Understanding Kronecker Delta Function for Faulhaber's Formula












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I am trying to use Faulhaber's formula to determine partial sums of a power series.



Faulhaber's formula is given by



$sum_{k=1}^{n}{k^{p}} = frac{1}{p+1}sum_{i=1}^{p+1}{(-1)^{delta_ip}{p+1choose i}}B_{p+1-i}n^{i}$ where $delta_ip$ is the Kronecker delta function and $B_{p+1-i}$ is the $p+1-i$th Bernoulli number.



My question is, what do I use for $i$ in the Kronecker delta function when using this formula?



For example, I am trying to derive the partial sum of the power series $sum_{k=1}^{n}{k^2}$ but I don't see what I would use for $i$.










share|cite|improve this question
























  • You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
    – callculus
    2 days ago












  • Thank you @callculus. Yes, I will make that edit.
    – Gnumbertester
    2 days ago










  • $delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
    – Andy Walls
    2 days ago












  • @AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
    – Gnumbertester
    2 days ago








  • 1




    It is the index of the summation on the RHS, i.e. the index of each term in the summation.
    – Andy Walls
    2 days ago


















0














I am trying to use Faulhaber's formula to determine partial sums of a power series.



Faulhaber's formula is given by



$sum_{k=1}^{n}{k^{p}} = frac{1}{p+1}sum_{i=1}^{p+1}{(-1)^{delta_ip}{p+1choose i}}B_{p+1-i}n^{i}$ where $delta_ip$ is the Kronecker delta function and $B_{p+1-i}$ is the $p+1-i$th Bernoulli number.



My question is, what do I use for $i$ in the Kronecker delta function when using this formula?



For example, I am trying to derive the partial sum of the power series $sum_{k=1}^{n}{k^2}$ but I don't see what I would use for $i$.










share|cite|improve this question
























  • You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
    – callculus
    2 days ago












  • Thank you @callculus. Yes, I will make that edit.
    – Gnumbertester
    2 days ago










  • $delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
    – Andy Walls
    2 days ago












  • @AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
    – Gnumbertester
    2 days ago








  • 1




    It is the index of the summation on the RHS, i.e. the index of each term in the summation.
    – Andy Walls
    2 days ago
















0












0








0


0





I am trying to use Faulhaber's formula to determine partial sums of a power series.



Faulhaber's formula is given by



$sum_{k=1}^{n}{k^{p}} = frac{1}{p+1}sum_{i=1}^{p+1}{(-1)^{delta_ip}{p+1choose i}}B_{p+1-i}n^{i}$ where $delta_ip$ is the Kronecker delta function and $B_{p+1-i}$ is the $p+1-i$th Bernoulli number.



My question is, what do I use for $i$ in the Kronecker delta function when using this formula?



For example, I am trying to derive the partial sum of the power series $sum_{k=1}^{n}{k^2}$ but I don't see what I would use for $i$.










share|cite|improve this question















I am trying to use Faulhaber's formula to determine partial sums of a power series.



Faulhaber's formula is given by



$sum_{k=1}^{n}{k^{p}} = frac{1}{p+1}sum_{i=1}^{p+1}{(-1)^{delta_ip}{p+1choose i}}B_{p+1-i}n^{i}$ where $delta_ip$ is the Kronecker delta function and $B_{p+1-i}$ is the $p+1-i$th Bernoulli number.



My question is, what do I use for $i$ in the Kronecker delta function when using this formula?



For example, I am trying to derive the partial sum of the power series $sum_{k=1}^{n}{k^2}$ but I don't see what I would use for $i$.







calculus sequences-and-series summation binomial-coefficients






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 days ago







Gnumbertester

















asked 2 days ago









GnumbertesterGnumbertester

1285




1285












  • You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
    – callculus
    2 days ago












  • Thank you @callculus. Yes, I will make that edit.
    – Gnumbertester
    2 days ago










  • $delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
    – Andy Walls
    2 days ago












  • @AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
    – Gnumbertester
    2 days ago








  • 1




    It is the index of the summation on the RHS, i.e. the index of each term in the summation.
    – Andy Walls
    2 days ago




















  • You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
    – callculus
    2 days ago












  • Thank you @callculus. Yes, I will make that edit.
    – Gnumbertester
    2 days ago










  • $delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
    – Andy Walls
    2 days ago












  • @AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
    – Gnumbertester
    2 days ago








  • 1




    It is the index of the summation on the RHS, i.e. the index of each term in the summation.
    – Andy Walls
    2 days ago


















You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
– callculus
2 days ago






You mean $sumlimits_{k=1}^n color{red}k^2=frac16cdot ncdot (n+1)cdot (2n+1)$?
– callculus
2 days ago














Thank you @callculus. Yes, I will make that edit.
– Gnumbertester
2 days ago




Thank you @callculus. Yes, I will make that edit.
– Gnumbertester
2 days ago












$delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
– Andy Walls
2 days ago






$delta_{ip} = 1 space mathrm{for} space i=p$ and 0 otherwise. So one term gets a multiplier of $-1$ while all the others just get a multiplier of $1$.
– Andy Walls
2 days ago














@AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
– Gnumbertester
2 days ago






@AndyWalls , yes, I understand how to evaluate $delta_{ip}$. I just don't understand what $i$ is in the context of Faulhaber's formula.
– Gnumbertester
2 days ago






1




1




It is the index of the summation on the RHS, i.e. the index of each term in the summation.
– Andy Walls
2 days ago






It is the index of the summation on the RHS, i.e. the index of each term in the summation.
– Andy Walls
2 days ago












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