In Leibniz notation, how do you write the second derivative of y with respect to the square of x?












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I know how to write in Leibniz notation for more plain-vanilla expressions like the the second derivative of y with respect to x. But I am not sure how to write, in Leibniz notation, the second derivative of y with respect to expressions more complex than a single variable. In, for example, the second derivative of y with respect to the square of x, would I just use parentheses and write $dy^2/d(x^2)^2$?










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    $begingroup$
    It’s $d^2y$, not $dy^2$.
    $endgroup$
    – KM101
    Jan 7 at 18:50


















1












$begingroup$


I know how to write in Leibniz notation for more plain-vanilla expressions like the the second derivative of y with respect to x. But I am not sure how to write, in Leibniz notation, the second derivative of y with respect to expressions more complex than a single variable. In, for example, the second derivative of y with respect to the square of x, would I just use parentheses and write $dy^2/d(x^2)^2$?










share|cite|improve this question









New contributor




resplaine is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    It’s $d^2y$, not $dy^2$.
    $endgroup$
    – KM101
    Jan 7 at 18:50
















1












1








1





$begingroup$


I know how to write in Leibniz notation for more plain-vanilla expressions like the the second derivative of y with respect to x. But I am not sure how to write, in Leibniz notation, the second derivative of y with respect to expressions more complex than a single variable. In, for example, the second derivative of y with respect to the square of x, would I just use parentheses and write $dy^2/d(x^2)^2$?










share|cite|improve this question









New contributor




resplaine is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I know how to write in Leibniz notation for more plain-vanilla expressions like the the second derivative of y with respect to x. But I am not sure how to write, in Leibniz notation, the second derivative of y with respect to expressions more complex than a single variable. In, for example, the second derivative of y with respect to the square of x, would I just use parentheses and write $dy^2/d(x^2)^2$?







calculus derivatives notation






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edited Jan 7 at 18:50









gt6989b

33.4k22452




33.4k22452






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asked Jan 7 at 18:48









resplaineresplaine

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resplaine is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 1




    $begingroup$
    It’s $d^2y$, not $dy^2$.
    $endgroup$
    – KM101
    Jan 7 at 18:50
















  • 1




    $begingroup$
    It’s $d^2y$, not $dy^2$.
    $endgroup$
    – KM101
    Jan 7 at 18:50










1




1




$begingroup$
It’s $d^2y$, not $dy^2$.
$endgroup$
– KM101
Jan 7 at 18:50






$begingroup$
It’s $d^2y$, not $dy^2$.
$endgroup$
– KM101
Jan 7 at 18:50












1 Answer
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$begingroup$

Indeed, if $z=x^2$ and you need
$$
frac{d^2y}{dz^2} = frac{d^2 y}{dleft(x^2right)^2}
$$






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  • $begingroup$
    Thanks so much! That's just the answer I needed.
    $endgroup$
    – resplaine
    Jan 7 at 18:58











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Indeed, if $z=x^2$ and you need
$$
frac{d^2y}{dz^2} = frac{d^2 y}{dleft(x^2right)^2}
$$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks so much! That's just the answer I needed.
    $endgroup$
    – resplaine
    Jan 7 at 18:58
















3












$begingroup$

Indeed, if $z=x^2$ and you need
$$
frac{d^2y}{dz^2} = frac{d^2 y}{dleft(x^2right)^2}
$$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thanks so much! That's just the answer I needed.
    $endgroup$
    – resplaine
    Jan 7 at 18:58














3












3








3





$begingroup$

Indeed, if $z=x^2$ and you need
$$
frac{d^2y}{dz^2} = frac{d^2 y}{dleft(x^2right)^2}
$$






share|cite|improve this answer









$endgroup$



Indeed, if $z=x^2$ and you need
$$
frac{d^2y}{dz^2} = frac{d^2 y}{dleft(x^2right)^2}
$$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jan 7 at 18:50









gt6989bgt6989b

33.4k22452




33.4k22452












  • $begingroup$
    Thanks so much! That's just the answer I needed.
    $endgroup$
    – resplaine
    Jan 7 at 18:58


















  • $begingroup$
    Thanks so much! That's just the answer I needed.
    $endgroup$
    – resplaine
    Jan 7 at 18:58
















$begingroup$
Thanks so much! That's just the answer I needed.
$endgroup$
– resplaine
Jan 7 at 18:58




$begingroup$
Thanks so much! That's just the answer I needed.
$endgroup$
– resplaine
Jan 7 at 18:58










resplaine is a new contributor. Be nice, and check out our Code of Conduct.










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