Is there any way for the second derivative of a circle to be constant? [on hold]
While trying to find the second derivative of a circle, I got to the result: 1/sin^2(t). However, my hypothesis was that the circle has the uniform shape because a second derivative is 1. How can I still make this connection? Is the result I got incorrect?
calculus derivatives circle curves
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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put on hold as unclear what you're asking by José Carlos Santos, Hans Lundmark, Abcd, Cesareo, amWhy Jan 6 at 15:10
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
While trying to find the second derivative of a circle, I got to the result: 1/sin^2(t). However, my hypothesis was that the circle has the uniform shape because a second derivative is 1. How can I still make this connection? Is the result I got incorrect?
calculus derivatives circle curves
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as unclear what you're asking by José Carlos Santos, Hans Lundmark, Abcd, Cesareo, amWhy Jan 6 at 15:10
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
1
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42
add a comment |
While trying to find the second derivative of a circle, I got to the result: 1/sin^2(t). However, my hypothesis was that the circle has the uniform shape because a second derivative is 1. How can I still make this connection? Is the result I got incorrect?
calculus derivatives circle curves
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
While trying to find the second derivative of a circle, I got to the result: 1/sin^2(t). However, my hypothesis was that the circle has the uniform shape because a second derivative is 1. How can I still make this connection? Is the result I got incorrect?
calculus derivatives circle curves
calculus derivatives circle curves
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
asked Jan 6 at 11:55
Valeria BujariValeria Bujari
6
6
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Valeria Bujari is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as unclear what you're asking by José Carlos Santos, Hans Lundmark, Abcd, Cesareo, amWhy Jan 6 at 15:10
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as unclear what you're asking by José Carlos Santos, Hans Lundmark, Abcd, Cesareo, amWhy Jan 6 at 15:10
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
2
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
1
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42
add a comment |
2
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
1
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42
2
2
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
1
1
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42
add a comment |
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2
It is difficult to guess what you are saying. Derivatives are for functions and a circle is not a function.
– Kavi Rama Murthy
Jan 6 at 12:01
Welcome to MSE. Please read this text about how to ask a good question.
– José Carlos Santos
Jan 6 at 12:01
1
I think you're looking for the "curvature" of the circle, which is related to the second derivative. Write the circle in parametric equations and then compute the curvature and you'll get a constant.
– B. Goddard
Jan 6 at 12:42