What is the Bruhat decomposition of the affine Grassmannian?
We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition
$GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$
where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix
$left(begin{array}{cc}
t^{-1} & 0 \
0 & t^{-1} \
end{array}right)$
is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse
$left(begin{array}{cc}
t & 0 \
0 & t \
end{array}right).$
So, my question is, what is wrong here? What is the correct decomposition and indexing set?
combinatorics algebraic-geometry schubert-calculus
add a comment |
We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition
$GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$
where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix
$left(begin{array}{cc}
t^{-1} & 0 \
0 & t^{-1} \
end{array}right)$
is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse
$left(begin{array}{cc}
t & 0 \
0 & t \
end{array}right).$
So, my question is, what is wrong here? What is the correct decomposition and indexing set?
combinatorics algebraic-geometry schubert-calculus
add a comment |
We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition
$GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$
where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix
$left(begin{array}{cc}
t^{-1} & 0 \
0 & t^{-1} \
end{array}right)$
is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse
$left(begin{array}{cc}
t & 0 \
0 & t \
end{array}right).$
So, my question is, what is wrong here? What is the correct decomposition and indexing set?
combinatorics algebraic-geometry schubert-calculus
We define the affine Grassmannian to be the quotient $Gr = GL_n(mathbb{C}((t)))/GL_n(mathbb{C}[[t]])$ where $mathbb{C}((t))$ is the field of formal Laurent series and $mathbb{C}[[t]]$ is the ring of formal power series. (The affine Grassmannian can be defined more generally, but here we restrict to a special case.) If we let $B$ be the Borel subgroup of upper triangular matrices in $GL_n(mathbb{C})$, $T$ a maximal torus, then the Weyl group $W=N(T)/T$ is just $S_n$. Let $widetilde{W} = mathbb{Z}^{n-1} rtimes W$ denote the affine Weyl group. Then for $i = 1, 2,...,n-1$ the affine permutations in $widetilde{W}$ correspond to the usual permutation matrices in $GL_n(mathbb{C})$, namely the identity matrix with columns $i$ and $i+1$ interchanged. The matrix for the affine permutation $s_0$ has ones along the diagonal in rows $2, 3, ..., n-1$, has $t$ in the right hand corner, and $t^{-1}$ in the bottom left corner. Let $I$ denote the Iwahori subgroup, that is, the inverse image of $B$ under the reduction map $GL_n(mathbb{C}((t))) rightarrow GL_n(mathbb{C})$. Then $I$ is the set of upper triangular matrices mod $t$. I read somewhere that $GL_n(mathbb{C}((t)))$ has a decomposition
$GL_n(mathbb{C}((t))) = cup IwGL_n(mathbb{C}[[t]])$
where $w$ varies across the affine permutation matrices. This decomposition is supposed to induce the Bruhat decomposition of the affine Grassmannian into Schubert cells. Now something here is wrong. Since $I subset GL_n(mathbb{C}[[t]])$, and the determinant of any affine permutation matrix is 1 or -1, we have that for any $w in widetilde{W}$ the determinant of any matrix in $IwGL_n(mathbb{C}[[t]])$ has power series determinant, but the matrix
$left(begin{array}{cc}
t^{-1} & 0 \
0 & t^{-1} \
end{array}right)$
is in $GL_n(mathbb{C}((t)))$ with determinant $t^{-2}$ and inverse
$left(begin{array}{cc}
t & 0 \
0 & t \
end{array}right).$
So, my question is, what is wrong here? What is the correct decomposition and indexing set?
combinatorics algebraic-geometry schubert-calculus
combinatorics algebraic-geometry schubert-calculus
edited 2 days ago
Matt Samuel
37.5k63665
37.5k63665
asked Jan 4 '12 at 20:56
MehtaMehta
35619
35619
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add a comment |
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Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.
This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.
2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
add a comment |
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1 Answer
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1 Answer
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active
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Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.
This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.
2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
add a comment |
Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.
This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.
2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
add a comment |
Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.
This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.
Your identification of the Affine Weyl Group with elements of $ G(mathbb{C}((t)) $ is wrong.
Any co-character $lambda:mathbb{C}^*to T$ where $T$ is a chosen maximal torus can be regarded as an element of $ G(mathbb{C}((t))) $. If you choose $P$ to be the abelian group generated by the dominant coroots (which is acted upon by W) the semi-direct product with $W$ is isomorphic to the Affine Weyl Group. Now these elements, for example $tmapsto (t^n,t^{-n})$, give you the desired Bruhat decomposition.
This is explained in the paper of Iwahori and Matsumoto: on some bruhat decomposition... from page 24 on.
answered Oct 16 '12 at 8:16
OliverOliver
462
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2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
add a comment |
2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
2
2
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
Can you provide a link to the referred paper?
– draks ...
Oct 16 '12 at 12:31
add a comment |
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