How can i converge my leapfrog code
$begingroup$
in leapfrog method i should compute this discretization equation
$$frac{u_i^{n+1}-u_i^{n-1}}{2∆t}=-cfrac{u_{i+1}^n-u_{i-1}^n}{2∆x}$$
my major problem is that how can I compute the $u_i^{n-1}$ term ???
thanks a lot
pde finite-difference-methods
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add a comment |
$begingroup$
in leapfrog method i should compute this discretization equation
$$frac{u_i^{n+1}-u_i^{n-1}}{2∆t}=-cfrac{u_{i+1}^n-u_{i-1}^n}{2∆x}$$
my major problem is that how can I compute the $u_i^{n-1}$ term ???
thanks a lot
pde finite-difference-methods
$endgroup$
$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
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– Ricky Tensor
Jan 10 at 6:38
add a comment |
$begingroup$
in leapfrog method i should compute this discretization equation
$$frac{u_i^{n+1}-u_i^{n-1}}{2∆t}=-cfrac{u_{i+1}^n-u_{i-1}^n}{2∆x}$$
my major problem is that how can I compute the $u_i^{n-1}$ term ???
thanks a lot
pde finite-difference-methods
$endgroup$
in leapfrog method i should compute this discretization equation
$$frac{u_i^{n+1}-u_i^{n-1}}{2∆t}=-cfrac{u_{i+1}^n-u_{i-1}^n}{2∆x}$$
my major problem is that how can I compute the $u_i^{n-1}$ term ???
thanks a lot
pde finite-difference-methods
pde finite-difference-methods
edited Jan 10 at 7:47
Amin Dpp
asked Jan 10 at 6:21
Amin DppAmin Dpp
12
12
$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
$endgroup$
– Ricky Tensor
Jan 10 at 6:38
add a comment |
$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
$endgroup$
– Ricky Tensor
Jan 10 at 6:38
$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
$endgroup$
– Ricky Tensor
Jan 10 at 6:38
$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
$endgroup$
– Ricky Tensor
Jan 10 at 6:38
add a comment |
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$begingroup$
This question is nearly impossible to read in its current state, and appears to be a duplicate of another that you posted just recently. StackExchange supports editing of questions, so you can modify your question to fix formatting or add clarification. You don't need to ask a whole new copy of a question each time you want to change something. :) Also, a bit more context and explanation wouldn't go amiss here.
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– Ricky Tensor
Jan 10 at 6:38