Contea di Owen (Indiana)








Abbozzo
Questa voce sull'argomento contee dell'Indiana è solo un abbozzo.

Contribuisci a migliorarla secondo le convenzioni di Wikipedia.















































Contea di Owen
contea
Localizzazione
Stato
Stati Uniti Stati Uniti
Stato federato
Flag of Indiana.svg Indiana
Amministrazione
Capoluogo Spencer
Data di istituzione 1818
Territorio

Coordinate
del capoluogo
39°18′36″N 86°50′24″W / 39.31°N 86.84°W39.31; -86.84 (Contea di Owen)Coordinate: 39°18′36″N 86°50′24″W / 39.31°N 86.84°W39.31; -86.84 (Contea di Owen)
Superficie 1 005 km²
Abitanti 21 786 (2000)
Densità 21,68 ab./km²
Altre informazioni
Fuso orario UTC-5
Cartografia

Mappa di localizzazione: Stati Uniti d'America

Spencer

Spencer


Contea di Owen – Mappa

Modifica dati su Wikidata · Manuale

La contea di Owen (in inglese Owen County) è una contea dello Stato dell'Indiana, negli Stati Uniti. La popolazione al censimento del 2000 era di 21786 abitanti. Il capoluogo di contea è Spencer.



Altri progetti |



Altri progetti


  • Wikimedia Commons



  • Collabora a Wikimedia CommonsWikimedia Commons contiene immagini o altri file su contea di Owen

.mw-parser-output .navbox{border:1px solid #aaa;clear:both;margin:auto;padding:2px;width:100%}.mw-parser-output .navbox th{padding-left:1em;padding-right:1em;text-align:center}.mw-parser-output .navbox>tbody>tr:first-child>th{background:#ccf;font-size:90%;width:100%}.mw-parser-output .navbox_navbar{float:left;margin:0;padding:0 10px 0 0;text-align:left;width:6em}.mw-parser-output .navbox_title{font-size:110%}.mw-parser-output .navbox_abovebelow{background:#ddf;font-size:90%;font-weight:normal}.mw-parser-output .navbox_group{background:#ddf;font-size:90%;padding:0 10px;white-space:nowrap}.mw-parser-output .navbox_list{font-size:90%;width:100%}.mw-parser-output .navbox_odd{background:#fdfdfd}.mw-parser-output .navbox_even{background:#f7f7f7}.mw-parser-output .navbox_center{text-align:center}.mw-parser-output .navbox .navbox_image{padding-left:7px;vertical-align:middle;width:0}.mw-parser-output .navbox+.navbox{margin-top:-1px}.mw-parser-output .navbox .mw-collapsible-toggle{font-weight:normal;text-align:right;width:7em}.mw-parser-output .subnavbox{margin:-3px;width:100%}.mw-parser-output .subnavbox_group{background:#ddf;padding:0 10px}






















Stati Uniti d'AmericaPortale Stati Uniti d'America: accedi alle voci di Wikipedia che trattano di Stati Uniti d'America



-

Popular posts from this blog

Mario Kart Wii

Image
Please consider supporting The Cutting Room Floor on Patreon. Thanks for all your support! Mario Kart Wii From The Cutting Room Floor Jump to: navigation, search Mario Kart Wii Developer : Nintendo Publisher : Nintendo Platform : Wii Released in JP : April 10, 2008 Released in US : April 27, 2008 Released in EU : April 11, 2008 Released in AU : April 24, 2008 Released in KR : April 30, 2009 This game has unused animations. This game has unused areas. This game has unused code. This game has unused objects. This game has unused modes / minigames. This game has unused graphics. This game has unused models. This game has unused items. This game has unused music. This game has regional differences. This game has a notes page This game has a prerelease article Mario Kart Wii is the sixth game in the series (not counting Arcade editions), which intro...
Read more

Partial Derivative Guidance.

Image
0 $begingroup$ I was given this tricky problem in which I'm confuse on how to solve it and I would like some help: Let $v(x,y)$ be continuously differentiable function. Let the function $u(s,t)$ be given by $u(s,t) = sin(s)*v(s-2t,t^2)$ . Compute $du/ds$ and $du/dt$ in terms of $v$ and it's partial derivatives. My attempt (which is wrong): Using chain rule: $du/ds=(du/dx)(dx/ds) + (du/dy)(dy/ds)$ $du/dt=(du/dx)(dx/dt) + (du/dx)(dy/dt)$ So, $du/ds = sin(s)*v(x,y)*s + sin(s)*v(x,y)*0$ $du/dt = 2t*sin(s)*v(x,y) - 2*sin(s)*v(x,y)$ Thanks, calculus multivariable-calculus share | cite | improve this question edited Jan 19 at 19:38...
Read more

Understanding the size os this class of aleatory events

Image
0 1 $begingroup$ Hi I am having problems to understand this: I have: $Omega = [0,1]$ , $Lambda =$ all subsets with defined length Let $A_{0}$ = {A $subset$ [0,1]: A is finite union of intervals} 1º: My doubt is that $A_{0}$ is a algebra but its not a sigma algebra. Why? Also, A = $(0,1/2) cup (1/2,3/4) cup (3/4,7/8) cup ... cup(1-1/2^{n},1-1/2^{n+1})...$ 2º: So the class of aleatory events would be bigger than $A_{0}$ . Why? How the set A is greater than $A_{0}$ ? measure-theory share | cite | improve this question asked Jan 8 at 19:17 Diogo Bastos Diogo Bastos 116 6 ...
Read more