Is there such a series?












0












$begingroup$


Is there a series of the form $$sum_{n=0}^{infty}a_nx^n$$ such that it is convergent on $$-1le x le 1$$ and divergent on all other real number $x$?










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    What happens if $a_n=1/n^2$?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 19:39






  • 2




    $begingroup$
    @SangchuiLee Or something like that, as long as $a_0$ is finite.
    $endgroup$
    – J.G.
    Jan 20 at 19:48










  • $begingroup$
    @SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
    $endgroup$
    – Low Zhen Heng
    Jan 20 at 21:37










  • $begingroup$
    @LowZhenHeng Are you aware of the $p$-series?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 22:08
















0












$begingroup$


Is there a series of the form $$sum_{n=0}^{infty}a_nx^n$$ such that it is convergent on $$-1le x le 1$$ and divergent on all other real number $x$?










share|cite|improve this question











$endgroup$








  • 2




    $begingroup$
    What happens if $a_n=1/n^2$?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 19:39






  • 2




    $begingroup$
    @SangchuiLee Or something like that, as long as $a_0$ is finite.
    $endgroup$
    – J.G.
    Jan 20 at 19:48










  • $begingroup$
    @SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
    $endgroup$
    – Low Zhen Heng
    Jan 20 at 21:37










  • $begingroup$
    @LowZhenHeng Are you aware of the $p$-series?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 22:08














0












0








0


1



$begingroup$


Is there a series of the form $$sum_{n=0}^{infty}a_nx^n$$ such that it is convergent on $$-1le x le 1$$ and divergent on all other real number $x$?










share|cite|improve this question











$endgroup$




Is there a series of the form $$sum_{n=0}^{infty}a_nx^n$$ such that it is convergent on $$-1le x le 1$$ and divergent on all other real number $x$?







sequences-and-series analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 20 at 19:48









J.G.

27.6k22843




27.6k22843










asked Jan 20 at 13:30









Low Zhen HengLow Zhen Heng

11




11








  • 2




    $begingroup$
    What happens if $a_n=1/n^2$?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 19:39






  • 2




    $begingroup$
    @SangchuiLee Or something like that, as long as $a_0$ is finite.
    $endgroup$
    – J.G.
    Jan 20 at 19:48










  • $begingroup$
    @SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
    $endgroup$
    – Low Zhen Heng
    Jan 20 at 21:37










  • $begingroup$
    @LowZhenHeng Are you aware of the $p$-series?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 22:08














  • 2




    $begingroup$
    What happens if $a_n=1/n^2$?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 19:39






  • 2




    $begingroup$
    @SangchuiLee Or something like that, as long as $a_0$ is finite.
    $endgroup$
    – J.G.
    Jan 20 at 19:48










  • $begingroup$
    @SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
    $endgroup$
    – Low Zhen Heng
    Jan 20 at 21:37










  • $begingroup$
    @LowZhenHeng Are you aware of the $p$-series?
    $endgroup$
    – Sangchul Lee
    Jan 20 at 22:08








2




2




$begingroup$
What happens if $a_n=1/n^2$?
$endgroup$
– Sangchul Lee
Jan 20 at 19:39




$begingroup$
What happens if $a_n=1/n^2$?
$endgroup$
– Sangchul Lee
Jan 20 at 19:39




2




2




$begingroup$
@SangchuiLee Or something like that, as long as $a_0$ is finite.
$endgroup$
– J.G.
Jan 20 at 19:48




$begingroup$
@SangchuiLee Or something like that, as long as $a_0$ is finite.
$endgroup$
– J.G.
Jan 20 at 19:48












$begingroup$
@SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
$endgroup$
– Low Zhen Heng
Jan 20 at 21:37




$begingroup$
@SangchulLee but isn't $frac{1}{n^2}$ similar to the harmonic series which is an infinite series?
$endgroup$
– Low Zhen Heng
Jan 20 at 21:37












$begingroup$
@LowZhenHeng Are you aware of the $p$-series?
$endgroup$
– Sangchul Lee
Jan 20 at 22:08




$begingroup$
@LowZhenHeng Are you aware of the $p$-series?
$endgroup$
– Sangchul Lee
Jan 20 at 22:08










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3080577%2fis-there-such-a-series%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3080577%2fis-there-such-a-series%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Mario Kart Wii

What does “Dominus providebit” mean?

File:Tiny Toon Adventures Wacky Sports JP Title.png