Can this integral (of PDE solution) be solved?












1












$begingroup$


I study the heat equation from the book, Heat Conduction, Third Edition.



By using the method of separation of variables for the boundary condition of



$$BC1: frac{partial T}{partial x} Bigg|_{x=0}= 0$$
$$IC: T(x,t=0)=F(x)$$



the following solution is given,



$$T(x,t) = frac{1}{(4 pi alpha t)^{1/2}} int_{x'=0}^{infty} F(x')Bigglbraceexp left [ -frac{(x-x')^2}{4 alpha t}right ] + exp left [ -frac{(x+x')^2}{4 alpha t}right ] Biggrbrace dx'$$



Surprisingly, the section ends with this equation. I wonder if this integration can be generally solved to obtain a more tangible solution for the temperature.










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
    $endgroup$
    – DaveNine
    Jan 26 at 0:10
















1












$begingroup$


I study the heat equation from the book, Heat Conduction, Third Edition.



By using the method of separation of variables for the boundary condition of



$$BC1: frac{partial T}{partial x} Bigg|_{x=0}= 0$$
$$IC: T(x,t=0)=F(x)$$



the following solution is given,



$$T(x,t) = frac{1}{(4 pi alpha t)^{1/2}} int_{x'=0}^{infty} F(x')Bigglbraceexp left [ -frac{(x-x')^2}{4 alpha t}right ] + exp left [ -frac{(x+x')^2}{4 alpha t}right ] Biggrbrace dx'$$



Surprisingly, the section ends with this equation. I wonder if this integration can be generally solved to obtain a more tangible solution for the temperature.










share|cite|improve this question









$endgroup$








  • 2




    $begingroup$
    In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
    $endgroup$
    – DaveNine
    Jan 26 at 0:10














1












1








1





$begingroup$


I study the heat equation from the book, Heat Conduction, Third Edition.



By using the method of separation of variables for the boundary condition of



$$BC1: frac{partial T}{partial x} Bigg|_{x=0}= 0$$
$$IC: T(x,t=0)=F(x)$$



the following solution is given,



$$T(x,t) = frac{1}{(4 pi alpha t)^{1/2}} int_{x'=0}^{infty} F(x')Bigglbraceexp left [ -frac{(x-x')^2}{4 alpha t}right ] + exp left [ -frac{(x+x')^2}{4 alpha t}right ] Biggrbrace dx'$$



Surprisingly, the section ends with this equation. I wonder if this integration can be generally solved to obtain a more tangible solution for the temperature.










share|cite|improve this question









$endgroup$




I study the heat equation from the book, Heat Conduction, Third Edition.



By using the method of separation of variables for the boundary condition of



$$BC1: frac{partial T}{partial x} Bigg|_{x=0}= 0$$
$$IC: T(x,t=0)=F(x)$$



the following solution is given,



$$T(x,t) = frac{1}{(4 pi alpha t)^{1/2}} int_{x'=0}^{infty} F(x')Bigglbraceexp left [ -frac{(x-x')^2}{4 alpha t}right ] + exp left [ -frac{(x+x')^2}{4 alpha t}right ] Biggrbrace dx'$$



Surprisingly, the section ends with this equation. I wonder if this integration can be generally solved to obtain a more tangible solution for the temperature.







calculus integration pde






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 25 at 20:57









KimiaKimia

314




314








  • 2




    $begingroup$
    In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
    $endgroup$
    – DaveNine
    Jan 26 at 0:10














  • 2




    $begingroup$
    In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
    $endgroup$
    – DaveNine
    Jan 26 at 0:10








2




2




$begingroup$
In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
$endgroup$
– DaveNine
Jan 26 at 0:10




$begingroup$
In general, no. Even more so, you don’t gain anything from the evaluates form that you can’t see from the integral solution.
$endgroup$
– DaveNine
Jan 26 at 0:10










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087614%2fcan-this-integral-of-pde-solution-be-solved%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3087614%2fcan-this-integral-of-pde-solution-be-solved%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Mario Kart Wii

What does “Dominus providebit” mean?

Antonio Litta Visconti Arese