What is meant by homogeneous boundary conditions?
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I am sorry if this is basic knowledge for differential equations but it has been a long time since I took the class, I probably learnt it and forgot about it. I would appreciate the explanation. Thank you!
ordinary-differential-equations analysis
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
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add a comment |
$begingroup$
I am sorry if this is basic knowledge for differential equations but it has been a long time since I took the class, I probably learnt it and forgot about it. I would appreciate the explanation. Thank you!
ordinary-differential-equations analysis
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
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5
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It means the function is zero at the boundaries
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– Alex
Dec 3 '17 at 21:48
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Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51
add a comment |
$begingroup$
I am sorry if this is basic knowledge for differential equations but it has been a long time since I took the class, I probably learnt it and forgot about it. I would appreciate the explanation. Thank you!
ordinary-differential-equations analysis
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
$endgroup$
I am sorry if this is basic knowledge for differential equations but it has been a long time since I took the class, I probably learnt it and forgot about it. I would appreciate the explanation. Thank you!
ordinary-differential-equations analysis
ordinary-differential-equations analysis
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
asked Dec 3 '17 at 21:46
dareToDiffer07dareToDiffer07
2317
2317
5
$begingroup$
It means the function is zero at the boundaries
$endgroup$
– Alex
Dec 3 '17 at 21:48
$begingroup$
Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51
add a comment |
5
$begingroup$
It means the function is zero at the boundaries
$endgroup$
– Alex
Dec 3 '17 at 21:48
$begingroup$
Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51
5
5
$begingroup$
It means the function is zero at the boundaries
$endgroup$
– Alex
Dec 3 '17 at 21:48
$begingroup$
It means the function is zero at the boundaries
$endgroup$
– Alex
Dec 3 '17 at 21:48
$begingroup$
Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51
$begingroup$
Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51
add a comment |
1 Answer
1
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The simplest way to test whether an equation (here the equation for the boundary conditions) is homogeneous is to substitute the zero function and see whether it equals to zero.
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The simplest way to test whether an equation (here the equation for the boundary conditions) is homogeneous is to substitute the zero function and see whether it equals to zero.
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
$endgroup$
add a comment |
$begingroup$
The simplest way to test whether an equation (here the equation for the boundary conditions) is homogeneous is to substitute the zero function and see whether it equals to zero.
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
$endgroup$
add a comment |
$begingroup$
The simplest way to test whether an equation (here the equation for the boundary conditions) is homogeneous is to substitute the zero function and see whether it equals to zero.
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
$endgroup$
The simplest way to test whether an equation (here the equation for the boundary conditions) is homogeneous is to substitute the zero function and see whether it equals to zero.
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
edited Dec 13 '18 at 14:40
LutzL
57.7k42054
57.7k42054
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
answered Oct 10 '18 at 23:42
James B. VidalesJames B. Vidales
91
91
add a comment |
add a comment |
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5
$begingroup$
It means the function is zero at the boundaries
$endgroup$
– Alex
Dec 3 '17 at 21:48
$begingroup$
Makes sense, I was thinking that was the case but was not sure. Thanks!
$endgroup$
– dareToDiffer07
Dec 3 '17 at 21:51