A subadditive functional which is not a convex functional
0
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I have been thinking about this for a while now, is there a subadditive functional which is not a convex functional?
functional-analysis
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
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0
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I have been thinking about this for a while now, is there a subadditive functional which is not a convex functional?
functional-analysis
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
$endgroup$
$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
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– saz
Jan 10 at 12:27
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1
$begingroup$
I have been thinking about this for a while now, is there a subadditive functional which is not a convex functional?
functional-analysis
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
$endgroup$
I have been thinking about this for a while now, is there a subadditive functional which is not a convex functional?
functional-analysis
functional-analysis
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
asked Jan 10 at 11:58
Omojola MichealOmojola Micheal
1,824324
1,824324
$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
$endgroup$
– saz
Jan 10 at 12:27
add a comment |
$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
$endgroup$
– saz
Jan 10 at 12:27
$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
$endgroup$
– saz
Jan 10 at 12:27
$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
$endgroup$
– saz
Jan 10 at 12:27
add a comment |
1 Answer
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On the real line $|sin (x+y)| =|sin, x cos, y+cos, x sin ,y| leq |sin (x)|+|sin (y)|$ but $|sin (x)|$ is not convex.
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
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$begingroup$
Sir, you're real good! (+1)
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– Omojola Micheal
Jan 10 at 12:57
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
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active
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votes
2
$begingroup$
On the real line $|sin (x+y)| =|sin, x cos, y+cos, x sin ,y| leq |sin (x)|+|sin (y)|$ but $|sin (x)|$ is not convex.
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
$endgroup$
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
add a comment |
2
$begingroup$
On the real line $|sin (x+y)| =|sin, x cos, y+cos, x sin ,y| leq |sin (x)|+|sin (y)|$ but $|sin (x)|$ is not convex.
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
$endgroup$
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
add a comment |
2
2
2
$begingroup$
On the real line $|sin (x+y)| =|sin, x cos, y+cos, x sin ,y| leq |sin (x)|+|sin (y)|$ but $|sin (x)|$ is not convex.
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
$endgroup$
On the real line $|sin (x+y)| =|sin, x cos, y+cos, x sin ,y| leq |sin (x)|+|sin (y)|$ but $|sin (x)|$ is not convex.
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
answered Jan 10 at 12:21
Kavi Rama MurthyKavi Rama Murthy
54.8k32055
54.8k32055
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
add a comment |
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
$begingroup$
Sir, you're real good! (+1)
$endgroup$
– Omojola Micheal
Jan 10 at 12:57
add a comment |
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$begingroup$
If $T$ is a subadditive functional which is homogeneous of order $1$, then it is convex.
$endgroup$
– saz
Jan 10 at 12:27