3-D Rotation Matrix [on hold]
Question says what constraints must the elements (R ij) of three dimensional rotation matrix satisfy in order to preserve the length of a vector A(for all vectors A).
I don't get why, at all would axes transformations change the magnitude of a vector?
vectors matrix-calculus geometric-transformation matrix-analysis
put on hold as off-topic by Saad, Leucippus, user91500, Paul Frost, José Carlos Santos 19 hours ago
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- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Leucippus, user91500, Paul Frost, José Carlos Santos
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Question says what constraints must the elements (R ij) of three dimensional rotation matrix satisfy in order to preserve the length of a vector A(for all vectors A).
I don't get why, at all would axes transformations change the magnitude of a vector?
vectors matrix-calculus geometric-transformation matrix-analysis
put on hold as off-topic by Saad, Leucippus, user91500, Paul Frost, José Carlos Santos 19 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Leucippus, user91500, Paul Frost, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday
add a comment |
Question says what constraints must the elements (R ij) of three dimensional rotation matrix satisfy in order to preserve the length of a vector A(for all vectors A).
I don't get why, at all would axes transformations change the magnitude of a vector?
vectors matrix-calculus geometric-transformation matrix-analysis
Question says what constraints must the elements (R ij) of three dimensional rotation matrix satisfy in order to preserve the length of a vector A(for all vectors A).
I don't get why, at all would axes transformations change the magnitude of a vector?
vectors matrix-calculus geometric-transformation matrix-analysis
vectors matrix-calculus geometric-transformation matrix-analysis
asked yesterday
Onkar Singh
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put on hold as off-topic by Saad, Leucippus, user91500, Paul Frost, José Carlos Santos 19 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Leucippus, user91500, Paul Frost, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Saad, Leucippus, user91500, Paul Frost, José Carlos Santos 19 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Leucippus, user91500, Paul Frost, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday
add a comment |
Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday
Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday
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Well, consider 3D transformation matrix $$mathbf{M} = left [ begin{matrix} 2 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 2 end{matrix} right ]$$It is a transformation: it doubles the length of all nonzero vectors.
– Nominal Animal
yesterday
I was looking for proper sources, but couldn't find any, so instead of providing an answer, I'll just comment that pure rotation matrices are orthonormal: all row vectors form an orthonormal basis set, and all column vectors form an orthonormal basis set. The result of those requirements is that such matrices have determinant +1, and the inverse of such matrices is equal to their transpose.
– Nominal Animal
yesterday