbb{R}^n$. Fix $(t_0,x_0)in A$ and consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(t_0)=x_0end{cases}.qquad[A]$$ It is well known that if $f$ is continuous then Peano's Theorem guarantee the existence of a local classical solution to $[A]$, which is also a $C^1$ function.



      The notion of Carathéodory solution for an initial problem like $[A]$ arises when $f$ is a general function, not necessarily continuous.



      Def. An absolutely continuous function $y:[t_0,t_0+a]to mathbb{R}^n$ ($a in mathbb{R},a>0$), such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is said to be a Carathedory solution for $[A]$ if $$y(t)=x_0+int_{t_0}^{t}f(s,y(s)dsqquad t in [t_0,t_0+a].$$ By equivalent definitions of absolute continuity for functions on closed and bounded intervals it follow immediately that if $y:[t_0,t_0+a]to mathbb{R}^n$, such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is an absolutely continuous function, then $$text{y is a Carathédory solution of}, [A] iff ,text y(t_0)=x_0,text{and}, y'(t)=f(t,y(t)), text {for a.e.}, t in [t_0,t_0+a].$$



      By Carathédory existence theorem we know that, under suitable conditions on $f$, there is at least a solution of $[A]$, in the weak sense as above.



      Now let's suppose we are given a function $f:[0,+infty)times mathbb{R}^nto mathbb{R}^n$ and a point $x_0 in mathbb{R}^n$. Consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(0)=x_0end{cases}.qquad[B]$$ In many books I read that under the hypothesis:



      (i)$f$ is bounded



      (ii) the map $tto f(x, t)$ is measurable for each $x$



      (iii) Exists $L>0$ such that $$|f(t,x_1)-f(t,x_2)|leq L|x_1-x_2| qquad forall (t,x_1)(t,x_2) in [0,+infty)times mathbb{R}^n $$
      then there exist a unique global solution $y_{x_0}:[0,+infty)to mathbb{R}^n$ to $[B]$.



      The problem is that I'm missing what "solution" in this case means (the interval of definition of $y_{x_0}$ is not closed and it is also unbounded). I think that it could be understood like a function $y:[0,+infty)to mathbb{R}^n$ such that $y$ is absolutely continuous on every compact subinterval $[a,b]subset [0,+infty)$ and $$y(t)=x_0+int_{t_0}^{t}f(s,y(s))ds qquad t>0,$$ but I'm not sure about it. For instance, this problem arises in studying optimal control theory.



      Can anyone give me some help or some good references?



      Thanks a lot.










      share|cite|improve this question









      $endgroup$




      I'm now approaching for the first time to first order differential equations with discontinuous right hand side.



      Let $Asubset mathbb{R}timesmathbb{R}^n$ and $f=f(t, x):Ato mathbb{R}^n$. Fix $(t_0,x_0)in A$ and consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(t_0)=x_0end{cases}.qquad[A]$$ It is well known that if $f$ is continuous then Peano's Theorem guarantee the existence of a local classical solution to $[A]$, which is also a $C^1$ function.



      The notion of Carathéodory solution for an initial problem like $[A]$ arises when $f$ is a general function, not necessarily continuous.



      Def. An absolutely continuous function $y:[t_0,t_0+a]to mathbb{R}^n$ ($a in mathbb{R},a>0$), such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is said to be a Carathedory solution for $[A]$ if $$y(t)=x_0+int_{t_0}^{t}f(s,y(s)dsqquad t in [t_0,t_0+a].$$ By equivalent definitions of absolute continuity for functions on closed and bounded intervals it follow immediately that if $y:[t_0,t_0+a]to mathbb{R}^n$, such that $(t,y(t))in A ,forall t in [t_0,t_0+a]$, is an absolutely continuous function, then $$text{y is a Carathédory solution of}, [A] iff ,text y(t_0)=x_0,text{and}, y'(t)=f(t,y(t)), text {for a.e.}, t in [t_0,t_0+a].$$



      By Carathédory existence theorem we know that, under suitable conditions on $f$, there is at least a solution of $[A]$, in the weak sense as above.



      Now let's suppose we are given a function $f:[0,+infty)times mathbb{R}^nto mathbb{R}^n$ and a point $x_0 in mathbb{R}^n$. Consider the initial value problem $$begin{cases} y'(t)=f(t,y(t))\y(0)=x_0end{cases}.qquad[B]$$ In many books I read that under the hypothesis:



      (i)$f$ is bounded



      (ii) the map $tto f(x, t)$ is measurable for each $x$



      (iii) Exists $L>0$ such that $$|f(t,x_1)-f(t,x_2)|leq L|x_1-x_2| qquad forall (t,x_1)(t,x_2) in [0,+infty)times mathbb{R}^n $$
      then there exist a unique global solution $y_{x_0}:[0,+infty)to mathbb{R}^n$ to $[B]$.



      The problem is that I'm missing what "solution" in this case means (the interval of definition of $y_{x_0}$ is not closed and it is also unbounded). I think that it could be understood like a function $y:[0,+infty)to mathbb{R}^n$ such that $y$ is absolutely continuous on every compact subinterval $[a,b]subset [0,+infty)$ and $$y(t)=x_0+int_{t_0}^{t}f(s,y(s))ds qquad t>0,$$ but I'm not sure about it. For instance, this problem arises in studying optimal control theory.



      Can anyone give me some help or some good references?



      Thanks a lot.







      real-analysis ordinary-differential-equations control-theory optimal-control






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 21 at 16:41









      eleguitareleguitar

      140114




      140114






















          0






          active

          oldest

          votes











          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });














          draft saved

          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3082082%2fsolution-for-first-order-ode-with-discontinuous-right-hand-side%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown

























          0






          active

          oldest

          votes








          0






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes
















          draft saved

          draft discarded




















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid



          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.


          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3082082%2fsolution-for-first-order-ode-with-discontinuous-right-hand-side%23new-answer', 'question_page');
          }
          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Mario Kart Wii

          Understanding the size os this class of aleatory events

          Partial Derivative Guidance.