How to compute $mathbb{E}[X_{s}^{2}e^{lambda X_{s}}]$ where $X_s$ is a Brownian motion with drift $s$?












3














I'm working on a problem and at a certain point I ran into the problem as described in the title. We have that ${W_t,tgeq 0}$ is a Brownian motion and $mathscr{F}_t$ is the corresponding filtration. We have that $mu>0$ is given in the process ${X_t,tgeq 0}$ defined via $X_t:=mu t+W_t$.



I don't want to post the full problem I was solving yet, rather I'd like to know if what I ended up with is even solvable, because if not, I'll know I'm definitely wrong.



As posted in the title, I came at a point where I was left to compute the expectation:




$mathbb{E}[X_{s}^{2}e^{lambda X_{s}}]$




Earlier in the exercise (it consisted of multiple parts) I used the moment generating function for the normal distribution. However, as far as I know, I cannot take the $X_{s}^{2}$ out of the expectation, stopping me from applying the moment generating function.



Is this expectation solvable in a relatively easy way? If not, I'll know I'm wrong and start over.










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  • 6




    Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
    – Did
    yesterday










  • @Did That works. Thank you very much!
    – S. Crim
    20 hours ago
















3














I'm working on a problem and at a certain point I ran into the problem as described in the title. We have that ${W_t,tgeq 0}$ is a Brownian motion and $mathscr{F}_t$ is the corresponding filtration. We have that $mu>0$ is given in the process ${X_t,tgeq 0}$ defined via $X_t:=mu t+W_t$.



I don't want to post the full problem I was solving yet, rather I'd like to know if what I ended up with is even solvable, because if not, I'll know I'm definitely wrong.



As posted in the title, I came at a point where I was left to compute the expectation:




$mathbb{E}[X_{s}^{2}e^{lambda X_{s}}]$




Earlier in the exercise (it consisted of multiple parts) I used the moment generating function for the normal distribution. However, as far as I know, I cannot take the $X_{s}^{2}$ out of the expectation, stopping me from applying the moment generating function.



Is this expectation solvable in a relatively easy way? If not, I'll know I'm wrong and start over.










share|cite|improve this question


















  • 6




    Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
    – Did
    yesterday










  • @Did That works. Thank you very much!
    – S. Crim
    20 hours ago














3












3








3







I'm working on a problem and at a certain point I ran into the problem as described in the title. We have that ${W_t,tgeq 0}$ is a Brownian motion and $mathscr{F}_t$ is the corresponding filtration. We have that $mu>0$ is given in the process ${X_t,tgeq 0}$ defined via $X_t:=mu t+W_t$.



I don't want to post the full problem I was solving yet, rather I'd like to know if what I ended up with is even solvable, because if not, I'll know I'm definitely wrong.



As posted in the title, I came at a point where I was left to compute the expectation:




$mathbb{E}[X_{s}^{2}e^{lambda X_{s}}]$




Earlier in the exercise (it consisted of multiple parts) I used the moment generating function for the normal distribution. However, as far as I know, I cannot take the $X_{s}^{2}$ out of the expectation, stopping me from applying the moment generating function.



Is this expectation solvable in a relatively easy way? If not, I'll know I'm wrong and start over.










share|cite|improve this question













I'm working on a problem and at a certain point I ran into the problem as described in the title. We have that ${W_t,tgeq 0}$ is a Brownian motion and $mathscr{F}_t$ is the corresponding filtration. We have that $mu>0$ is given in the process ${X_t,tgeq 0}$ defined via $X_t:=mu t+W_t$.



I don't want to post the full problem I was solving yet, rather I'd like to know if what I ended up with is even solvable, because if not, I'll know I'm definitely wrong.



As posted in the title, I came at a point where I was left to compute the expectation:




$mathbb{E}[X_{s}^{2}e^{lambda X_{s}}]$




Earlier in the exercise (it consisted of multiple parts) I used the moment generating function for the normal distribution. However, as far as I know, I cannot take the $X_{s}^{2}$ out of the expectation, stopping me from applying the moment generating function.



Is this expectation solvable in a relatively easy way? If not, I'll know I'm wrong and start over.







probability-theory stochastic-processes brownian-motion expected-value






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




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asked yesterday









S. Crim

13212




13212








  • 6




    Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
    – Did
    yesterday










  • @Did That works. Thank you very much!
    – S. Crim
    20 hours ago














  • 6




    Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
    – Did
    yesterday










  • @Did That works. Thank you very much!
    – S. Crim
    20 hours ago








6




6




Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
– Did
yesterday




Differentiate twice $E(e^{lambda X_t})$ with respect to $lambda$.
– Did
yesterday












@Did That works. Thank you very much!
– S. Crim
20 hours ago




@Did That works. Thank you very much!
– S. Crim
20 hours ago










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