Medical Units into grams












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I'm trying to figure out how to divide a medicine up by millions of units into grams or half grams and figure a group like this who play with various math problems might be able to help:



What I know about it: comes in a container labeled '1BU'



Net Weight is '153 grams'



Potency is '6536 I.U./mg'



Trying to figure out how to convert 3 million units to grams or percentage of grams. Told it maybe .45 grams. Sound about right? Thanks










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  • $begingroup$
    $6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
    $endgroup$
    – Anvit
    Jan 13 at 4:10












  • $begingroup$
    1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
    $endgroup$
    – achille hui
    Jan 13 at 15:22
















0












$begingroup$


I'm trying to figure out how to divide a medicine up by millions of units into grams or half grams and figure a group like this who play with various math problems might be able to help:



What I know about it: comes in a container labeled '1BU'



Net Weight is '153 grams'



Potency is '6536 I.U./mg'



Trying to figure out how to convert 3 million units to grams or percentage of grams. Told it maybe .45 grams. Sound about right? Thanks










share|cite|improve this question









$endgroup$












  • $begingroup$
    $6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
    $endgroup$
    – Anvit
    Jan 13 at 4:10












  • $begingroup$
    1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
    $endgroup$
    – achille hui
    Jan 13 at 15:22














0












0








0





$begingroup$


I'm trying to figure out how to divide a medicine up by millions of units into grams or half grams and figure a group like this who play with various math problems might be able to help:



What I know about it: comes in a container labeled '1BU'



Net Weight is '153 grams'



Potency is '6536 I.U./mg'



Trying to figure out how to convert 3 million units to grams or percentage of grams. Told it maybe .45 grams. Sound about right? Thanks










share|cite|improve this question









$endgroup$




I'm trying to figure out how to divide a medicine up by millions of units into grams or half grams and figure a group like this who play with various math problems might be able to help:



What I know about it: comes in a container labeled '1BU'



Net Weight is '153 grams'



Potency is '6536 I.U./mg'



Trying to figure out how to convert 3 million units to grams or percentage of grams. Told it maybe .45 grams. Sound about right? Thanks







unit-of-measure






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asked Jan 13 at 3:57









jordanbrianjason126jordanbrianjason126

1




1












  • $begingroup$
    $6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
    $endgroup$
    – Anvit
    Jan 13 at 4:10












  • $begingroup$
    1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
    $endgroup$
    – achille hui
    Jan 13 at 15:22


















  • $begingroup$
    $6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
    $endgroup$
    – Anvit
    Jan 13 at 4:10












  • $begingroup$
    1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
    $endgroup$
    – achille hui
    Jan 13 at 15:22
















$begingroup$
$6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
$endgroup$
– Anvit
Jan 13 at 4:10






$begingroup$
$6536$ units per mg means $6,536,000$ units per gram which means $1,000,000$ units in $0.15299$ grams and hence 3 millions units in $0.45899$ grams
$endgroup$
– Anvit
Jan 13 at 4:10














$begingroup$
1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
$endgroup$
– achille hui
Jan 13 at 15:22




$begingroup$
1BU = 1 billion unit = $10^9 {rm unit} = 153{rm g} implies 3 times 10^6 {rm unit} = 153times frac{3times 10^6}{10^9} = 0.459 {rm g}$
$endgroup$
– achille hui
Jan 13 at 15:22










1 Answer
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$begingroup$

Anvil has already given a correct answer in a comment, but here is the calculation in more detail.



Here is how I was taught to do such calculations, long ago:



$$require{cancel} frac{3,000,000 cancel{text{ IU}}}
{6,536 cancel{text{ IU}} / cancel{text{mg}} times 1,000 cancel{text{ mg}}/text{gm}} = 0.4590 text{ gm}$$



The idea is to treat the units of measurement as if they were algebraic variables; so IU in the numerator cancels the IU in the denominator, then the /mg and mg in the numerator cancel, leaving /gm in the denominator. Finally,
$$frac{1}{1/text{gm}} = text{gm}$$
so the unit of measurement of the final result is gm. The rest of the calculation is just arithmetic. The only fact you have to know beyond what is in the problem statement is the conversion factor of 1,000 milligrams per gram.






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    1 Answer
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    1 Answer
    1






    active

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    0












    $begingroup$

    Anvil has already given a correct answer in a comment, but here is the calculation in more detail.



    Here is how I was taught to do such calculations, long ago:



    $$require{cancel} frac{3,000,000 cancel{text{ IU}}}
    {6,536 cancel{text{ IU}} / cancel{text{mg}} times 1,000 cancel{text{ mg}}/text{gm}} = 0.4590 text{ gm}$$



    The idea is to treat the units of measurement as if they were algebraic variables; so IU in the numerator cancels the IU in the denominator, then the /mg and mg in the numerator cancel, leaving /gm in the denominator. Finally,
    $$frac{1}{1/text{gm}} = text{gm}$$
    so the unit of measurement of the final result is gm. The rest of the calculation is just arithmetic. The only fact you have to know beyond what is in the problem statement is the conversion factor of 1,000 milligrams per gram.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Anvil has already given a correct answer in a comment, but here is the calculation in more detail.



      Here is how I was taught to do such calculations, long ago:



      $$require{cancel} frac{3,000,000 cancel{text{ IU}}}
      {6,536 cancel{text{ IU}} / cancel{text{mg}} times 1,000 cancel{text{ mg}}/text{gm}} = 0.4590 text{ gm}$$



      The idea is to treat the units of measurement as if they were algebraic variables; so IU in the numerator cancels the IU in the denominator, then the /mg and mg in the numerator cancel, leaving /gm in the denominator. Finally,
      $$frac{1}{1/text{gm}} = text{gm}$$
      so the unit of measurement of the final result is gm. The rest of the calculation is just arithmetic. The only fact you have to know beyond what is in the problem statement is the conversion factor of 1,000 milligrams per gram.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Anvil has already given a correct answer in a comment, but here is the calculation in more detail.



        Here is how I was taught to do such calculations, long ago:



        $$require{cancel} frac{3,000,000 cancel{text{ IU}}}
        {6,536 cancel{text{ IU}} / cancel{text{mg}} times 1,000 cancel{text{ mg}}/text{gm}} = 0.4590 text{ gm}$$



        The idea is to treat the units of measurement as if they were algebraic variables; so IU in the numerator cancels the IU in the denominator, then the /mg and mg in the numerator cancel, leaving /gm in the denominator. Finally,
        $$frac{1}{1/text{gm}} = text{gm}$$
        so the unit of measurement of the final result is gm. The rest of the calculation is just arithmetic. The only fact you have to know beyond what is in the problem statement is the conversion factor of 1,000 milligrams per gram.






        share|cite|improve this answer









        $endgroup$



        Anvil has already given a correct answer in a comment, but here is the calculation in more detail.



        Here is how I was taught to do such calculations, long ago:



        $$require{cancel} frac{3,000,000 cancel{text{ IU}}}
        {6,536 cancel{text{ IU}} / cancel{text{mg}} times 1,000 cancel{text{ mg}}/text{gm}} = 0.4590 text{ gm}$$



        The idea is to treat the units of measurement as if they were algebraic variables; so IU in the numerator cancels the IU in the denominator, then the /mg and mg in the numerator cancel, leaving /gm in the denominator. Finally,
        $$frac{1}{1/text{gm}} = text{gm}$$
        so the unit of measurement of the final result is gm. The rest of the calculation is just arithmetic. The only fact you have to know beyond what is in the problem statement is the conversion factor of 1,000 milligrams per gram.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 13 at 15:06









        awkwardawkward

        5,96011022




        5,96011022






























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