Simple example of a function that is convex but not jointly convex?












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Can a function be convex is each of it's arguments but not jointly convex? If yes, please provide an example and if not, could you please provide a proof?



The definition of joint convexity I use is: For any function $f(x,y)$, we have $f(lambda x_1 + (1-lambda)x_2, lambda y_1 + (1-lambda)y_2) leq lambda f(x_1, y_1) + (1-lambda)f(x_2,y_2)$.



Convex in each argument implies $f(lambda x_1 + (1-lambda)x_2, y) leq lambda f(x_1, y) + (1-lambda)f(x_2, y)$ and similar for $y$



Also, please do include if it makes sense to take a strict inequalities in the convexity definition as well. Thank you.










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  • 3




    What about $f(x,y)=xy$?
    – A.Γ.
    2 days ago










  • What is a jointly convex function?
    – Mostafa Ayaz
    2 days ago
















0














Can a function be convex is each of it's arguments but not jointly convex? If yes, please provide an example and if not, could you please provide a proof?



The definition of joint convexity I use is: For any function $f(x,y)$, we have $f(lambda x_1 + (1-lambda)x_2, lambda y_1 + (1-lambda)y_2) leq lambda f(x_1, y_1) + (1-lambda)f(x_2,y_2)$.



Convex in each argument implies $f(lambda x_1 + (1-lambda)x_2, y) leq lambda f(x_1, y) + (1-lambda)f(x_2, y)$ and similar for $y$



Also, please do include if it makes sense to take a strict inequalities in the convexity definition as well. Thank you.










share|cite|improve this question




















  • 3




    What about $f(x,y)=xy$?
    – A.Γ.
    2 days ago










  • What is a jointly convex function?
    – Mostafa Ayaz
    2 days ago














0












0








0







Can a function be convex is each of it's arguments but not jointly convex? If yes, please provide an example and if not, could you please provide a proof?



The definition of joint convexity I use is: For any function $f(x,y)$, we have $f(lambda x_1 + (1-lambda)x_2, lambda y_1 + (1-lambda)y_2) leq lambda f(x_1, y_1) + (1-lambda)f(x_2,y_2)$.



Convex in each argument implies $f(lambda x_1 + (1-lambda)x_2, y) leq lambda f(x_1, y) + (1-lambda)f(x_2, y)$ and similar for $y$



Also, please do include if it makes sense to take a strict inequalities in the convexity definition as well. Thank you.










share|cite|improve this question















Can a function be convex is each of it's arguments but not jointly convex? If yes, please provide an example and if not, could you please provide a proof?



The definition of joint convexity I use is: For any function $f(x,y)$, we have $f(lambda x_1 + (1-lambda)x_2, lambda y_1 + (1-lambda)y_2) leq lambda f(x_1, y_1) + (1-lambda)f(x_2,y_2)$.



Convex in each argument implies $f(lambda x_1 + (1-lambda)x_2, y) leq lambda f(x_1, y) + (1-lambda)f(x_2, y)$ and similar for $y$



Also, please do include if it makes sense to take a strict inequalities in the convexity definition as well. Thank you.







functions convex-analysis






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edited 2 days ago







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  • 3




    What about $f(x,y)=xy$?
    – A.Γ.
    2 days ago










  • What is a jointly convex function?
    – Mostafa Ayaz
    2 days ago














  • 3




    What about $f(x,y)=xy$?
    – A.Γ.
    2 days ago










  • What is a jointly convex function?
    – Mostafa Ayaz
    2 days ago








3




3




What about $f(x,y)=xy$?
– A.Γ.
2 days ago




What about $f(x,y)=xy$?
– A.Γ.
2 days ago












What is a jointly convex function?
– Mostafa Ayaz
2 days ago




What is a jointly convex function?
– Mostafa Ayaz
2 days ago










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