Simple Expression Related to Mutual Information
One way to define the mutual information is
$I(X;Y) = H(X) - H(X|Y)$
I have found it useful to look the related quantity
$?(X;Y=y) = H(X) - H(X|Y=y)$
That is, we look at how much the entropy of $X$ is decreased given a particular outcome $y$ for $Y$.
It is not hard to see that the mutual information is regained on expectation on $Y$, so that we have
$E_Y[?(X;Y=y)] \
= sum_y p(y)(H(X) - H(X|Y=y)) \
= H(X) - sum_y p(y)H(X|Y=y) \
= H(X) - H(X|Y) \
= I(X;Y)$
My question: does my $?(X;Y=y)$ function have a name? Or a standardized notation?
Note it's not the same as pointwise mutual information: rather, I think this would be the expectation of pointwise mutual information, but only on $X$ (rather than both variables). So it's "in between" the regular mutual information and the pointwise version.
statistics information-theory entropy
add a comment |
One way to define the mutual information is
$I(X;Y) = H(X) - H(X|Y)$
I have found it useful to look the related quantity
$?(X;Y=y) = H(X) - H(X|Y=y)$
That is, we look at how much the entropy of $X$ is decreased given a particular outcome $y$ for $Y$.
It is not hard to see that the mutual information is regained on expectation on $Y$, so that we have
$E_Y[?(X;Y=y)] \
= sum_y p(y)(H(X) - H(X|Y=y)) \
= H(X) - sum_y p(y)H(X|Y=y) \
= H(X) - H(X|Y) \
= I(X;Y)$
My question: does my $?(X;Y=y)$ function have a name? Or a standardized notation?
Note it's not the same as pointwise mutual information: rather, I think this would be the expectation of pointwise mutual information, but only on $X$ (rather than both variables). So it's "in between" the regular mutual information and the pointwise version.
statistics information-theory entropy
add a comment |
One way to define the mutual information is
$I(X;Y) = H(X) - H(X|Y)$
I have found it useful to look the related quantity
$?(X;Y=y) = H(X) - H(X|Y=y)$
That is, we look at how much the entropy of $X$ is decreased given a particular outcome $y$ for $Y$.
It is not hard to see that the mutual information is regained on expectation on $Y$, so that we have
$E_Y[?(X;Y=y)] \
= sum_y p(y)(H(X) - H(X|Y=y)) \
= H(X) - sum_y p(y)H(X|Y=y) \
= H(X) - H(X|Y) \
= I(X;Y)$
My question: does my $?(X;Y=y)$ function have a name? Or a standardized notation?
Note it's not the same as pointwise mutual information: rather, I think this would be the expectation of pointwise mutual information, but only on $X$ (rather than both variables). So it's "in between" the regular mutual information and the pointwise version.
statistics information-theory entropy
One way to define the mutual information is
$I(X;Y) = H(X) - H(X|Y)$
I have found it useful to look the related quantity
$?(X;Y=y) = H(X) - H(X|Y=y)$
That is, we look at how much the entropy of $X$ is decreased given a particular outcome $y$ for $Y$.
It is not hard to see that the mutual information is regained on expectation on $Y$, so that we have
$E_Y[?(X;Y=y)] \
= sum_y p(y)(H(X) - H(X|Y=y)) \
= H(X) - sum_y p(y)H(X|Y=y) \
= H(X) - H(X|Y) \
= I(X;Y)$
My question: does my $?(X;Y=y)$ function have a name? Or a standardized notation?
Note it's not the same as pointwise mutual information: rather, I think this would be the expectation of pointwise mutual information, but only on $X$ (rather than both variables). So it's "in between" the regular mutual information and the pointwise version.
statistics information-theory entropy
statistics information-theory entropy
asked yesterday
Mike Battaglia
1,2581126
1,2581126
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3062475%2fsimple-expression-related-to-mutual-information%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3062475%2fsimple-expression-related-to-mutual-information%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown