Equality between two equations
at the moment I am reading the following paper
Benno, Steven A., and José MF Moura. "On translation invariant
subspaces and critically sampled wavelet transforms." Multidimensional
Systems and Signal Processing 8.1-2 (1997): 89-110.
The step between the equations (10) and (11) I can't comprehend. The step is as follows
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega)k}Big)domega =
$$
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k delta(f-omega+k)Big) domega.
$$
I know that $e^{-i2pi k}$ for $kinmathbb{Z}$ is an orthnormal basis, but not over $mathbb{R}$ and I have no idea, why $k$ comes into the dirac function with an "+". At most I woud expect something like $delta(f-omega)$ since it is in a product with k.
Has someone an idea about this?
Thanks Matthias
exponential-function dirac-delta
add a comment |
at the moment I am reading the following paper
Benno, Steven A., and José MF Moura. "On translation invariant
subspaces and critically sampled wavelet transforms." Multidimensional
Systems and Signal Processing 8.1-2 (1997): 89-110.
The step between the equations (10) and (11) I can't comprehend. The step is as follows
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega)k}Big)domega =
$$
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k delta(f-omega+k)Big) domega.
$$
I know that $e^{-i2pi k}$ for $kinmathbb{Z}$ is an orthnormal basis, but not over $mathbb{R}$ and I have no idea, why $k$ comes into the dirac function with an "+". At most I woud expect something like $delta(f-omega)$ since it is in a product with k.
Has someone an idea about this?
Thanks Matthias
exponential-function dirac-delta
1
good catch. interesting too.
– Nick
2 days ago
add a comment |
at the moment I am reading the following paper
Benno, Steven A., and José MF Moura. "On translation invariant
subspaces and critically sampled wavelet transforms." Multidimensional
Systems and Signal Processing 8.1-2 (1997): 89-110.
The step between the equations (10) and (11) I can't comprehend. The step is as follows
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega)k}Big)domega =
$$
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k delta(f-omega+k)Big) domega.
$$
I know that $e^{-i2pi k}$ for $kinmathbb{Z}$ is an orthnormal basis, but not over $mathbb{R}$ and I have no idea, why $k$ comes into the dirac function with an "+". At most I woud expect something like $delta(f-omega)$ since it is in a product with k.
Has someone an idea about this?
Thanks Matthias
exponential-function dirac-delta
at the moment I am reading the following paper
Benno, Steven A., and José MF Moura. "On translation invariant
subspaces and critically sampled wavelet transforms." Multidimensional
Systems and Signal Processing 8.1-2 (1997): 89-110.
The step between the equations (10) and (11) I can't comprehend. The step is as follows
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega)k}Big)domega =
$$
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k delta(f-omega+k)Big) domega.
$$
I know that $e^{-i2pi k}$ for $kinmathbb{Z}$ is an orthnormal basis, but not over $mathbb{R}$ and I have no idea, why $k$ comes into the dirac function with an "+". At most I woud expect something like $delta(f-omega)$ since it is in a product with k.
Has someone an idea about this?
Thanks Matthias
exponential-function dirac-delta
exponential-function dirac-delta
asked 2 days ago
Matthias LauberMatthias Lauber
283
283
1
good catch. interesting too.
– Nick
2 days ago
add a comment |
1
good catch. interesting too.
– Nick
2 days ago
1
1
good catch. interesting too.
– Nick
2 days ago
good catch. interesting too.
– Nick
2 days ago
add a comment |
1 Answer
1
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votes
Clearly there is a typo in equation (10), the correct expression is
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega+k)}Big)domega,
$$
which can be seen by substituting the definition of $a_k$ exactly as the authors describe.
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
add a comment |
Your Answer
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Clearly there is a typo in equation (10), the correct expression is
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega+k)}Big)domega,
$$
which can be seen by substituting the definition of $a_k$ exactly as the authors describe.
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
add a comment |
Clearly there is a typo in equation (10), the correct expression is
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega+k)}Big)domega,
$$
which can be seen by substituting the definition of $a_k$ exactly as the authors describe.
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
add a comment |
Clearly there is a typo in equation (10), the correct expression is
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega+k)}Big)domega,
$$
which can be seen by substituting the definition of $a_k$ exactly as the authors describe.
Clearly there is a typo in equation (10), the correct expression is
$$int_R G(omega) overline{tilde{G}(omega)} e^{-j2piomegatau} Big(sum_k e^{-j2pi(f-omega+k)}Big)domega,
$$
which can be seen by substituting the definition of $a_k$ exactly as the authors describe.
answered 2 days ago
pre-kidneypre-kidney
12.8k1748
12.8k1748
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
add a comment |
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
Hi, thank you for your answer. I checked equation (10) if $a_k$ is inserted. The sum is reordered by k and (10) should be correct.
– Matthias Lauber
yesterday
add a comment |
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good catch. interesting too.
– Nick
2 days ago