“nothing” in boolean algebra
-1
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Is there formal notation for saying "there is no x for which P(x)" or is it simply something like $( neg exists x) P(x)$?
notation boolean-algebra
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
$endgroup$
add a comment |
-1
$begingroup$
Is there formal notation for saying "there is no x for which P(x)" or is it simply something like $( neg exists x) P(x)$?
notation boolean-algebra
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
$endgroup$
4
$begingroup$
There's nothing informal about using words. Words are great.
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– Misha Lavrov
Jan 8 at 20:48
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@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
3
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
3
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02
add a comment |
-1
-1
-1
$begingroup$
Is there formal notation for saying "there is no x for which P(x)" or is it simply something like $( neg exists x) P(x)$?
notation boolean-algebra
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
$endgroup$
Is there formal notation for saying "there is no x for which P(x)" or is it simply something like $( neg exists x) P(x)$?
notation boolean-algebra
notation boolean-algebra
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
edited Jan 8 at 20:51
NetherGranite
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
asked Jan 8 at 20:45
NetherGraniteNetherGranite
1417
1417
4
$begingroup$
There's nothing informal about using words. Words are great.
$endgroup$
– Misha Lavrov
Jan 8 at 20:48
$begingroup$
@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
3
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
3
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02
add a comment |
4
$begingroup$
There's nothing informal about using words. Words are great.
$endgroup$
– Misha Lavrov
Jan 8 at 20:48
$begingroup$
@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
3
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
3
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02
4
4
$begingroup$
There's nothing informal about using words. Words are great.
$endgroup$
– Misha Lavrov
Jan 8 at 20:48
$begingroup$
There's nothing informal about using words. Words are great.
$endgroup$
– Misha Lavrov
Jan 8 at 20:48
$begingroup$
@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
$begingroup$
@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
3
3
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
3
3
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02
add a comment |
1 Answer
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$begingroup$
There's no established symbol analogous to $forall$ or $exists$, no. You can write either $neg exists x. P(x)$ or $forall x. neg P(x)$.
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
$endgroup$
add a comment |
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$begingroup$
There's no established symbol analogous to $forall$ or $exists$, no. You can write either $neg exists x. P(x)$ or $forall x. neg P(x)$.
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
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3
$begingroup$
There's no established symbol analogous to $forall$ or $exists$, no. You can write either $neg exists x. P(x)$ or $forall x. neg P(x)$.
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
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add a comment |
3
3
3
$begingroup$
There's no established symbol analogous to $forall$ or $exists$, no. You can write either $neg exists x. P(x)$ or $forall x. neg P(x)$.
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
$endgroup$
There's no established symbol analogous to $forall$ or $exists$, no. You can write either $neg exists x. P(x)$ or $forall x. neg P(x)$.
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
15.6k32977
answered Jan 8 at 20:51
Daniel McLauryDaniel McLaury
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15.6k32977
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4
$begingroup$
There's nothing informal about using words. Words are great.
$endgroup$
– Misha Lavrov
Jan 8 at 20:48
$begingroup$
@MishaLavrov Sorry, I meant formal notation. I will revise my wording.
$endgroup$
– NetherGranite
Jan 8 at 20:50
3
$begingroup$
I would use parentheses a little differently but you have the basic idea: $lnot (exists x P(x))$
$endgroup$
– hardmath
Jan 8 at 20:52
3
$begingroup$
$not exists x mid P(x)$
$endgroup$
– Kuifje
Jan 8 at 20:55
$begingroup$
In boolean algebra, wouldn't this just be "For all $x$, $P(x)=0$"? (I mean if it were a logic circuit, you'd just take the $P(x)$ signal directly from the OV supply raill . . .)
$endgroup$
– timtfj
Jan 8 at 22:02