What is the Bruhat decomposition of the affine Grassmannian?












6














We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition



$GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$



where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix



$left(begin{array}{cc}
t^{-1} & 0 \

0 & t^{-1} \
end{array}right)$



is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse



$left(begin{array}{cc}
t & 0 \

0 & t \
end{array}right).$



So, my question is, what is wrong here? What is the correct decomposition and indexing set?










share|cite|improve this question





























    6














    We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition



    $GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$



    where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix



    $left(begin{array}{cc}
    t^{-1} & 0 \

    0 & t^{-1} \
    end{array}right)$



    is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse



    $left(begin{array}{cc}
    t & 0 \

    0 & t \
    end{array}right).$



    So, my question is, what is wrong here? What is the correct decomposition and indexing set?










    share|cite|improve this question



























      6












      6








      6


      3





      We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition



      $GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$



      where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix



      $left(begin{array}{cc}
      t^{-1} & 0 \

      0 & t^{-1} \
      end{array}right)$



      is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse



      $left(begin{array}{cc}
      t & 0 \

      0 & t \
      end{array}right).$



      So, my question is, what is wrong here? What is the correct decomposition and indexing set?










      share|cite|improve this question















      We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition



      $GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$



      where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix



      $left(begin{array}{cc}
      t^{-1} & 0 \

      0 & t^{-1} \
      end{array}right)$



      is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse



      $left(begin{array}{cc}
      t & 0 \

      0 & t \
      end{array}right).$



      So, my question is, what is wrong here? What is the correct decomposition and indexing set?







      combinatorics algebraic-geometry schubert-calculus






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      edited 2 days ago









      Matt Samuel

      37.5k63665




      37.5k63665










      asked Jan 4 '12 at 20:56









      MehtaMehta

      35619




      35619






















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          Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
          Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.



          This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.






          share|cite|improve this answer

















          • 2




            Can you provide a link to the referred paper?
            – draks ...
            Oct 16 '12 at 12:31











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          1 Answer
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          1 Answer
          1






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          active

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          active

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          3














          Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
          Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.



          This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.






          share|cite|improve this answer

















          • 2




            Can you provide a link to the referred paper?
            – draks ...
            Oct 16 '12 at 12:31
















          3














          Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
          Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.



          This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.






          share|cite|improve this answer

















          • 2




            Can you provide a link to the referred paper?
            – draks ...
            Oct 16 '12 at 12:31














          3












          3








          3






          Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
          Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.



          This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.






          share|cite|improve this answer












          Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
          Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.



          This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Oct 16 '12 at 8:16









          OliverOliver

          462




          462








          • 2




            Can you provide a link to the referred paper?
            – draks ...
            Oct 16 '12 at 12:31














          • 2




            Can you provide a link to the referred paper?
            – draks ...
            Oct 16 '12 at 12:31








          2




          2




          Can you provide a link to the referred paper?
          – draks ...
          Oct 16 '12 at 12:31




          Can you provide a link to the referred paper?
          – draks ...
          Oct 16 '12 at 12:31


















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