In commutative ring, flat is equivalent to locally free












3












$begingroup$


In wikipedia https://en.m.wikipedia.org/wiki/Flat_module , particularly Case of commutative rings, they say that



"In a commutative ring, a finitely generated module is flat if and only if it is locally free, i.e. $M_P$ is free for all prime ideals"



In Atiyah anf MacDonald's commutative algebra, they proved that



"In a commutative ring, a finitely generated module is flat if and only if it is locally flat, i.e. $M_P$ is flat for all prime ideals"



So does it mean "$M_P$ is free iff $M_P$ is flat"? How? $R_P$ is only local while we need it to be also Noetherian for the statement to be true?



Thank you for your help










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
    $endgroup$
    – Qiaochu Yuan
    Jan 17 '18 at 9:11










  • $begingroup$
    See mathoverflow.net/questions/33522/flatness-and-local-freeness .
    $endgroup$
    – darij grinberg
    Jan 13 at 13:14
















3












$begingroup$


In wikipedia https://en.m.wikipedia.org/wiki/Flat_module , particularly Case of commutative rings, they say that



"In a commutative ring, a finitely generated module is flat if and only if it is locally free, i.e. $M_P$ is free for all prime ideals"



In Atiyah anf MacDonald's commutative algebra, they proved that



"In a commutative ring, a finitely generated module is flat if and only if it is locally flat, i.e. $M_P$ is flat for all prime ideals"



So does it mean "$M_P$ is free iff $M_P$ is flat"? How? $R_P$ is only local while we need it to be also Noetherian for the statement to be true?



Thank you for your help










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
    $endgroup$
    – Qiaochu Yuan
    Jan 17 '18 at 9:11










  • $begingroup$
    See mathoverflow.net/questions/33522/flatness-and-local-freeness .
    $endgroup$
    – darij grinberg
    Jan 13 at 13:14














3












3








3


1



$begingroup$


In wikipedia https://en.m.wikipedia.org/wiki/Flat_module , particularly Case of commutative rings, they say that



"In a commutative ring, a finitely generated module is flat if and only if it is locally free, i.e. $M_P$ is free for all prime ideals"



In Atiyah anf MacDonald's commutative algebra, they proved that



"In a commutative ring, a finitely generated module is flat if and only if it is locally flat, i.e. $M_P$ is flat for all prime ideals"



So does it mean "$M_P$ is free iff $M_P$ is flat"? How? $R_P$ is only local while we need it to be also Noetherian for the statement to be true?



Thank you for your help










share|cite|improve this question









$endgroup$




In wikipedia https://en.m.wikipedia.org/wiki/Flat_module , particularly Case of commutative rings, they say that



"In a commutative ring, a finitely generated module is flat if and only if it is locally free, i.e. $M_P$ is free for all prime ideals"



In Atiyah anf MacDonald's commutative algebra, they proved that



"In a commutative ring, a finitely generated module is flat if and only if it is locally flat, i.e. $M_P$ is flat for all prime ideals"



So does it mean "$M_P$ is free iff $M_P$ is flat"? How? $R_P$ is only local while we need it to be also Noetherian for the statement to be true?



Thank you for your help







commutative-algebra






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 17 '18 at 8:08









chí trung châuchí trung châu

1,0741725




1,0741725








  • 1




    $begingroup$
    I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
    $endgroup$
    – Qiaochu Yuan
    Jan 17 '18 at 9:11










  • $begingroup$
    See mathoverflow.net/questions/33522/flatness-and-local-freeness .
    $endgroup$
    – darij grinberg
    Jan 13 at 13:14














  • 1




    $begingroup$
    I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
    $endgroup$
    – Qiaochu Yuan
    Jan 17 '18 at 9:11










  • $begingroup$
    See mathoverflow.net/questions/33522/flatness-and-local-freeness .
    $endgroup$
    – darij grinberg
    Jan 13 at 13:14








1




1




$begingroup$
I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
$endgroup$
– Qiaochu Yuan
Jan 17 '18 at 9:11




$begingroup$
I also don't know how to remove the Noetherian hypothesis, so I suspect the first statement is false with no Noetherian hypotheses.
$endgroup$
– Qiaochu Yuan
Jan 17 '18 at 9:11












$begingroup$
See mathoverflow.net/questions/33522/flatness-and-local-freeness .
$endgroup$
– darij grinberg
Jan 13 at 13:14




$begingroup$
See mathoverflow.net/questions/33522/flatness-and-local-freeness .
$endgroup$
– darij grinberg
Jan 13 at 13:14










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