JSON Query in PostgreSQL












2















I have a table:



CREATE TABLE foo (id,lat,lon)
AS VALUES
( 1, 34, 45 ),
( 1, 45, 56 ),
( 2, 56, 67 ),
( 2, 58, 64 );


How can I get JSON like that:



{"1":[[34,45],[45,56]], "2":[[56,67],[58,64]]}









share|improve this question

























  • This has nothing to do with spatial, or geojson.

    – Evan Carroll
    Jan 11 at 23:21











  • The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

    – Evan Carroll
    Jan 11 at 23:29













  • I have an ability to save them like Postgis geom::point, can u provide this solution also?

    – delkov
    Jan 11 at 23:36











  • no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

    – Evan Carroll
    Jan 11 at 23:44
















2















I have a table:



CREATE TABLE foo (id,lat,lon)
AS VALUES
( 1, 34, 45 ),
( 1, 45, 56 ),
( 2, 56, 67 ),
( 2, 58, 64 );


How can I get JSON like that:



{"1":[[34,45],[45,56]], "2":[[56,67],[58,64]]}









share|improve this question

























  • This has nothing to do with spatial, or geojson.

    – Evan Carroll
    Jan 11 at 23:21











  • The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

    – Evan Carroll
    Jan 11 at 23:29













  • I have an ability to save them like Postgis geom::point, can u provide this solution also?

    – delkov
    Jan 11 at 23:36











  • no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

    – Evan Carroll
    Jan 11 at 23:44














2












2








2


1






I have a table:



CREATE TABLE foo (id,lat,lon)
AS VALUES
( 1, 34, 45 ),
( 1, 45, 56 ),
( 2, 56, 67 ),
( 2, 58, 64 );


How can I get JSON like that:



{"1":[[34,45],[45,56]], "2":[[56,67],[58,64]]}









share|improve this question
















I have a table:



CREATE TABLE foo (id,lat,lon)
AS VALUES
( 1, 34, 45 ),
( 1, 45, 56 ),
( 2, 56, 67 ),
( 2, 58, 64 );


How can I get JSON like that:



{"1":[[34,45],[45,56]], "2":[[56,67],[58,64]]}






postgresql json






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 11 at 23:28









Evan Carroll

31.8k967215




31.8k967215










asked Jan 11 at 22:46









delkovdelkov

626




626













  • This has nothing to do with spatial, or geojson.

    – Evan Carroll
    Jan 11 at 23:21











  • The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

    – Evan Carroll
    Jan 11 at 23:29













  • I have an ability to save them like Postgis geom::point, can u provide this solution also?

    – delkov
    Jan 11 at 23:36











  • no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

    – Evan Carroll
    Jan 11 at 23:44



















  • This has nothing to do with spatial, or geojson.

    – Evan Carroll
    Jan 11 at 23:21











  • The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

    – Evan Carroll
    Jan 11 at 23:29













  • I have an ability to save them like Postgis geom::point, can u provide this solution also?

    – delkov
    Jan 11 at 23:36











  • no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

    – Evan Carroll
    Jan 11 at 23:44

















This has nothing to do with spatial, or geojson.

– Evan Carroll
Jan 11 at 23:21





This has nothing to do with spatial, or geojson.

– Evan Carroll
Jan 11 at 23:21













The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

– Evan Carroll
Jan 11 at 23:29







The spatial solution is actually much easier, but then you don't store points in a table. You store either lines or MULTIPOINTs. and you can use PostGIS's ST_ToGeoJSON

– Evan Carroll
Jan 11 at 23:29















I have an ability to save them like Postgis geom::point, can u provide this solution also?

– delkov
Jan 11 at 23:36





I have an ability to save them like Postgis geom::point, can u provide this solution also?

– delkov
Jan 11 at 23:36













no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

– Evan Carroll
Jan 11 at 23:44





no, it's a totally different question that requires you store a GEOGRAPHY or GEOMETRY type on the table, install the PostGIS extension, save all your points in a totally different format, and then query the table differently. It would take 25 pages for me to go over that setup and explain what's happening. I do however HIGHLY suggest the PostGIS in Action book if you're looking for direction and you want to learn GIS.

– Evan Carroll
Jan 11 at 23:44










1 Answer
1






active

oldest

votes


















4














First you do something like this,



SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
FROM foo
GROUP BY id;


That aggregates the values into an JSON Array. You get



 id |          j           
----+----------------------
2 | [[56, 67], [58, 64]]
1 | [[34, 45], [45, 56]]


From there you need to build an JSON Object..



SELECT jsonb_object_agg(id,j)
FROM (
SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
FROM foo
GROUP BY id
) AS t;





share|improve this answer























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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    First you do something like this,



    SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
    FROM foo
    GROUP BY id;


    That aggregates the values into an JSON Array. You get



     id |          j           
    ----+----------------------
    2 | [[56, 67], [58, 64]]
    1 | [[34, 45], [45, 56]]


    From there you need to build an JSON Object..



    SELECT jsonb_object_agg(id,j)
    FROM (
    SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
    FROM foo
    GROUP BY id
    ) AS t;





    share|improve this answer




























      4














      First you do something like this,



      SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
      FROM foo
      GROUP BY id;


      That aggregates the values into an JSON Array. You get



       id |          j           
      ----+----------------------
      2 | [[56, 67], [58, 64]]
      1 | [[34, 45], [45, 56]]


      From there you need to build an JSON Object..



      SELECT jsonb_object_agg(id,j)
      FROM (
      SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
      FROM foo
      GROUP BY id
      ) AS t;





      share|improve this answer


























        4












        4








        4







        First you do something like this,



        SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
        FROM foo
        GROUP BY id;


        That aggregates the values into an JSON Array. You get



         id |          j           
        ----+----------------------
        2 | [[56, 67], [58, 64]]
        1 | [[34, 45], [45, 56]]


        From there you need to build an JSON Object..



        SELECT jsonb_object_agg(id,j)
        FROM (
        SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
        FROM foo
        GROUP BY id
        ) AS t;





        share|improve this answer













        First you do something like this,



        SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
        FROM foo
        GROUP BY id;


        That aggregates the values into an JSON Array. You get



         id |          j           
        ----+----------------------
        2 | [[56, 67], [58, 64]]
        1 | [[34, 45], [45, 56]]


        From there you need to build an JSON Object..



        SELECT jsonb_object_agg(id,j)
        FROM (
        SELECT id, jsonb_agg(jsonb_build_array(lat,lon)) AS j
        FROM foo
        GROUP BY id
        ) AS t;






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 11 at 23:28









        Evan CarrollEvan Carroll

        31.8k967215




        31.8k967215






























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