Sum of logs $log x + loglog x +…$












1












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Is there a reduction for this infinite sum?



$$log x + loglog x + logloglog x +... = ?$$



for all $x > 0$?










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  • 2




    $begingroup$
    Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
    $endgroup$
    – Tito Eliatron
    Jan 24 at 20:47
















1












$begingroup$


Is there a reduction for this infinite sum?



$$log x + loglog x + logloglog x +... = ?$$



for all $x > 0$?










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
    $endgroup$
    – Tito Eliatron
    Jan 24 at 20:47














1












1








1





$begingroup$


Is there a reduction for this infinite sum?



$$log x + loglog x + logloglog x +... = ?$$



for all $x > 0$?










share|cite|improve this question











$endgroup$




Is there a reduction for this infinite sum?



$$log x + loglog x + logloglog x +... = ?$$



for all $x > 0$?







summation






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share|cite|improve this question













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share|cite|improve this question








edited Jan 24 at 20:46









T. Bongers

23.5k54762




23.5k54762










asked Jan 24 at 20:42









Matt DeleeuwMatt Deleeuw

113




113








  • 2




    $begingroup$
    Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
    $endgroup$
    – Tito Eliatron
    Jan 24 at 20:47














  • 2




    $begingroup$
    Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
    $endgroup$
    – Tito Eliatron
    Jan 24 at 20:47








2




2




$begingroup$
Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
$endgroup$
– Tito Eliatron
Jan 24 at 20:47




$begingroup$
Possible duplicate of In which interval (domain) does the $sum_{n=1}^{infty}log^n(1+x)$ converge absolutely?
$endgroup$
– Tito Eliatron
Jan 24 at 20:47










1 Answer
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The sum diverges with any reasonable interpretation of the logarithms. After all, $log log cdots log x$ is eventually a number that's less than $1$, and the next logarithm gives a negative result. After that, you get a complex result. Continuing in this manner, the terms do not tend to zero.






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    14












    $begingroup$

    The sum diverges with any reasonable interpretation of the logarithms. After all, $log log cdots log x$ is eventually a number that's less than $1$, and the next logarithm gives a negative result. After that, you get a complex result. Continuing in this manner, the terms do not tend to zero.






    share|cite|improve this answer









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      14












      $begingroup$

      The sum diverges with any reasonable interpretation of the logarithms. After all, $log log cdots log x$ is eventually a number that's less than $1$, and the next logarithm gives a negative result. After that, you get a complex result. Continuing in this manner, the terms do not tend to zero.






      share|cite|improve this answer









      $endgroup$
















        14












        14








        14





        $begingroup$

        The sum diverges with any reasonable interpretation of the logarithms. After all, $log log cdots log x$ is eventually a number that's less than $1$, and the next logarithm gives a negative result. After that, you get a complex result. Continuing in this manner, the terms do not tend to zero.






        share|cite|improve this answer









        $endgroup$



        The sum diverges with any reasonable interpretation of the logarithms. After all, $log log cdots log x$ is eventually a number that's less than $1$, and the next logarithm gives a negative result. After that, you get a complex result. Continuing in this manner, the terms do not tend to zero.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 24 at 20:44









        T. BongersT. Bongers

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        23.5k54762






























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